Chemistry Bridging Course Flashcards

1
Q

Atomic Number

A

Number of protons in the nucleus

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2
Q

Mass Number

A

The total number of protons and neutrons in the nucleus

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3
Q

Cation

A

Positive ion which has less electrons than protons

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4
Q

Anion

A

Negative ion which has more electrons than protons

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5
Q

Isotopes

A

Atoms of the same element with the same number of protons but different number of neutrons

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6
Q

Do isotopes of the same element have the same chemical properties

A

Yes, they have the same electron configuration (same number of electrons)

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7
Q

What physical properties of isotopes of the same element might be different ?

A

The mass, density, boiling point, diffusion rate

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8
Q

Relative Atomic Mass , Ar

A

The weighted mean mass of an atom compared with 1/12th mass of an atom of carbon-12

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9
Q

Relative Isotopic Mass

A

The mass of an isotope compared with 1/12th mass of an atom of carbon-12

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10
Q

Ar Value

A

Mass of an element (mass number)

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11
Q

Relative Formula Mass (Mr)

A

Mass of each atom multiples by how many of each atom there is
Ar values of each atom
e.g O2 (oxygen) = 16 x 2
Mr = 32

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12
Q

Water of crystallisation

A

eg CuSO4.5H20
The full stop is the water of crystallisation
You multiply the Mr of water (1+1+16=18) by the number in front of H2O in this case 5
so 18x5

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13
Q

Diatomic Substances

A

O2 Oxygen
H2 Hydrogen
N2 Nitrogen
F2 Fluorine
Br2 Bromine
I2 Iodine
Cl2 Chlorine

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14
Q

Polyatomic Substances

A

H2O Water - Molecule
NaOH Sodium Hydroxide - Lattice

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15
Q

Molecular Formula

A

Actual number of atoms in each element in a molecule
e.g Glucose = C6H12O6
6 Carbons
12 Hydrogens
6 Oxygen

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16
Q

Empirical Formula

A

Simplest whole number ratio of atoms of each element in a compound
e.g Glucose = C6H12O6 = CH2O

17
Q

Calculating Empirical Formula

A

Step 1: Mass or Percentage/Ar for each element
Step 2: Divide all the answers by the smallest answer from step 1
Step 3: Find the simplest whole number ratio
1.49 or 1.5 can’t be rounded up to 2.
Multiply all rations till they are whole numbers

18
Q

Calculating The Molecular Formula From The Empirical Formula (with Mr known)

A

Step 1: Calculate Empirical Formula

Step 2: Work out empirical mass e.g CH2 = 12+2 = 14

Step 3: Divide Mr by empirical mass which is the multiple e.g 56/14 = 4

Step 4: Multiple empirical formula by the multiple = CH2 x 4 = C4H8

19
Q

Calculating The ‘Water of Crystallisation’
Example 1

A

CuSO4.xH2O
x = water of crystallisation
CuSO4.5H2O
5H2O = water of crystallisation
. = 18 x number in front if H2O
Step 1: Calculate the mass of the anhydrous salt (mass of crucible&resiude - mass of crucible)
Step 2: Calculate the mass of water lost
(mass of crucible&hydrated salt - mass of crucible&residue)
Step 3: Ratio of Anhydrous (without water) salt : water
Use empirical formula
Step 4: Find the simplest whole number ratio of anhydrous salt : water
Step 5: The number for water is the number that goes in front of H2O

20
Q

Calculating the ‘Water of Crystallisation’
Example 2

A

Step 1: Calculate the mass of water lost:
(Mass of hydrated salt - mass of anhydrous salt) which equals the mass of water
Step 2: Ratio of anhydrous salt : water using empirical formula
Step 3: Find the simplest whole number ratio

21
Q

Endings

A

‘ide’ - element negative ion (anion) with a negative charge
‘ate’ - compound negative ion (anion) with oxygen

22
Q

Polyatomic Ions

A

Ammonium- NH4(+)
Hydroxide- OH(-)
Nitrate (v) NO3(-)
Carbonate - CO3(2-)
Sulfate (VI) - SO4(2-)
Phosphate - PO4(3-)

23
Q

Combustion of Fuels

A

Burning - Reacting with Oxygen
Balance those equations in alphabetical order
1-Carbon 2-Hydrogen 3-Oxygen