Chapter 2 Gravitational Fields Flashcards
Defining Gravitational Field
- There is a force of attraction between all masses
- This force is known as the ‘force due to gravity’ or the weight
- The Earth’s gravitational field is responsible for the weight of all objects on Earth
- A gravitational field is defined as:
- A region of space where a mass experiences a force due to the gravitational attraction of another mass
- The direction of the gravitational field is always towards the centre of the mass
- Gravitational forces cannot be repulsive
The strength of this gravitational field (g) at a point is the force (Fg) per unit mass (m) of an object at that point:
- Where: F=ma
- g = gravitational field strength (N kg-1)
- Fg = force due to gravity, or weight (N)
- m = mass (kg)
Representing Gravitational Fields
- The direction of a gravitational field is represented by gravitational field lines
- The gravitational field lines around a point mass are radially inwards
- The gravitational field lines of a uniform field, where the field strength is the same at all points, is represented by equally spaced parallel lines
- For example, the fields lines on the Earth’s surface
Radial fields are considered
- are considered non-uniform fields
- The gravitational field strength g is different depending on how far you are from the centre
- Parallel field lines on the Earth’s surface are considered a
-
uniform field
- The gravitational field strength g is the same throughout
Point Mass Approximation
- For a point outside a uniform sphere, the mass of the sphere may be considered to be a point mass at its centre
- A uniform sphere is one where its mass is distributed evenly
- The gravitational field lines around a uniform sphere are therefore identical to those around a point mass
- An object can be regarded as point mass when:
- A body covers a very large distance as compared to its size, so, to study its motion, its size or dimensions can be neglected
- So, the gravitational field strength (The force per unit mass on an object in a gravitational field. g = 9.81 N/kg on Earth. g = GM/r2
- g is different depending on how far you are from the centre of mass of the sphere
Newton’s Law of Gravitation
- The gravitational force between two bodies outside a uniform field, e.g. between the Earth and the Sun, is defined by Newton’s Law of Gravitation:
- Newton’s Law of Gravitation states that:
The gravitational force between two point masses is proportional to the product of the masses and inversely proportional to the square their separation
Newton’s Law of Gravitation equation form, this can be written as:
Gravitation Equation
- Where:
- FG = gravitational force between two masses (N)
- G = Newton’s gravitational constant
- m1 and m2 = two points masses (kg)
- r = distance between the centre of the two masses (m)
The inverse relationship
- Although planets are not point masses, their separation is much larger than their radius
- Therefore, Newton’s law of gravitation applies to planets orbiting the Sun
- 1/r2
- This means that when a mass is twice as far away from another, its force due to gravity reduces by (½)2 = ¼
Circular Orbits in Gravitational Fields
- Since most planets and satellites have a near circular orbit, the gravitational force FG between the sun or another planet provides the centripetal force needed to stay in an orbit
- Both the gravitational force and centripetal force are perpendicular to the direction of travel of the planet
Kepler’s Third Law of Planetary Motion
- For the orbital time period T to travel the circumference of the orbit 2πr, the linear speed v can be written as
v=2πr/T
- This is a result of the well-known equation, speed = distance / time
- Substituting the value of the linear speed v into the above equation:
- v2= (2πr/T)2=GM/r
- Rearranging leads to Kepler’s third law equation:
- T2=4(π)2r3/GM
- The equation shows that the orbital period T is related to the radius r of the orbit. This is known as Kepler’s third law:
For planets or satellites in a circular orbit about the same central body, the square of the time period is proportional to the cube of the radius of the orbit
- Kepler’s third law can be summarised as:
Circular Orbits in Gravitational Fields equations
- Consider a satellite with mass m orbiting Earth with mass M at a distance r from the centre travelling with linear speed v
- Fg=Fcirc
- Equating the gravitational force to the centripetal force for a planet or satellite in orbit gives:
- GMm/r2 = mv2/r
- The mass of the satellite m will cancel out on both sides to give:
- v2=GM/r
- This means that all satellites, whatever their mass, will travel at the same speed v in a particular orbit radius r
- Recall that since the direction of a planet orbiting in circular motion is constantly changing, it has centripetal acceleration
Geostationary Orbits
- Many communication satellites around Earth follow a geostationary orbit
- This is a specific type of orbit in which the satellite:
- Remains directly above the equator, therefore, it always orbits at the same point above the Earth’s surface
- Moves from west to east
- Has an orbital time period equal to Earth’s rotational period of 24 hours
use of geostationary orbits
- Geostationary satellites are used for telecommunication transmissions (e.g. radio) and television broadcast
- A base station on Earth sends the TV signal up to the satellite where it is amplified and broadcast back to the ground to the desired locations
- The satellite receiver dishes on the surface must point towards the same point in the sky
- Since the geostationary orbits of the satellites are fixed, the receiver dishes can be fixed too
Deriving Gravitational Field Strength (g)
- For calculations involving gravitational forces, a spherical mass can be treated as a point mass at the centre of the sphere
- Newton’s law of gravitation states that the attractive force F between two masses M and m with separation r is equal to:
Fg=GMm/r2
- The gravitational field strength at a point is defined as the force F per unit mass m
g=F/m
- Substituting the force F with the gravitational force FG leads to:
g=F/m=((GMm)/r2)÷m
- Cancelling mass m, the equation becomes:
g=GM/r2
Where:
- g = gravitational field strength (N kg-1)
- G = Newton’s Gravitational Constant
- M = mass of the body producing the gravitational field (kg)
- r = distance from the mass where you are calculating the field strength (m)
Newton’s Gravitational Constant
- a constant used to relate the gravitational field strength between two objets to their mass and separation. the number will be given to you in the exam.
