Chemical formula Flashcards
K(w)
ionic production of water; K(w) = [H+][OH-] = (10^-7)(10^-7)= 10^-14
Dilution entail
Dilution factor
of 1 in 10
Entail: 1 volume of material & 9 volume of diluent
Factor: 1 + 9 = 10
10ml glucose in 90ml water = ___fold dilution
1L glucose in 1L water = __ fold dilution
- 10 fold
- 2 fold
1 pH unit = ?
10 fold difference in[H+] concentration
Dilution expression
20ml acid & 80 ml water
2 in 10
2:8
Number of Moles formula
no of moles = actual mass (g) / molar mass (gmol^-1)
Amu of C used as standard because?
Mass of Carbon atom is the exact 12g as its atomic mass. It’s used as the standard
Avogardro ‘s number
6.02 x 10^23
- Mass of H2CO3 with 0.1M in 1L
- Mass of H2CO3 with 0.2M in 500ml
- Mass of H2CO3 with 0.02M in 5L
- Molar mass of H2CO3
- Mass of H2CO3 with 0.1M in 1L > 0.1 - mole in 1L > 2+12+48= 62 amu > 0.1 X 62 amu x (6.02 x 10^23) = 6.2g
- Mass of H2CO3 with 0.2M in 500ml > 0.2 mole in 1L > 0.1 mole in 500ml> 0.1 x 62 amu x (6.02x 10^23) = 6.2g
- Mass of H2CO3 with 0.02M in 5L > 0.02mole in 1L > 0.1 mole in 5L > 0.1 X 62 amu x (6.02 x 10^23) = 6.2g
- molar mass of H2CO3 2+12+48= 62 gmol^-1
1M = how many mole in 2L
10M = how many mole in 1L
10M = how many mole in 500ml
10M = how many in 5L
10 mole/dm^3 = how many mole in 1L
10 mole/dm^3 = how many mole in 5L
10 mole/dm^3 = how many mole in 500ml
1M = how many mole in 2L 2 moles
10M = how many mole in 1L 10 moles
10M = how many mole in 500ml 5 moles
10M = how many in 5L 50 moles
10 mole/dm^3 = how many mole in 1L 10 moles
10 mole/dm^3 = how many mole in 5L 50 moles
10 mole/dm^3 = how many mole in 500ml 5 moles
Formula for concentration
Concentration= no of mole/ volume
Molar = concentration = molarity T/F
True
Milli mole =
Micro mole =
Nano mole =
Milli mole = 10^-3
Micro mole = 10^-6
Nano mole = 10 ^-9
Unit for molar mass
gmol^-1
Formula for mass of atom
= amu x ( 6.02 x 10^23)
