DAT BOOTCAMP QUESTIONS Flashcards

1
Q

Effects of positron emission, electron capture, alpha decay, and beta decay

A

Positron emission (β+ decay) = Proton -> Neutron

Electron capture = Proton + Electron -> Neutron

Alpha Decay (α-decay) = Emits a Helium atom. Reduces mass number.

Beta Decay (β– decay) = Neutron -> Proton + Electron emitted

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2
Q

Describe why the answer for this question is positive (C).

The ∆Hf for Br(g) is +193 kJ/mol. What is the bond dissociation energy of a Br-Br bond?
  A. +193 kJ / mol
  B. -193 kJ / mol
  C. +386 kJ / mol
  D. -386 kJ / mol
  E. +96.5 kJ / mol
A

Bond dissociation energies are always positive because we have to put in energy to break the bond.

In other words, the bond has to absorb energy, meaning bond breaking is an endothermic process

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3
Q

Element X has a nucleus that is stable against decomposition. Which of the following must be true of Element X?

A. the effective nuclear charge is high
B. the nuclear binding energy is high
C. the ionization energy is high
D. the electron shielding effect is high
E. the bond dissociation energy is high

A

B

Binding energy is the energy needed to split the nucleus into the individual components, i.e. protons and neutrons (or nucleons). The higher the binding energy, the harder it is to decompose the nucleus.

The effective nuclear charge is the net positive charge experienced by an electron in a multi-electron atom. It explains the atomic radii trend across periods.

The electron shielding effect dictates the atomic radii trend down a group.

Bond dissociation energy deals with compounds, not nuclei.

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4
Q

Which of the following is true for the energy diagram of a reversible exothermic reaction?

A. The forward reaction proceeds slower than the reverse reaction.
B. The enthalpy of the products is greater than the enthalpy of the reactants.
C. The reverse reaction has a higher activation energy than the forward reaction.
D. The reverse reaction has a lower activation energy than the forward reaction.
E. The forward reaction has a higher activation energy than the reverse reaction.

A

C

know what exo vs endothermic reaction diagrams look like

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5
Q

Explain why HI is a stronger acid than HBr.

The strength of an acid is usually determined by how much the acid _____.

Thus, the ____ the bond holding the proton to the molecule, the ____ the acid is.

A

disassociates, weaker, stronger

The bond strength is largely determined by the difference in electronegativity.

Fluorine is one of the most electronegative elements, and thus is not as strong of an acid as HCl or HI, which have weaker bonds, and thus a more readily available proton.

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6
Q

If given the Kc of the forward reaction, how would you find the Kc of the reverse?

A

reverse is the reciprocal!

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7
Q

Raoult’s Law

A

PA = XaPpure

Ppure = vapor pressure of given compound

Xa = percentage of solvent in the solution

use this formula to find a new vapor pressure

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8
Q

Haber Process

A

Nitrogen and hydrogen react to form ammonia

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9
Q

What is the maximum number of electrons that can be held in the 4th energy level?

  A. 2
  B. 8
  C. 10
  D. 14
  E. 32
A

E

The fourth energy level has four orbitals, s, p, d, and f.

S = 2 electrons
p = 6 electrons
d orbitals = 10 electrons
f orbitals = 14 electrons

Therefore the 4th energy level can hold at most 2 + 6 + 10 + 14 = 32 electrons. Notice that the first energy level can only hold 2 electrons. This is why helium is considered a noble gas even though it only has 2 electrons; it has a full energy level already!

