chapter 11 Flashcards
dot product of u and v
\u\v\cos(theta)
magnitudes times the cos of angle inbetween
how to determine if vectors are orthogonal
their dot product will be zero
algebraec dot product
u dot v = u1v1 + u2v2 +u3v3
orthogonal projection of u onto v
udotv/magv
Work
f DOT D
ijk circle
ijk arrows pointing left to right
cross product
\u\v\sin(theta)
testing paralell
uxv must be 0
0 cross product
evaluating a cross product
use determenants and shit
torque
r x F
remember that the angle must be the angle invetween
2 things i need for a line in 3d space
point and a vector multiplied by time
tangent vector at a point t
derive y y and z then.
plug t into the original to find the point
when are vectors teh same
same direction and magnitude
when are 2 vectors paralell
their vectors are scalar multiples of eachother
find a vector perpendicular to another vector
let the known vector be P=ai+bj+ck…………………….(1)
and, let the unknown vector be Q=xi+yj+zk………………(2)
Since the two vectors are to be perpendicular to each other,their dot product should be 0.
ie : P.Q=0=(ai+bj+ck).(xi+yj+zk)=ax+by+cz=0………(3)
Now we have three variables and one equation. So there exists infinitely many solutions.
To find one of them, assign any value to any two variables of x,y and z.
This will give you the third variable when you solve the above equation.
Then you get a vector when you plugin the values of x,y and z to the Q
equation (2).
then you have found a vector which satisfies the condition given in the question.
You may find vectors of any magnitude that still satisfies the condition by multiplying a suitable scalar to the newly found vector Q.