Chapter 22 - Differentiation 2 (Pure) Flashcards

1
Q

what are convex curves?

A

convex curves are u shaped so has an increasing gradient and in turn a positive second derivative

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2
Q

what is a convex curve?

A

a convex curve looks like an n shape and has a decreasing gradient and in turn a negative second derivative

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3
Q

what are points of inflection?

A

a point where a curve changes from concave to convex.

remember f’‘(x)=0 at a point of inflection

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4
Q

what’s the chain rule?

A

y = f(g(x))

dy/dx = g⁻¹ (x) f⁻¹(g(x))

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5
Q

what’s the connected rate of change rule?

A

dy/dx = dy / du X du / dx

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6
Q

when is the chain rule used?

A

the chain rule is used to differentiate composite functions
like f(g(x))

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7
Q

how to differentiation Y= e ^f(x)

A

Y= e ^f(x) dy/dx = f’(x) e ^ f(x)

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8
Q

how to differentiate Y= ln(x)

A

Y= ln(x) dy/dx = 1/x

or

dy/dx = f’(x) / f(x)

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9
Q

what do cos and sin x differentiate to?

A

sin x
cos x
-sin x
- cos x

differentiate down integrate up

btw its a loop :)

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10
Q

what does tan differentiate to?

A

tan differentiates to sec² x

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11
Q

what’s the product rule? when do you use the product rule?

A

if Y=uv, dy/dx= u dv/dx + v du/dx

where u and v are functions

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12
Q

when to use the quotient rule?

A

you use the quotient rule when its a fraction

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13
Q

how to differentiate parametric equations? what is the equation?

A

dy/dx = dy/dt ÷dx/dt

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14
Q

what is implicit differentiation?

A

‘implicit differentiation’ is used when an equation is written in the form f(x,y) = g(x,y)

example: y²= xy + x + 2 is implicit

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15
Q

how to do implicit differentiation?

A

step 1 : differentiate terms in the x only with respect to x
step 2: use the chain rule to differentiate the y only
step 3: use the the product rule to differentiate terms in both x and y
step 4: re arrange to make dy/dx the subject

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16
Q

what’s y= arcsin x differentiate?

A

y= arcsin x

dy/dx = 1/ √ 1 -x²

17
Q

what’s y= arccos x differentiate to?

A

y= arccos x

dy/dx = - 1 / √1-x²