Chapter 10 Flashcards
Henry’s Law
C=KP
Solubility of gases ________ as temperature increases
decreases
COD
chemical oxygen demand
- measured by using dichromate as an oxidizing titrant to measure the demand of oxygen in water
Using COD to measure oxygen demand is inaccurate due to the fact that ___________________
Acidified dichromate is so strong of an oxidizing agent that is oxidizes substances that are very slow to consume oxygen in natural water
BOD
biological oxygen demand
- the capacity of the organic and biological matter of natural water to consume oxygen
- uses bacteria and measures oxygen present before and after a period of time
TOC
total organic carbon
- dissolved and suspended organic matter
DOC
dissolved organic carbon
- about 5 ppm in surface waters (bogs/swamps can be 10x this)
fermentation
anaerobic reaction done by bacteria to decompose organic matter
- both oxidation and reduction occurs
epilimnion
top layer of a stratified lake
- substances exist in their most oxidized forms
hypolimnion
bottom layer of a stratified lake
- substances exist in their most reduced forms
Acid-mine drainage
soluble Fe2+ is oxidized when surfaced during mining and is converted into insoluble Fe3+
- reacts with sulfide to form iron(III)sulfide
- and sulfuric ACID
Low pE values signify _____ electron availability, so the medium is very reducing/oxidizing in nature
high, reducing
High pE values signify ______ electron availability, to the medium is very reducing/oxidizing in nature
low, oxidizing
Nernst Equation
E = E* - (RT/zF)lnQ
pE = E/0.0591 (for 1e- @25*C)
calcareous waters
natural waters exposed to limestone
- dissolve carbonate ions into water
Ksp
solubility product equilibrium constant
- concentration of product ions, raised to its coeffiecient in a balanced equation
most abundant ions in calcareous water
Ca2+ and H2CO3 (bicarbonate)
source of bicarbonate in noncalcareous waters?
aluminosilicates
Lower line (rxn) of water pourbaix diagram
2H2O + 2e- = H2 + OH-
Upper line (rxn) of water pourbaix diagram
O2 + 4H+ + 4e- = 2H2O