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10
Q

The addition of a strong acid to a saturated solution of Mg(OH)2 that has 100g of solid remaining would cause which of the following?

a) increase pH
b) increase number of Mg ions in solution
c) increase number of OH ions in solution

A

B

The correct answer is [D]. Notice that Mg(OH)2 is technically insoluble, however, this does not mean that none of the reactant will dissolve. A very small portion of the Mg(OH)2 still dissolves according to the following reaction:

Mg(OH)2 ⇌ Mg2+ + 2OH–

The solution is saturated, meaning all the Mg(OH)2 that can dissolve has dissolved, and there are still 100g of it left as a solid. If we add a strong acid, or essentially H+, it will combine with the OH– to form H2O. Since some of the OH– has been removed, then according to Le Chatelier’s principle, the reaction will shift to the right to restore equilibrium. As a result, more Mg(OH)2 will be dissolved, and more Mg2+ will be released, or answer choice [D].

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11
Q

Given an elementary reaction, how would you find the:

  • intermediate
  • rate law
  • overall reaction
A
  • the intermediate will be made in the middle of the reaction and get used up before the end
  • to find the rate law, it’s simply the reactants of the SLOW STEP
  • overall will be adding up elementary steps and cancelling the intermediates out
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12
Q

An exothermic reaction at equilibrium will proceed at a:

A. slower rate while its Kc increases at higher temperatures.
B. slower rate while its Kc decreases at higher temperatures.
C. faster rate while its Kc increases at higher temperatures.
D. faster rate while its Kc decreases at higher temperatures.

A

D

*think of this one mathematically

From Le Chatlier’s principle, increasing the temperature would increase the heat, so therefore the reaction would shift to the left (towards the reactants, [A] and [B]).

If the concentrations of [A] and [B] increase, then the overall Kc of the reaction would decrease at higher temperatures, eliminating answer choices A and C.

Lastly, increasing the temperature will increase the rates of both the forward and the reverse reactions, so the reaction will proceed at a faster rate. Thus we arrive at answer choice D.

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13
Q

Metal oxides produce ___ solutions in water.

Non-metal oxides produce ___ solutions in water.

A

basic, acidic

give examples of both!

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14
Q

A solid compound that has a vapor pressure higher than atmospheric pressure will most likely be able to do which of the following?

  A. melt
  B. freeze
  C. condense
  D. vaporize
  E. sublime
A

E

If a solid compound has a high internal vapor pressure relative to the external environment, the compound will be able to sublime as the particles will be able to readily turn into vapor without first transitioning into the liquid state. This is seen with dry ice, as the dry ice has a higher vapor pressure than the atmosphere, thus as the dry ice “evaporates” the solid particles are said to sublime.

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15
Q

If the conjugate base of a molecule has a pKb of 1.4, what would you expect the molecule to be?

a) strong acid
b) weak acid
C) neutral
D) weak base
E) strong base

A

B

  1. Strong acids have a weak conjugate base.
  2. Strong bases have a weak conjugate acid.

So if the problem says you have a strong conjugate base, then the molecule must be a weak acid. To illustrate this, think of ammonium, NH4+. Ammonium is a weak acid, but the conjugate base of ammonium is ammonia, NH3, which is a reasonably good base. Thus, the correct answer is [B].

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16
Q

Electron affinity measures the:

A. tendency to attract electrons towards the atom and form a bond.

B. chemical reactivity of the valence electrons of the atom.

C. amount of energy absorbed when an electron is added to an atom.

D. ease with which an atom gains an electron.

E. average distance between the electrons and nucleus.

A

D

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17
Q

Normal Boiling Point

A

The temperature at which the vapor pressure of the liquid equals one atmosphere of pressure.

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18
Q

Water molecules in an aqueous solution will have the strongest interactions with ions with which of the following characteristics?

A. Small charge and small size
B. Small charge and large size
C. Large charge and small size
D. Large charge and large size

A

C

Let’s first examine charge. A polar water molecule will be more likely to interact with an ion with more charge. This is a stretch of the analogy “like dissolves like”. The high polarity molecule will enjoy the company of a highly charged ion, and this will result in a greater interaction between the two.

For size, think about the charged ion and water molecule as two tiny magnets. When these magnets are spaced far apart, they barely have an effect on each other. As you bring the magnets closer together, you begin to feel their force of interaction. The same principle applies to a water molecule and a charged ion in an aqueous solution. We need to minimize the distance between the water molecule and charged ion, and we can do that by choosing an ion with a smaller size.

