Chemical Kinetics Flashcards
Differential Rate Law? (General one)
-Δ[A]/Δt
Rate Law (n=1)
Rate = k[A]
Slope (n=0)
Slope = -k
Half-Life (n=2)
t(1/2) = 1/k[A]o
Rate Law (n=0)
Rate = k
Plot needed to give a straight line (n=1)
ln[A] vs t
Slope (n=2)
Slope = k
Half-Life (n=0)
t(1/2) = [A]o/2k
Integrated Rate Law (n=2)
1/[A] = kt + 1/[A]o
Half-Life (n=1)
t(1/2) = ln(2)/k
Plot needed to give a straight line (n=2)
1/[A] vs t
Integrated Rate Law (n=0)
[A] = -kt + [A]o
Rate Law (n=2)
Rate = k[A]^2
Integrated Rate Law (n=1)
ln[A] = -kt + ln[A]o
Plot needed to give a straight line (n=0)
[A] vs t
When n= 1, how does t(1/2) vary when [A] varies?
- in what way does [A] vary to make t(1/2) in this way?
t(1/2) is constant and does NOT depends on [A]
When n= 0, how does t(1/2) vary when [A] varies?
- in what way does [A] vary to make t(1/2) in this way?
t(1/2) gets shorter as [A]o decreases
–> As the [A]o goes down, the time taken for the [ ] to go down gets shorter
When n= 2, how does t(1/2) vary when [A] varies?
- in what way does [A] vary to make t(1/2) in this way?
t(1/2) gets longer as [A]o decreases
–> As the [A]o goes down, the time taken for the [ ] to go down gets longer
For n=0 what is the relationship between the variation in rates and in [ ]
Rate stays the same as [ ] VARIES
–> same slope throughout time
For n=2 what is the relationship between the variation is rates and in [ ]
Rate is squared as [ ] is double (x2)
–> going really fast
For n=1 what is the relationship between the variation in rates and in [ ]
Rate is double as [ ] is double
–> take ln[ ] and get k (slope)
What is the Arrhenius Equation?
k = Ae^(-Ea/RT)
What is the equation when solving the Arrhenius equation with the natural log?
ln(k2/k1) = Ea/R (1/T1 - 1/T2)
