Chapter17 - Ruin Theory Flashcards

1
Q

Describe N(t) and state its distribution.

A

N(t) is the number of claims arising within a time period of [0,t] for all t>0.

If N(1) ~ Poi(lambda) then N(t)~Poi(lambda*t)
(This is called the Poisson Process)

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2
Q

State the conditions for the claim number process.

A
  1. N(0) = 0
  2. N(t) must be integer value for all t>0
  3. N(s)<N(t) for s<t - claims are non-decreasing over time
    4.When s<t, N(t)-N(s) represent the number of claims over the period (s,t]
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3
Q

What type of Process is the Poisson Process?

A

A counting process

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4
Q

State the conditions for a claim number process to be a Poisson process

A
  1. N(0) = 0 and N(s)<=N(t) when s<t
  2. Maximum of one claim in a very short time interval h
  3. The number of claims in a time interval of length h does not depend on when that time interval starts
    4.For s<t , the number of claims in the time interval (s,t] is independent of the number of claims up to time s
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5
Q

What is the distribution of T1, the time until the first claim?

A

T1~exp(lambda)

P(T1<= t) = 1-exp(-lamba*t)

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6
Q

What is meant by the compound Poisson process?

A

The Poisson process for the number of claims will be combined with a claim amount distribution to give a compound Poisson process for the aggregate claims.

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7
Q

State the 3 assumptions for the aggregate claims process S(t)
to be a compound Poisson process.

A
  1. The random variables Xi are independently and identically distributed
  2. The random variables Xi are independent of N(t) for all t>0
  3. The stochastic process N(t) is a Poisson process whose parameter is lambda
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8
Q

What is the kth moment about zero of Xi’s

A

m_k = E[x^k]

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9
Q

Define the moment generating function Mx(r)

A

Mx(r)=E[exp(-r*x))

Where Mx(r) is dependent on the distribution of x

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10
Q

What is the mean and variance of S(t)

A

If S(t)=x1+x2+…+xN then (N, number of claims and N~Poi(lambda)
E[s(t)] = lamdaE[x] = lambdam1
Var[s(t)]=lamdaE[x^2]=lambdam2

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11
Q
A
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12
Q

Define and state Lundbergs inequality

A

Lundberg’s inequality tells us that we can find an upper bound for the probability of Ultimate ruin (Y(U))

Y(U) <=exp(-R*U)
R - the adjustment coefficient
U initial surplus

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13
Q

What does large values of R, the Adjustment Coefficient, imply.

A

R measures risk - it in a inverse measure of risk. So a large R implies the probability of ultimate ruin, Y(U), reduces.

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14
Q

What is the equation to calculate R?

A

lambda*Mx(r) = lambda + CR

Where C is the the premium income per unit of time

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15
Q

What is the upper bound for R?

A

lambda + CR = lambdaMx(R)
lambda + CR = lambda
E[exp(Rx)]
lambda + CR = lambdaE[1+ Rx + (Rx)^2/2
lambda + CR = lambda
(E(1) + RE(x) + 1/2R^2E(x^2)

lambda + CR = lambda(1+ Rm1 + 1/2R^2m2)
R< 2(c-lambam1)/lambdam2

If c = (1+o)lamda*m1 where o is the insurers loading factor, then

R<(2om1)/m2

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16
Q

When can you define a low bound for R?

A

When the distribution of X, the individual claim amounts, has an upper limit, say M.

17
Q

What is the lower bound for R?

A

M is the upper bound to the distribution of X. e.g. X~uni(0,100), M=100

R>1/Mlog(c/lamda*m1)

If c=(1+o)lamda*m1 then

R>1/Mlog(1+o)

18
Q

Define proportional reinsurance.

A

alpha is the retained proportion that the insurer will pay of every claims.

Y=alphaX
Z=(1-alpha)
X

19
Q

What is the mean and variance of the claim amount paid by the direct insurer and reinsurer under proportional reinsurance?

A

Y = amount paid by direct insurer
Z = amount paid by reinsurer

E[Y] = E[alphaX] = alphaE[X}
E[Z] = E[(1-alpha)X] = (1-alpha)^2E[X]

Var[Y] = Var[alphax] = alpha^2Var[X]
Var[Z] = Var[(1-alpha)X] = (1-alpha)^2Var[X]