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19
Q

A student finds that the average number of cells over 10 samples is 2130, with a standard deviation of ±6. However, the professor determines the true average number of cells is 2850. The student’s measurement was:

A. inaccurate and precise
B. accurate and imprecise
C. inaccurate and imprecise
D. accurate and precise

A

The definition of accuracy is that the measurement taken is close to the true value, whereas the definition of precise is that the measurement produces consistent results.

Thus, the student’s measurements were precise, since we can see the standard deviation is LOW compared to the total number of cells, meaning the variation of each measurement was low.

However, the measurement was inaccurate, because the measured value by the student differed significantly from the true value.

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20
Q

What is the molar solubility of BaF2 (Ksp = 1.8×10-7) in 0.10 M sodium fluoride?

  A. 1.8×10-5 M
  B. 1.8×10-7 M
  C. 1.8×10-9 M
  D. (1.8×10-7)1/2 M
  E. (1.8×10-7)2 M
A

A

BaF2(s) Ba2+(aq) + 2F–(aq)

Ksp = [Ba2+][F–]2

We can solve this via an ICE table, which is the longer way, or we can skip to the end and just use the Ksp equation above to solve the question. Speed is important on the DAT, so we’re going to solve this the fast way.

Let x = molar solubility of BaF2

We have 1 ion of Ba2+ and 2 ions of F–. We’re going to assume that the molar solubility of BaF2 is very small (common on the DAT since we don’t have a calculator) and that it probably won’t impact the concentration of fluoride that much. Therefore:

Ksp = [Ba2+][F–]2

Ksp = 1.8×10-7 = (x)(0.10)2

Solve for x, the molar solubility

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21
Q

A researcher has a solution of 3M nitric acid that she needs to neutralize. In order to do this, she decides to add the acid to a solution to neutralize it. Which of the following would neutralize the acid the fastest?

  A.	Br-
  B.	Na3PO4
  C.	NH3
  D.	Cl-
  E.	H2O
A

B

In order to neutralize the acid the fastest, we want the base that is capable of absorbing the most protons per molecule.

Na3PO4 is able to absorb 3 protons, because it dissociates into the very basic PO43- ion. Thus, adding trisodium phosphate would neutralize the acid the fastest, versus the other answer choices that would only absorb 1 proton.

Strategy tip: We could eliminate Br– and Cl– immediately because they’re both almost identical (weak base, halide). Given that there cannot be two correct answers, both of them must be wrong.

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22
Q

Neutralization reactions tend to be

a) exothermic
b) endothermic
c) neutral
d) cannot be determined

A

A

23
Q

T/F? - In regards to electrolytic and galvanic cells, currents are driven by the electrostatic attraction of electrons

A

FALSE - they are not driven by this

24
Q

If the Ka of acetic acid is 1.8 × 10-5, what is the pKb of acetate?

  A. 14 – log (1.8 × 10-5)
  B. 14 + log (1.8 × 10-5)
  C. – log (1.8 × 10-5)
  D. –14 + log (1.8 × 10-5)
  E. –14 – log (1.8 × 10-5)
A

B

The “p” in pKa and pH stands for “–log”. Here are some useful equations to know for this problem.

(Ka)(Kb) = Kw = 10-14

pKa + pKb = 14

pKb = 14 – pKa

pKb = 14 – (–log(Ka))

pKb = 14 – (–log(1.8 × 10-5))

The two negatives cancel to form our final equation.

pKb = 14 + log (1.8 × 10-5)

25
Q

What is the OH–(aq) concentration in 9.0 M CH3NH2? The Kb for CH3NH2 is 4 × 10-4.

