Chapter 23 - Integration 2 (Pure) Flashcards

1
Q

∫ (ax+b) ⁿ =?

A

∫ (ax+b) ⁿ = 1/ a (n+1) (ax+ b) ⁿ + C

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2
Q

∫ 1/x = ?

A

∫ 1/x = ln [x] + c

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3
Q

∫ 1/ ax + b = ?

A

∫ 1/ ax + b = 1 / a ln [ ax+ b ] + C

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4
Q

∫ e^ax dx = ?

A

∫ e^x dx = 1/a e^x + c

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5
Q

∫ e^ (ax + b ) = ?

A

∫ e^ (ax + b ) = 1/a e^(ax + b ) + C

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6
Q

∫ sin ax dx = ?

A

∫ sinx dx = - 1/ a cosx + c

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7
Q

∫ cos ax dx = ?

A

∫ cosx dx = 1/a sin x + c

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8
Q

∫ sec² x = ?

A

∫ sec² x = 1/a tan ax + c

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9
Q

∫ f’(x) / f(x) = ?

A

∫ f’(x) / f(x) dx = ln [f(x)] + c

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10
Q

∫ du/dx f’(u) dx = ?

A

∫ du/dx f’(u) dx = f (u) + C

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11
Q

the double angle formula, for sin(2A) = ?

A

sin(2A) = 2 sin A cos A

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12
Q

the double angle formula, for cos(2A) = ?

A

cos(2A) = cos²A - sin²A

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13
Q

the double angle formula for tan 2A = ?

A

tan 2A = (2 tan A)/ (1- tan²A)

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14
Q

what’s ‘sexy tans’ ?

A

sec²x = 1 + tan²x

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15
Q

what’s ‘cosey cots’ ?

A

cosec² x = 1 + cot² x

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16
Q

what’s integration by parts? found on the data sheet…

A

∫ u dv/dx = uv -∫ v du/dx dx

L logarithms
Algebra
T trigonometry
E everything else

the order to choose u :)

17
Q

how to do integration by substitution?

A

step one - set u as inner of equation
step two - take integral of u
step three- take out dx and substitute in

(6x+ 1)^1/2 dx

u= 6x+1
du/dx = 6

u^0.5 X 1/6

1/9 (6X + 1) ^3/2 + C