Circles Flashcards

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0
Q

What is a Circumference?

A

The edge of a circle

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1
Q

What is a Radius?

A

A line from the center of a circle to its edge

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2
Q

What is a Diameter?

A

A line splitting the circle through its center

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3
Q

What is a Tangent?

A

A line that touches the edge of a circle but doesn’t enter it

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4
Q

What is a Points of Tangency?

A

The point where a radius touches a tangent. This always creates right angles

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5
Q

What is a Secant?

A

A line that cuts through a circle (touching it in two places)

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6
Q

What is a Chord?

A

A line that starts and ends at the edge of a circle. The longest chord will be the diameter

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7
Q

What is a Sector?

A

Pie shaped pieces of a circle

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8
Q

What is a Minor Arc?

A

Less than half a circle

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9
Q

What is a Major Arc?

A

More than half a circle

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10
Q

What is a Semicircle?

A

Half a circle

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11
Q

What is the area of a circle?

A

πr²

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12
Q

How do you find the circumference of a circle?

A

2πr

πd

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13
Q

How do you find the area of a sector?

A

θ
—— (πr²)
360º

θ = Inner Angle

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14
Q

How do you find the arc length of a sector?

A

θ
—— (2πr)
360º

θ = Inner Angle

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15
Q

How do you find the perimeter of a sector?

A

AL + 2r

AL = Arc Length

16
Q

If the area of ΔAOB is 25, what is the area of circle O?

A

ΔAOB: ½(r)(r) or ½r². So 50 = r²

O: 50π.

(Area of a circle = πr²)

17
Q

If the OA = 8, what is the area of the shaded region BAYB?

A

ΔAOB: ½(8)(8) = ½(64) = 32

O: π(8²) = 64π

Sector BYAOB: ¼(64π) = 16π

Shaded Region: 16π - 32 = 16(π - 2)

18
Q

If CD = 10, what is the perimeter of sector DOCXD?

A

ΔDOC is equilateral. All sides will equal 10.

Arc Length DXC: 36/360(2π)(10) = 1/6(20π) = 1/3(10π) =
= 10π/3

Perimeter: 10π/3 + 2(10) = 10π/3 + 20

19
Q

If OC = 2, what is the area of the shaded portion DCXD?

A

ΔCOD: 2²√3/4 = 4√3/4 = √3

Sector DCXD: 60/360(π)(2²) = 1/6(4π) = 1/3(2π) = 2π/3

Shaded Area: 2π/3 - √3 or…..

2π/ - 3√3
————-
3

20
Q

If the area of ΔCOD is 25√3, what is the perimeter of semicircle EOBDXCE?

A

25√3 = x²√3/4 || 100√3 = x²√3 || 100 = x² || 10 = x

Arc BDXCE: 180/360(2π)(10) = ½(2π)(10) = 10π

Semicircle EOBDXCE Perimeter: 10π + 2(10) =
= 10π + 20 -or- 10(x + 2)

21
Q

What is the perimeter of this figure?

A

Δ: 8² + 6² = x² || 64 + 36 = x² || 100 = x² || 10 = x

AL: 90/360(2π)(10) = 1/4(2π)(10) = 1/2π(10) = 5π

Figure: 8 + 6 + 5π = 14 + 5π

22
Q

If AB = 10, what is the the area of the shaded portion?

A

❏ = (10)(10) = 100

❍ = π(5²) = 25π

Shade: 100 - 25π

23
Q

If OC bisects AB, AB = 16, and OC = 6, what is the area of the circle?

A

AC = 8

AO = 10

❍: π(10²) = 100π