Chapter 3 Flashcards
stoichiometry
quantities of substances consumed and produced in chem reaction
combination reaction
2+ substances combine to form 1 product
decomposition reaction
1+ substance decomposes to form 2+ other substances
combustion reaction
rapid reactions produce flame (with O2- air)
combustion: meth-
1 carbon atom
combustion: eth-
2 carbon atoms
combustion: prop-
3 carbon atoms
hydrocarbon formula:
C(n)H(2n+2)
(n = # of carbons)
amu
mass of 1 proton
atomic weight
avg amu of all isotopes; given on pt
formula weight
sum of atomic weights in chem formula
molecular weights
sum of atomic weights in a molecule
mole
6.022 x 10^23 atoms
molar mass
(g/mol)
molar mass
mass of 1 mole of substance
- g/mol = formula weight
empirical formula
lowest ration # of atoms
combustion analysis
compound w/ C, H, O analyzed through combustion
limiting reactant
completely consumed in reaction
theoretical yield
quantity of product when limiting reactant in consumed
actual yield
amount of product obtained (always less than theoretical yield)
combustion formula
hydrocarbon + O2 (g) –> CO2 (g) + H2O (g)
(hydrocarbon = C(n)H(2n+2))
percent mass composition
((number of atoms of element) x (atomic weight of element)) / (formula weight of substance) x 100%
of molecules per 1 mol
1.66054 x 10^-24 molecules
determining empirical formulas
- Change % to grams
- Calculate moles of each element
- Divide by the smallest number of moles to calculate the mole ratio
determining molecular formulas
- Calculate molecular weight of empirical formula
- Divide by experimental molecular weight
- Multiply subscripts by this whole-number ratio
Stoichiometric Calculations (ex: how many – to react away –)
- grams of substance A–>
(molar mass/(g/mol)) –> - moles of substance A –> –> moles of substance B
(coefficient ratio from balance =) 3. (molar mass of B) - find: grams/milligrams
steps for limiting reactant questions
- write/balance equation
- substance (A) g–>mol
- mol-to-mol ratio
- substance (B) mol–>g
- if # is more than given amount = limiting
- if # is less than amount; not limiting
steps for theoretical yield
- start w/ limiting reactant
- g –> mol
- mol-to-mol w/ (whole compound-to-limiting)
- mol –> g (compound)