Chapter 12 Flashcards

1
Q

Oxygen’s oxidation state is usually -2, except in hydrogen peroxide, in which it will equal ______.

A

-1

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2
Q

Hydrogen’s oxidation state is usually +1, except when bonded to a metal, in which it will equal _____

A

-1

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3
Q

What are the oxidation states of Al, Zn, Cd, and Ag?

A

Al = +3

Zn = +2

Cd = +2

Ag = +1

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4
Q

In a voltaic cell, what is the purpose of the salt bridge?

A

serves to counter balance charges and as a source of unreactive cations

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5
Q

In a galvanic cell, electrons will flow from ____ to _____ because the anode will always have a ____ energy than the cathode.

A

high, low, higher

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6
Q

When the ∆G < 0 (negative), the Ecell is _____

When ∆G > 0 (positive), the Ecell is ______

A

positive

negative

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7
Q

Electrolytic Cells

A

the opposite of galvanic; require an external power source to push electrons uphill and thus will have a non spontaneous ∆G (positive) and thus a negative Ecell

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8
Q

T/F? Anode is the site of oxidation and the cathode is the site of reduction, regardless of the type of cell.

A

TRUE

flow of electrons is the same, spontaneity changes

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9
Q

Molten electrolysis lacks a ____ _____; thus it requires an ____ ____ ___ to push the electrons towards the cathode.

A

salt bride, external power source

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10
Q

If a reduction potential is more negative, this indicates that it is a ______ _____. If a reduction potential is more positive, this indicates that it is a _____ _____.

A

more negative = strong oxidant

more positive = strong reductant

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11
Q

Nernst Equation

A

Ecell = 0.592/n x log (Q)

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12
Q

Which of the following reduction reactions involve the greatest number of electrons per mol of oxidant?

  A. CO2 → C2O42-
  B. Cr2O72- → Cr3+
  C. NO3– → NO
  D. N2 → N2H5+
  E. Al3+ → Al
A

B

assign oxidation numbers!

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13
Q

In which of the following compounds does nitrogen have the most positive oxidation state?

  A. NH3
  B. N2O4
  C. NO3
  D. N2H5+
  E. N2
A

C

practice this one out/write it out

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14
Q

Given the following standard reduction potentials, which of the following statements is correct?

Ni2+ + 2 e– → Ni, –0.25 V
Cu+ + e– → Cu, +0.521 V
Co3+ + 3 e– → Co, +1.83 V

A. When Co3+/Co and Ni2+/Ni are used in a voltaic cell, Ni2+/Ni is the cathode.

B. Co3+/Co can reduce Ni2+/Ni

C. Cu+/Cu is a stronger oxidizing agent than Co3+/Co.

D. Ni2+/Ni is a stronger reducing agent that Cu+/Cu.

E. Ni2+/Ni can oxidize Cu+/Cu.

A

D

The higher the potential, the greater the tendency for reduction to occur, and therefore, the stronger the oxidizing agent is (or weaker the reducing agent). Thus, C is incorrect since cobalt has a more positive reduction potential, is more likely to be reduced, and cobalt a stronger oxidizing agent than copper.

A substance with a more positive reduction potential can oxidize those that have a less positive reduction potential. With cobalt and nickel, cobalt is more likely to be reduced and therefore will oxidize nickel. Therefore, B is incorrect. With nickel and copper, nickel is more likely to be oxidized and therefore would reduce copper. Thus, E is incorrect.

D is correct since nickel has a less positive reduction potential, is more likely to be oxidized, and therefore is a stronger reducing agent, than copper.

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15
Q

Given the following standard electron potentials, which metal cation can oxidize Ni but not Ag?

Au3+ + 3e– → Au, +1.50 V 
Ag+ + e– → Ag, +0.80 V 
Cu2+ + 2e– → Cu, +0.34 V 
Ni2+ + 2e– → Ni, –0.25 V 
Fe2+ + 2e– → Fe, –0.44 V
A Au3+
  B. Fe2+
  C. Cu2+
  D. Fe2+ and Cu2+
  E. Au3+ and Cu2+
A

C - Cu

Substances that have a more positive electrode potential can oxidize those that have a less positive electrode potential.

Au3+ can oxidize both Ni And Ag, Fe2+ can oxidize neither Ni nor Ag, and Cu2+ can oxidize Ni but not Ag.

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16
Q

Describe the relationship between electrode potential and reducing agent.

A

the smaller the electrode potential, the stronger the reducing agent is

17
Q

A voltaic cell was constructed using the following half-reactions (written as reduction half-reactions). What is the overall reaction and the standard cell potential of this voltaic cell?

Cd2+ + 2 e– → Cd, –0.40 V
Pb2+ + 2 e– → Pb, –0.13 V

A. Cd2+ + Pb → Cd + Pb2+, Ecell = +0.27 V
B. Cd2+ + Pb → Cd + Pb2+, Ecell = –0.27 V
C. Pb2+ + Cd → Pb + Cd2+, Ecell = +0.27 V
D. Pb2+ + Cd → Pb + Cd2+, Ecell = –0.27 V
E. Pb2+ + Cd → Pb + Cd2+,Ecell = –0.54 V

A

C

In order for Ecell to be positive, the half-reaction with a more positive potential must be the cathode (the site of reduction).

Thus, Pb2+/Pb must be the cathode (reduction) and Cd2+/Cd must be the anode (oxidation). So we flip the Cd half-reaction (and flip the sign of the Cd half reaction so we have our oxidation potential) and add the two equations to get the overall reaction: