Communication, Electrical Signalling, Channels and Transporters Flashcards
Direct Signalling
- gap junctions between cells found joining nearly all cells in solid tissues
- -connexon in each cell membrane join together to form channel between the two cells
-cell-cell recognition, receptors on one cell surface bind to specific ligands on nearby cell initiating a cascade of events
Non-Direct Signalling
- panacrine signalling - molecules released by endocyotsis and transmitted to other cell by diffusion through extracellular fluid
- synaptic signalling - neurotransmitter released and diffuses across synapse
- long distance (hormonal) signalling - molecule released into blood stream, communication molecule transported in blood to other cells
Stages of Cell Signalling
- transmitting cell releases primary messenger molecules
- received by cell membrane receptors triggering transduction
- inside the cell, secondary messenger molecules which trigger cellular responses / change in gene expression
Quoram Sensing
- regulation of gene expression in response to changes in cell population density
- cells release a sepcific signalling molecule constantly ase well as detecting it
- so signalling molecules increase in concentration as a function of cell population density
- receptors that recognise the molecules respond when a threshold concentration is reached
- at low cell density cells exhibit individual behaviours
- above the threshold cell density quoram sensing genes are activated enabling group behaviours
Molecular Communication Timescales
- it takes ~50s for a drop of blood to circulate the body
- it takes ~7hrs for ions to diffuse the length of an axon by random diffusion
- it takes ~4hrs for a molecular motor to walk the axon length
- these are all very slow compared to the sub-second reactions observed
Electrical Signalling (Neurons)
- ions move across the membrane generating a current
- this changes the potential across the membrane
- if conditions are right charge flows and the potential change propagates down the axon in ms
- diffusion wants to make uniform the concetration of ions across the membrane by diffusion but a electric potential could prevent this
Nernst Relation
General Case
-consider charge distribution in the presence of a battery
-what will be the voltage for a given charge distribution:
ln[ c(L) / c(0)] = - qΔV/kbT
Nernst Relation
Membranes
ΔV = - kbT/q ln[cin/cout]
-for postive ions, for negative ions: cout/cin
Establishing Existence of Membrane Potential Experiment
- electrodes inserted into giant squid axons to measure potential across membrane
- found that positive ions were mobile across the membrane whilst negative ions tended not to be
What happens when you have a population of mobile and immobile ions?
- the mobile positive ions would like to diffuse away from the cell to make the inside and outside concentrations the same
- but doing this pulls them away from negative ions therefore costing electrostatic energy
- as a result an equilibrium is set up
Setting the Membrane Potential
- if some positive ions flow out:
- -the negative charges inside are attracted to the inner membrane due to the cloud of positive charges outside that have just flowed out
- like parallel plate capacitor with +/- q on the surface
- this sets up the voltage difference across membrane, V given by Nernst
Donnan Equilibrium
-cells have >2 species of ion and charged proteins (usually negative)
-how do all of these come to equilibrium?
-at equilibrium, by charge neutrality:
cin,tot = cout,tot = 0
-and from the Nernst relation:
ΔV = -kbT/q ln[c1+in/c1+out] = -kbT/q ln[c2+in/c2+out]
= -kbT/q ln[c3-out/c3-in]
-e.g. for three types of ion, 1 & 2 positive and 3 negative
-at equilibrium, these values can be maintained by the cell without using any energy
Osmotic Pressure Due to Charge Imbalance
-at Donnan equilibrium there can be a significant concentration difference causing osmotic pressure
Δp = Δc kb T
-where Δc = cin,tot - cout,tot
-to resolve this the cell pumps (mainly Na+) ions out of the cell
Sodium Anomaly Experiment
- equilibirum predicts ΔV<0 but sodium is way off, (positive)
- this Na+ being way out of equilibrium is refered to as the ‘sodium anomaly’
- the large Na+ difference between in a out balances the osmotic pressure so the cell is not in equilibrium
- it burns energy to pump Na+ out of the cell to balance osmotic pressure
Ionic Current
-can describr flow of ions using Ohm’s Law:
I = V/R OR I=gV
-where g is conductance
-for ion species, i, the current flux is given by:
Ji = Ii/A = gi [ΔV - Vi,nernst]