Chapter 9 Flashcards
Convergence of a Geometric Series
A geometric series with ratio “r” diverges if |r| ≥ 1. If 0 < |r| < 1, then the series converges to the sum ∞Σn=0 a(r)^n = a/(1 - r), 0 < |r| < 1
nth Term Test for a Convergent Series
If ∞Σn=1 (an) converges, then lim(n -> ∞) an = 0
nth Term Test for a Divergent Series
If lim(n -> ∞) an ≠ 0, then ∞Σn=1 (an) diverges
The Integral Test
If “f” is positive, continuous, and decreasing for x ≥ 1 and an = f(n), then ∞Σn=1 (an) and 1∫∞ f(x)dx either both converge or both diverge
P-series
- converges if p > 1
2. diverges if 0 < p ≤ 1
Direct Comparison Test
Let 0 < an ≤ bn for all “n”
- If ∞Σn=1 (bn) converges, then ∞Σn=1 (an) converges.
- If ∞Σn=1 (an) diverges, then ∞Σn=1 (bn) diverges.
Limit Comparison Test
Suppose that an > 0, bn > 0, and lim(n -> ∞) an/bn = L where L is finite and positive. Then the two series Σan and Σbn either both converge or both diverge.
Alternating Series Test
Let an > 0. The alternating series ∞Σn=1 [(-1)^n * (an)] and ∞Σn=1 [(-1)^n+1 * (an)] converge if the following two conditions are met:
- lim(n -> ∞) an = 0
- a(n+1) ≤ an, for all “n”
Alternating Series Remainder
If a convergent series satisfies the condition a(n+1) ≤ an, then the absolute value of the remainder (Rn) involved in approximating the sum “S” by Sn is less than (or equal to) the first neglected term. That is, |S - Sn| = |Rn| ≤ a(n+1)
Absolute Convergence
If the series Σ|an| converges, then the series Σan also converges.
Definitions of Absolute and Conditional Convergence (2)
- Σan is absolutely convergent if Σ|an| converges.
2. Σan is conditionally convergent if Σan converges, but Σ|an| diverges.
nth Taylor Polynomial
Pn(x) = f(c) + f’(c)(x-c) + f’’(c)/2! (x-c)^2 + . . . + f^n(c)/n! (x-c)^n
Ratio Test
Let Σan be a series with nonzero terms
- Σan converges absolutely if lim(n -> ∞) |a(n+1)/an| < 1
- lim(n -> ∞) an diverges if lim(n -> ∞) |a(n+1)/an| > 1 or lim(n -> ∞) |a(n+1)/an| = ∞
- The Ratio Test is inconclusive if lim(n -> ∞) |a(n+1)/an| = 1