G= 6.67 x 10^-11
Calculating g
- Gravitational field strength, g, is a vector quantity
- The direction of g is always towards the centre of the body creating the gravitational field
- This is the same direction as the gravitational field lines
- On the Earth’s surface, g has a constant value of 9.81 N kg-1
- However outside the Earth’s surface, g is not constant
- g decreases as r increases by a factor of 1/r2
- This is an inverse square law relationship with distance
- When g is plotted against the distance from the centre of a planet, r has two parts:
- When r < R, the radius of the planet, g is directly proportional to r
- When r > R, g is inversely proportional to r2 (this is an ‘L’ shaped curve and shows that g decreases rapidly with increasing distance r)
Graph showing how gravitational field strength varies at greater distance from the Earth’s surface
The Value of g on Earth
- Gravitational field strength g is approximately constant for small changes in height near the Earth’s surface (9.81 m s-2)
- This is because from the inverse square law relationship:
g∝1/r2
- The value of g depends on the distance from the centre of Earth r
- If we take a position h above the Earth’s surface, where it is reasonable to assume h is much smaller than the radius of the Earth (h << R):
g=GM/(R+h)2≈GM/(R)2
- This means g remains approximately constant until a significant distance away from the Earth’s surface
Gravitational Potential
- The gravitational potential energy (G.P.E) is the energy an object has when lifted off the ground given by the familiar equation:
- G.P.E = mgΔh
- The G.P.E on the surface of the Earth is taken to be 0
- This means work is done to lift the object
- However, outside the Earth’s surface, G.P.E can be defined as:
The energy an object possess due to its position in a gravitational field
- The gravitational potential at a point is the gravitational potential energy per unit mass at that point
- Therefore, the gravitational potential is defined as:
The work done per unit mass in bringing a test mass from infinity to a defined point
Calculating Gravitational Potential
- The equation for gravitational potential ɸ is defined by the mass M and distance r:
- Where:
- ɸ = gravitational potential (J kg-1)
- G = Newton’s gravitational constant
- M = mass of the body producing the gravitational field (kg)
- r = distance from the centre of the mass to the point mass(m)
Point Mass
When a body covers a very large distance as compared to its size, its size or dimensions can be neglected to study its motion.
The gravitational potential is negative near
- an isolated mass, such as a planet, because the potential when r is at infinity is defined as 0
- Gravitational forces are always attractive so as r decreases, positive work is done by the mass when moving from infinity to that point
- When a mass is closer to a planet, its gravitational potential becomes smaller (more negative)
- As a mass moves away from a planet, its gravitational potential becomes larger (less negative) until it reaches 0 at infinity
- This means when the distance (r) becomes very large, the gravitational force tends rapidly towards 0 at a point further away from a planet
Gravitational potential increases and decreases depending on whether the object is travelling towards or against the field lines from infinity
Gravitational Potential Energy Between Two Point Masses
- The gravitational potential energy (G.P.E) at point in a gravitational field is defined as:
The work done in bringing a mass from infinity to that point
- The equation for G.P.E of two point masses m and M at a distance r is:
- GPE=-GMm/r
- The change in G.P.E is given by:
- ΔG.P.E = mgΔh
- Where:
- m = mass of the object (kg)
- ɸ = gravitational potential at that point (J kg-1)
- Δh = change in height (m)
Gravitational Potential
The work done per unit mass in bringing a test mass from infinity to a defined point.
- Φ = -GM/r
Recall that at infinity, ɸ =
- 0 and therefore G.P.E = 0
- It is more useful to find the change in G.P.E e.g. a satellite lifted into space from the Earth’s surface
- The change in G.P.E from for an object of mass m at a distance r1 from the centre of mass M, to a distance of r2 further away is:
ΔGPE= -GMm/r2-(-GMm/r1)=GMm(1/r1-1/r2)
Change in gravitational potential energy between two points
- The change in potential Δɸ is the same, without the mass of the object m:
Δɸ= -GM/r2-(-GM/r1)=GM(1/r1-1/r2)
Change in gravitational potential between two points
Gravitational potential energy increases as a satellite leaves the surface of the Moon