  A. 3 × 10-4
  B. 3 × 10-2
  C. 6 × 10-2
  D. 6 × 10-3
  E. 6 × 10-4
A

The go-to formula for dealing with weak bases with Kb values and [OH–] is very similar to the formula we use for weak acids.

Formula for weak acids: sqrt (Ka)(M)

Formula for weak bases: sqrt (Kb)(M)

26
Q

Differentiate between electron affinity, electronegativity, and ionization energy

A

Electron affinity - the ease with which a neutral atom gains an electron

Electronegativity - tendency to attract electrons towards the atom and form bonds; this value is estimated based on ionization energies and electron affinities.

Ionization energy - The amount of energy it takes to remove an electron from an atom

27
Q

What are some general characteristics of alkali metals?

A

very reactive with H2O, low ionization energies, low melting points due to weak inter-atomic bonding

28
Q

Which is the best definition of a boiling point?

A. The temperature at which the vapor pressure of the liquid equals one atmosphere of pressure.

B. The temperature at which the liquid vaporizes.

C. The temperature at which the surrounding pressure becomes greater than the vapor pressure of the liquid.

D. The temperature at which the vapor pressure of the liquid equals the surrounding pressure.

E. The pressure at which a liquid can no longer vaporize.

A

D

29
Q

Which of the following is a characteristic of network covalent solids?

  A. malleability
  B. conductivity
  C. high melting point
  D. high luster
  E. frail
A

C

Think “hard as a diamond!” Diamonds have to be ground down to become shiny and lustrous. Metals are naturally lustrous!

30
Q

Consider the below chemical equilibrium in a closed vessel at a constant temperature. The easiest method to measure the equilibrium constant for this system is to measure:

Na2CO3(s) < –> CO2(g) + Na2O(s)

a) temperature of the reaction
b) [CO2]
c) molar concentrations of the reactants
d) forward and reverse rates

A

B

The correct answer is B. Equilibrium constants do not include solids or liquids, such as Na2CO3 and Na2O.

So the equilibrium constant equation here would be
Kp = [CO2]. The pressure of the CO2 gas is the only determinant in the equilibrium constant.

31
Q

What volume of 0.5M H2SO4 is needed to neutralize 250mL of 0.5M KOH?

A

Don’t get tricked by this! use the number of H’s

H2SO4 has two moles of H+ ions (n1=2), while OH only has one mole of OH–(n1=1). Therefore, we must remember to use the normality of the acid in this dilution reaction.

(n1) (M1)(V1) = (n2)(M2)(V2)
(2) (0.5)(V1) = (1)(0.5)(250)

V1 = 125 mL

32
Q

Henry’s Law

A

Pa = kh [A]

Pa = pressure
[A] = concentration of gas molecules

proportional!

33
Q

___ numbers in pKb correlate with stronger bases, and ____ numbers in pKb correlate with stronger acids

A

lower, higher

34
Q

Which statement best explains why bromine is a liquid and iodine is a solid at STP?

A. At a given temperature, bromine has a higher vapor pressure than iodine.

B. Smaller atoms tend to be more polarizable and exhibit greater intermolecular forces.

C. The dipole-dipole interactions in iodine are stronger than in bromine.

D. Elements in the same column tend to have different chemical properties.

E. London dispersion forces increase as molar mass increases.

A

E. - London dispersion intermolecular forces increase as molar mass increases.

This is the most accurate statement. As molecules get heavier, they exhibit a greater amount of London dispersion forces (nonpolar forces), and these forces become so powerful that iodine actually turns into a solid.

35
Q

What is the pH of a solution prepared by adding 20 mL of 0.02 M NaOH(aq) to 20 mL of water?

  A. 2
  B. 3
  C. 10
  D. 11
  E. 12
A

NaOH is a strong base and fully dissociates into Na+ and OH–. To find the new concentration of NaOH after we dilute it with water, we use:

M1V1 = M2V2

(0. 02)(0.02) = M2(0.04)
0. 01 = M2

Notice that we use 0.04 L for the second volume, NOT 0.02 L. This is because we are adding 0.02 L of NaOH(aq) to 0.02 L of water for a total of 0.04 L.

