Chapter 15 - Chemistry of Haloalkanes Flashcards

1
Q

General formula of Haloalkanes?

A

CnH2n+1X

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2
Q

Polarity of haloalkanes?

A

Halogen atoms are more electronegative than carbon. The C-X bond polarity decreases from F –> I .

Polarity of the C-X bond attracts nucleophiles to the Carbon atom with partial positive charge.

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3
Q

What is a nucleophile?

A

A nucleophile is an atom or group of atoms that donates an electron pair to an electron-deficient centre.

  • Electron donator
  • Usually electron rich and may be a negative ion, with a lone pair, or a molecule containing an atom with a partial negative charge
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4
Q

What is nucleophilic substitution?

A

Nucleophile replaces the halogen in the haloalkane, which is lost as a halide ion.

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5
Q

What are the nucleophilic substitution steps?

A
  • The OH- ion acts as a nucleophile, donating an electron to the partially positive carbon atom
  • A new bond forms between the oxygen atom of the OH- ion and the carbon atom
  • The carbon-halogen bond breaks by heterolytic fission
  • organic product formed is an alcohol + halide ion is formed
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6
Q

Hydrolysis of Haloalkane?

A

Alcohol + h+ion + halide ion formed

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7
Q

Halide ions react with silver ions to form what?

A

Forms silver halide precipitate.

  • The rates of hydrolysis of different carbon-halogen bonds can be measured by measuring the time for silver halide precipitate to form
  • The lower the bond enthalpy, the faster the haloalkane reacts
  • I reacts faster than Br and that reacts faster than Cl
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8
Q

Benefits of the Ozone layer?

A

Helps filter out harmful UV radiation which is harmful to us which can cause skin cancer, cataracts and damage to crops.

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9
Q

CFC molecules in the presence of UV radiation?

A

C-Cl bonds are broken by homolytic fission to form radicals.

CFC molecule = CCl3F

Breakdown = CCl3F –> .CCl2F + Cl.

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10
Q

The breakdown of ozone catalysed by Cl. radicals.

The two Propagation steps?

A
  1. Cl. + O3 –> ClO. + O2
  2. ClO. + O –> Cl. + O2

overall: O3 + O –> O2

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