Density Part II Flashcards
Latent image
- occurs immediately after exposure, but before processing
- invisible
- this happens to all images, regardless of how it is acquired (film, digital DR, CR)
Image formation
- how do we get it? Result of differential absorption of the x-ray beam
- differential absorption is: process where some of the beam is ABSORBED and some is TRANSMITTED
- it is called differential absorption because the beam is not absorbed to the same degree over the entire area exposed
Differential absorption
- creates an image that represents the structures of anatomy (results from the variation between absorption and transmission
- when an image is created this way, several processes are required
- occurs in beam ATTENUATION
Beam attenuation
- when the primary x-ray beam passes through tissue and loses some of its energy (this reduction is known as attenuation)
- attenuation (loss of energy) consists of:
- absorption
- scattering
- photon transmission
Absorption
- interaction called photoelectric effect
- complete absorption of x-ray photon
- inner shell electron ejected (by x-ray photon)
- photoelectron
- outershell electron drops to fill the spot
- characteristic radiation emitted
- low energy (usually remains in the body)
- atom is ionized
Probability of PE interactions increases if:
- energy levels are CLOSER together
- binding energy of inner shell electron and energy of incoming x-ray photon
- the closer they are, the higher the odds of PE occurring
- complete absorption of the x-ray photon
- what other interactions are classified as absorption? Pair production and photo disintegration
Scattering
- what interaction would this be? Compton
- incoming x-ray photon is not absorbed
- ejects outer shell electron
- compton electron, secondary electron
- x-ray photon loses energy, changes direction
- can go onto interact with IR
- can leave body
Scattering cont
- what else would be in this category? Coherent
- not significant
- occurs with very low energy x-rays
- can interact with IR but very minimally
- In diagnostic ranges, very little contribution from coherent scatter
Scattered photons
Why are they an issue?
-if they reach the IR they degrade image, contribute nothing useful to the image, AKA image fog
KVp and image fog
- when kVp is increased there are: fewer interactions in total, increased amount of x-rays transmitted, increased compton scattering
- scattered radiation creates unwanted exposure on the image called image fog
- does not offer any useful information
Scatter and image fog
- when kVp is INCREASED the amount of fog is INCREASED
- how is density affected? Increased fog will increase overall image density
- how is contrast affected? Increased fog leads to a decrease in contrast
Transmission
- defined as: the x-ray photon passes through to the image receptor
- direct transmission
- indirect transmission
Interactions and kVp
⬆️ kVp ⬇️interactions
Exit radiation
= transmitted and scattered radiation
=(direct and indirect transmission)
-amount of absorption and transmission are varied (differential absorption)
On the image
- WHITE (low radiographic density, areas of absorption, photoelectric interactions)
- BLACK (transmission, high radiographic density)
- GREY (mix of both absorption and transmission)
All about compromise
⬆️ kVp ⬇️ patient dose
Exponential absorption
- as x-rays pass through tissue, there is no fixed range to describe how far they go
- attenuated exponentially
- for every increment of thickness, the x-rays are decreased in #, by a certain percentage
- never reaches 0
Distance and density
SID
- source to image distance aka FFD (focus to film distance)
- intensity changes with distance
- inverse square law
SID
- as the distance between the focal spot and the IR changes, the intensity of the radiation will change also
- you’ll notice as the distance is increased, the light covers a larger area
- what happens to the # of photons as the area is increased? Same # of photons covering a larger area, so less density
SID cont
- What happens to the image as the area is increased? Because it is receiving less radiation, there will be less radiographic density
- what if we have a very short SID? The reverse is true, more photons in a smaller area -> increased intensity, more radiographic density
Density maintenance formula
- derived from the inverse square law
- when do we use it? Portables (especially chests), to fit larger parts to a receptor, patient condition
OID
- object to image distance
- increased OID allows less scatter to reach the IR (coming off in all directions and may just miss the IR)
- how would less scatter affect radiographic density? It would decrease it
- increased OID, results in decreased radiographic density
Body habitus
- sthenic (average, muscular)
- hyposthenic (thin, slim, healthy)
- hypersthenic (large)
- aesthenic (small and frail)
Thickness
- calipers
- with increased thickness, how would we adjust our exposure factors? MUST INCREASE EXPOSURE FACTORS
- can change mAs or kVp
- in most situations would choose to adjust mAs