Next, since NaOH is a strong base, we can conclude [OH–] = 0.01 M.

pOH = -log([OH–])
pOH = -log(0.01)
pOH = 2

pH + pOH = 14
pH = 14 – pOH
pH = 14 – 2 = 12

36
Q

Decantation

A

Decantation is the process to remove the top layer of liquid after the precipitate has settled at the bottom.

37
Q

All of the following will affect the rate of an irreversible chemical reaction EXCEPT one. Which one is this EXCEPTION?

  A. pressure.
  B. concentration of reactants.
  C. presence of a catalyst.
  D. surface area of reactant solid.
  E. concentration of products.
A

E

More surface area of a reactant will give more opportunities for molecules to strike to cause a reaction. However, the concentration of products will not affect the rate of an irreversible reaction. Product molecules colliding into each other will not help the forward reaction to occur quicker.

38
Q

All of the following are assumptions of an ideal gas EXCEPT one. Which one is the EXCEPTION?

A. All gas molecules are in constant, rapid, and random motion.

B. There are no attractive or repulsive forces between the gases.

C. The average kinetic energy is proportional to the number of gas molecules.

D. The volume of the molecules is negligibly small compared to the volume of the gas.

E. All collisions within the gas are perfectly elastic.

A

Here is the entire list of assumptions for ideal gases:

The volume of the gas molecules is negligibly small compared to the volume of the entire gas.
Gas molecules are in constant, random motion.
Gas molecules collisions are perfectly elastic.
There are no intermolecular forces occurring between gas molecules. Hence, they are assumed to be nonpolar (i.e. no attraction/repulsion between molecules).
The average kinetic energy of the gas molecules depends only on the temperature of the system (not the number of gas molecules!).

39
Q

The ΔH for which of the following reactions is the standard enthalpy of formation (ΔH°f) for sodium chloride?

  A. Na+ (aq) + Cl- (aq) --> NaCl (aq)
  B. Na (s) + 1/2 Cl2 (g) --> NaCl (s)
  C. Na (g) + 1/2 Cl2 (g) --> NaCl (g)
  D. 2Na (s) + Cl2 (g) --> 2NaCl (s)
  E. 2 Na (g) + Cl2 (g) --> 2NaCl (s)
A

B

The ΔH°f for a compound is the enthalpy change for the formation of one mole of the compound from reactants in their most stable forms at standard conditions (298K and 1 atm). Sodium is solid and chlorine is a gas at standard conditions. To form one mole of the compound we must use 1 mole of Na (s) and 1/2 a mole of Cl2 (g).

40
Q

How many electrons are transferred in this half-reaction?

Mn2+ → MnO4-

A

5

assign oxidation numbers - Mn2+ to Mn+7 = 5

41
Q

Hydrogen gas and nitrogen gas react to produce ammonia. How many liters of ammonia can be produced from 2 liters of hydrogen gas and 2 liters of nitrogen gas at STP?

  A. 1.3
  B. 2.6
  C. 2.0
  D. 4.0
  E. 6.0
A

he described reaction is the Haber process:

N2 + 3 H2 → 2 NH3

This is a limiting reagent problem. We have to find out which reactant is going to run out first and limit our ability to produce ammonia gas.

We can treat the liters of gas the same as mols in this case. This is because at a constant temperature and pressure, the volume of the gas is directly proportional to the number of mols.

So hydrogen gas is our limiting reagent in this case. Only 1.33 mols of ammonia can be produced before we run out of hydrogen gas and the reaction stops.

42
Q

Label a phase change diagram

A

label

inclines = phase
plateau = phase change
43
Q

Dilution equation

A

M1V1 = M2V2

where M = molarity, V = volume

44
Q

How much water should be added to 10 mL of 3.00 M HCl(aq) in order to dilute it to a 2.00 M solution of HCl(aq)?

