Chapter 2 Flashcards
ω λ wavelength f/v frequency μm micrometer τ transmissivity ξ absorptivity θ theta
EMR defined
- Form of energy transport in free space
* wave travel through space at speed of light
Maxwell equations
Esubx = Eomega cos (wt-kz)
Eomega = max electrical energy ω= angular freq (2 piv)
Electric and magnetic fields are ________ to each other
Orthagonal (perpendicular?)
Radiant energy (Q of a photon) is proportional to frequency
Q=hv
Q=radiant energy (J)
v=frequency
h=Plank’s constant (6.626 X 10^-34 Js
substituteQ=hc/wavelength
h is small number, so approx Q~ 1/wavelength
Radiation from the Sun is ________________ (re polarization)
un-polarized
Man-made sources (laser, radar) have ___________ radiation (re polarization)
polarized
Electromagnetic spectrum for remote sensing
UV, visible, near-ir, mid-ir, thermal, microwave bands (Ka, Ku, X, C, S, L, P)–LOOK AT GRAPH FROM LECTURE
shorthand ranges for RGB spectra
blue .4-.5 μm
green .5-.6 μm
red .6-.7 μm
Polarization
The orientation of the electric field
Vertical polarization: electric vector is PERPENDICULAR to the plane of incidence
Horizontal polarization: electric vector is PARALLEL to the plane of incidence
Sun=unpolarized
Man-made sources (laser, radar) have polarized radiation
Infrared
near and mid=reflective =short wave
far=emissive radiative thermal
Microwaves
letters come from military, don’t want enemy to know signal
The bulk of sun’s radient energy distribution is
visible (43.5%) and near infrared (36.8%). Also significant amts of near UV (5.32%) and Mid IR (12%)
Blackbody concept
Object that absorbs and emits 100% of radiation
Does not exist in nature
Emissivity would equal 1
Assumptions:
- Isotropic
- homegeneous
- unpolarized
2 objects with same temp would emit same E
Blackbody would emit more E than a comparable gray body (which has Emissivity is < 1)
MOST IMPORT. CONCEPT
Graybody
Object that reflects part of the incident radiant
Emissivity is < 1
M=emissivitysigma constantTemp4 (double check this)
Emissivity
the relative ability of a surface to emit radiation
- describes ACTUAL absorption and emission properties of real objects (gray bodies)
- Is wavelength dependent (usually use avg)
- Is equal to (graybody emittance)/(blackbody emittance)–of same temp
- Use it to calculate an object’s radiant temp, or brightness temp
The temp at which a blackbody would have to be to emit the same energy as emitted a graybody at some physical temp
T(rad) = e^(1/4)T(kin) e= [(T(rad) / T(kin)] ^4
kin=kinematic physical
Selective radiator
emits certain types of EMR (better)
Two objects can have the same ___________ temp but different _________ temperatures…Why?
kinematic, radiant
Because they have different emissitivities
Understand why mirror has no emissivity
gah
Planck’s law (Spectral radiance)
‘All bodies who temp are above absolute zero K (-273.2), emit radiation”
Heat transformed into radiant energy
(need formula)
L = amount of E per unit serface per unit time, per solid angle emitted at the wavelength λ
Maximum radiation of sun at what wavelength?
6000K (Kelvin) at ~.5 micrometer