Chapter 1: Kinematics and Dynamics Flashcards
metric system
MKS
lenght
meter (m)
mass
kg
time
second (s)
current
ampere (A)
amount of substance
mole (mol)
newton
N or kg.m/s^2
angstroms
1A = 10^-10m
breaking each vector into perpendicular componentes
x- and y- componenmts
nanometer
1nm = 10^-9 m
vector addition
tip-to-tail
electron-volts
1 eV = 1.6 x 10^-19 J
x-component
X=V cosθ
y-component
Y =V sinθ
Pythagorean theorem
a^2 + b^2 = c^2
or c= square root of a2+b2
vector subtraction
A - B = A + (-B)
pointing the other direction
multipling vectors by scalars
B = nA
to determine the direction of B, if n is a positive number then B is pointing at the same direction of A but if n is negative number, then B is pointing in the opposite direction of A
displacement (x or d)
vector quantity, does not account for pathway
multiplying vectors by other vectors
to generate a scalar quantity, we use the dot ptoduct:
A . B = A B cosθ
to generate a vector qauntity, we use the cross product:
A x B = A B sinθ
is it notcommutative (A x B ≠ B x A)
distance (d)
considers pathway and is a scalar quantity
up and down signs
up is positive and down is negative
universal gravitational force
Fg = G m1 m2 / r^2
G = 6.67 x 10^-11 N . m^2 / kg ^2
earth’s surface gravity
10 m/s^2
always have a direction
sin 90 =
1
sin 0 =
0
average velocity
v = Δx / Δt
kinetic friction
fk = μk N
static friction
0 < fs < μs N
newton’s first law
Fnet = m a = 0
object will remian at rest or move with a constant velocity if there is no net force on the object
average acceleration
a = Δv / Δt
newton’s second law
Fnet = m a
any acceleration is the result of the sum of the forces acting on the objet and its mass
newton’s third law
Fab = -Fba
any two objects interacting with one another experience equal and opposite forces as a result of their interaction
kinematic (no displacement)
v = v {0}+ at
v {0} = initial velocity
kinematic ( no final velocity)
x = v {0} t + at^2 / 2
kinematic (no time)
v^2 = v {0}^2 + 2ax
kinematic (no acceleration)
x = vt
components of gravity on an inclined plane
Fgx = mg sinθ
Fgy = mg cosθ
torque
t = r x F = rF sinθ
centripetal force
Fc = mv^2 / r
linear motion
free fall
rotational equilibrium
absence of any net torque