  A. 5 mL
  B. 10 mL
  C. 15 mL
  D. 30 mL
  E. 50 mL
A

We can use the equation M1V1 = M2V2 to solve this problem. We are given the following values:

M1 = 3.00 M HCl(aq)
V1 = 10 mL
M2 = 2.00 M HCl(aq)

We’ll use the above equation to solve for V2:

(3.00)(10) = (2.00)(V2)
V2 = 15 mL

The question asks how much water should be ADDED to the original solution, so we subtract by the original amount, V1.

15 – 10 = 5 mL, or answer choice [A].

45
Q

A sample of hydrated magnesium sulfate, MgSO4 • xH2O, weighs 21.0 g. It is placed inside of an oven until all of the water is vaporized, the anhydrous form weighs 12.0 g. What is the value of x in the hydrated salt? MgSO4 = 120 g•mol-1.

  A. 3
  B. 4
  C. 5
  D. 6
  E. 7
A

Hydrated salt problems can be tricky. Just remember this formula to find the value “x”:

mol H2O/mol MgSO4 = x

To find the mol of H2O, we subtract the original weight of the hydrated salt (the salt + water) by the weight of the anhydrous salt (only salt, no water).

21.0 – 12.0 = 9 grams of water.

9g / 18 (g•mol-1) = 0.5 mol of water
*The molar mass of water is 18 g•mol-1.

To find the mol of MgSO4, we use the anhydrous salt (only salt, no water).

12 / 120 = 0.10 mol of MgSO4

Finally, we plug back into the original equation to find:

0.5 / 0.1 = 5

So the formula of the hydrated salt is: MgSO4 • 5 H2O

46
Q

Percent Change Formula

A

(new - original)/ original * 100

47
Q

Name common examples for the following molecular geometries - how many bonding and nonbonding electrons does each have?

Seesaw 
Trigonal pyramidal 
Bent
Square Planar 
Square pyramidal
A
SF4 - 4, 1 
BrF3 or NH3 - 3, 1
H2O - 2, 2
XeF4 - 4, 2
BrF5 - 5, 1
48
Q

Hydrogen peroxide (H2O2, 34 g/mol) decomposes into water vapor and oxygen gas. How many liters of water vapor are produced from the decomposition of 17.0 g of H2O2 at STP?

  A. 2.80
  B. 5.60
  C. 11.2
  D. 22.4
  E. 44.8
A

C

Remember this trick for the DAT. One mole of a gas is equal to 22.4L at STP. If we have half a mole, then we will have 11.2L of gas at STP. Therefore, the amount of water we have in liters at the end of this reaction is 11.2L.

49
Q

What is responsible for the decrease, and increase in atomic size, respectively?

A

The increasing effective nuclear charge is responsible for the decrease in atomic size across the periodic table from left to right.

The increasing electron shielding effect is responsible for the increase in atomic size moving down groups.

50
Q

Mass Percent Formula

A

grams solute / grams solution

51
Q

Describe whether N2 and O2 are diamagnetic or paramagnetic.

A

N2 is diamagnetic and O2 is paramagnetic

Paramagnetic compounds = attracted to magnetic fields, unpaired

diamagnetic compounds = repelled from magnetic fields, paired spins

52
Q

What is the pH of a solution comprised of 1.0 M HF (pKA = 3.2) and 0.1 M NaF?

What is the pH of a solution comprised of 0.1 M HF (pKA = 3.2) and 10 M NaF?

A

Use HH equation!

  1. 2
  2. 2
53
Q
Which of the following acts as a reducing agent?
  A. Cl-
  B. IO3-
  C. F2
  D. Zn2+
  E. Cl2
A

A

In this case, the reducing agent we’re looking for must have an element that will likely give up electrons (or become oxidized).

Cl– is a great candidate to act as a reducing agent since it will change oxidation states from -1 to 0.