Chapter 15 (approved) Flashcards

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1
Q

How can haloalkanes be classified?

A

As primary, secondary or tertiary depending on how many carbon atoms attached to the C-X carbon atom

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2
Q

Why is the carbon halogen bond polar in haloalkanes?

A

The halogen atoms are more electronegative than the carbon atoms so, the bond is closer to the halogen atom

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3
Q

What is the carbon atom in haloalkanes able to do due to its slight positive charge?

A

Attract species containing a lone pair of electrons

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4
Q

Nucleophile def. (1)

A

Electron pair donor

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5
Q

What happens to the nucleophile?

A

It is attracted to an electron deficient carbon atom, where it donates a pair of electrons to form a new covalent bond

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6
Q

What is hydrolysis?

A

A reaction involving water or an aqueous solution of a hydroxide that causes the breaking of a bond in a molecule, resulting in the molecule being split into two products

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7
Q

Nucleophilic substitution in the hydrolysis of a haloalkane where the halogen atom is replaced by an -OH group (6)

A

1 The nucleophile approaches the carbon atom attached to the halogen on the opposite side of the molecule from the halogen atom

2 This direction of attack by the -OH ion minimised repulsion between the nucleophile and the S- halogen atom

3 A lone pair of electrons on the hydroxide ion is attracted and donated to the S+ carbon atom

4 A new bond is formed between the oxygen atom of the hydroxide ion and the carbon atom

5 The carbon-halogen bond breaks by heterolytic fission

6 The new organic product is an alcohol, a halide ion is also formed

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8
Q

Hydrolysis of haloalkanes:

Type of reaction mechanism
Products
Reaction conditions

A

Nucleophilic substitution
Alcohol and halide ion
Aqueous sodium hydroxide and heating under reflux

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9
Q

Why must the hydrolysis of haloalkanes be done under reflux?

A

Because the reaction is very slow at room temperature so it must be done under reflux to obtain a good yield of product

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10
Q

What does the rate of hydrolysis depend on?

A

The strength of the carbon halogen bond in the haloalkanes
The classification of the haloalkanes (primary, secondary, tertiary)

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11
Q

How does the rate of hydrolysis change down the halogen group and why?

A

Chlorine has a very strong C-X bond due to the largest difference in electronegativity, so a lot of energy is required to break it, making it the least reactive, but down the group the Electronegativity difference decreases, leading to weaker bonds due to less energy required to overcome them and therefore more reactive compounds down the group

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12
Q

How do you measure the rate of hydrolysis of primary haloalkanes? (Method)

A
  1. Set up 3 test tubes, adding 1cm3 of ethanol to each, and. 2 drops of 1-chlorobutane, 1-bromobutane and 1-iodobutane to each respective test tube
  2. Stand the test tubes in a water bath at 60C
  3. Place a tests tube with 0.1 mol dm^-3 silver nitrate in the water bath and allow all tubes to reach a constant temperature
  4. Add 1cm^3 of the silver nitrate quickly to each of the test tubes. Immediately start a stop watch and time how long the reaction takes
  5. Observe and record how long it takes each precipitate (silver halide) to form
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13
Q

What are the expected observations from the rate of hydrolysis of primary haloalkanes reaction?

A

1-chlorobutane: A white precipitate forms very slowly
1-bromobutane: A cream precipitate forms slowly (faster than chloro but slower than iodo)
1-iodobutane: A yellow precipitate forms rapidly

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14
Q

What causes the results of the rate of hydrolysis of haloalkanes experiment? (1)

A

The respective bond enthalpies of the carbon-halogen bonds

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15
Q

How does the classification of the haloalkane affect its rate of hydrolysis?

A

The primary haloalkanes are hydrolysed the slowest, whilst the tertiary haloalkanes are hydrolysed the fastest

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16
Q

What are the two reasons that the rate of hydrolysis of tertiary alkanes is faster than for primary haloalkanes?

A

Tertiary carbocations are more stable, and tertiary carbocations are formed by a two step mechanism

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17
Q

How do you know that the carbon halogen bond strength isn’t the only factor influencing the rate of hydrolysis?

A

Because the isomers of haloalkanes hydrolyse at different rates

18
Q

Hydrolysis of a tertiary haloalkane is a two step mechanism.
Describe each step:

A
  1. C-X breaks by heterolytic fission so a tertiary carbocation and halide ion (X-) formed
  2. OH- ion attacks carbocation to form product
19
Q

Organohalogen compounds

A

Molecules that contain at least one halogen atom joined to a carbon chain

20
Q

Where is the ozone layer found?

A

At the outer edge of the stratosphere

21
Q

What proportion of the gases in the ozone layer are ozone

A

A tiny fraction

22
Q

What does ozone do?

A

Absorbs the most biologically damaging ultraviolet radiation (UV-B) from the Sun’s rays, allow only a small amount to reach the Earth’s surface

23
Q

What are the harmful effects of UV-B?

A

Biologically damaging, causes sunburn

24
Q

What is a consequence of continued depletion of the ozone layer?

A

This will allow more UV-B radiation to reach the Earth’s surface

25
Q

Why is an ethanol solvent used in the hydrolysis of haloalkanes experiment?

A

Because haloalkanes are insoluble in water, so ethanol allows the water and the haloalkane to mix

26
Q

What happens to ozone in the stratosphere?
(Explanation and formulae)

A

It is continually being formed and broken down by UV radiation
High energy UV breaks oxygen molecules into oxygen radicals
O2 —> 2O
Equilibrium is then reached between the oxygen molecules and oxygen radicals, where ozone is formed and broken down at the same rate
O2 + O <—> O3 reversible

27
Q

What human activity has affected the stratosphere and how?

A

The use of CFC’s has affected the equilibrium between the rate of formulation and breakdown of ozone in the stratosphere, by breaking down to form chlorine radicals which catalyse the breakdown of ozone

28
Q

How were CFC’s commonly used?

A

As refrigerants and aerosol propellants

29
Q

Why were CFC’s so stable, and what was the consequence of this?

A

The because of their strong carbon-halogen bonds, which means that it takes them a long time to reach the stratosphere

30
Q

What happens to the CFCs once they reach the stratosphere?

A

UV radiation breaks the carbon-halogen bond by homolytic fission as it has the lowest bond enthalpy
Chlorine radicals are formed
The chlorine radicals catalyse the breakdown of the ozone

31
Q

Photodissection

A

When the carbon-halogen bond in CFCs is broken down into radicals by UV radiation

32
Q

Photodissection of CF2Cl2 formula

A

CF2Cl2 —> CF2CL.+ Cl.

33
Q

What does the chlorine radical formed by photodissection do?

A

It is very reactive, and reacts with ozone molecules, breaking it down into oxygen by a 2 step process: propagation, which repeats in a chain reaction over and over

34
Q

Propagation steps of ozone breakdown by chlorine radiation

A

Step 1: Cl. + O3 —> ClO. + O2
Step 2: ClO. + O —> Cl.+ O2

Overall:
(remove what’s the same before and after, then combine them)
O3 + O —-> 2O2

35
Q

How are nitrogen oxide radicals formed

A

During lighting strikes and due to aircraft travel

36
Q

Are CFCs responsible for all ozone depleting reactions?

A

No, other things like nitrogen oxide radicals also catalyse the breakdown of ozone

37
Q

Propagation steps form the breakdown of ozone by nitrogen oxide radicals:

A

Step 1: NO. + O3 —> NO2. + O2
Step 2: NO2. + O —> NO. + O2

38
Q

Properties of CFC’s

A

Non-toxic, unreactive, non-flammable

39
Q

Why are CFCs used in fire extinguishers?

A

Because they are non-flammable

40
Q

Why are CFCs used in aerosols?

A

Because they are non-toxic