Ch5.1 Rates, equilibrium and pH Flashcards

1
Q

What does a rate equation allow you to do?

A
  • to calculate exactly how fast a chemical reaction will proceed
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2
Q

What is the general form of the rate equation?

A

rate = k [A]ᵐ [B]ⁿ

k = rate constant
A and B = concs of reactants a and b
m and n = the orders of reaction with respect to each reactant

the orders can be 0, 1 or 2

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3
Q

What must be considered before constructing a rate equation?

A
  • think carefully about how to design our experiment
  • decide what we’re going to record as a measure of reaction rate eg. vol of gas
  • a trial experiment will establish a suitable range of concs to use
  • we decide on actual values for variables such as concs
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4
Q

Describe the method for determining the orders of reaction

A
  1. keep conc of A the same and systematically change B
  2. draw a reaction curve for each experiment
  3. draw a tangent on each curve at the initial rate
  4. plot the gradients against the concs on a new graph
  5. flat line = 0, straight diagonal = 1, curve upwards = 2
  6. repeat for any other reactants
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5
Q

When would the half-lives method be used to work out the orders of reaction in a rate equation?

A

if nothing in a reaction is visibly measurable eg. esterification, 2 clear colourless liquids react to produce 2 clear colourless liquids

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6
Q

Describe the half-lives method

A
  1. mix a large volume of the reaction mixture in a big beaker
  2. at fixed intervals (usually 1 min) withdraw small samples of the mixture with a volumetric pipette and quench each to stop the reaction
  3. when sufficient samples have been collected/quenched, carry out titrations on each
  4. plot graph of conc falling against time
  5. plot 3 successive half-lives
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7
Q

What will the 3 successive hallf-lives tell you at the end of the half-lives method?

A
  • if half-lives decrease, the reaction is 0 order
  • if they remain constant, the reaction is 1 order
  • if they increase, the reaction is 2 order
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8
Q

What 2 things can a rate equation tell you?

A
  • how quickly the reaction will proceed for any given concs
  • how many steps there are likely to be in the reaction which will help us to work out the mechanism
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9
Q

What is the rate-determining step?

A
  • the slowest step in a reaction
  • it determines the overall speed
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10
Q

How can the rate equation tell you the rate-determining step?

A
  • if the conc of a reactant is in the rate equation, then that reactant or something derived from it takes part in the slow step of the reaction
  • if the conc of a reactant doesn’t appear in the rate equation then neither the reactant nor anything derived from it participates in the slow step
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11
Q

If the equation for the reaction of CO and NO2 is this:
CO+NO2 -> NO+CO2
and the rate equation for this is:
rate = k[NO2]^2,
what does this tell us?

A
  • the rate determining step (usually the first step) involves two molecules of NO2 and nothing else
  • there must be a separate and faster step involving the products of the first step and CO
  • if 2 molecules of NO2 are used in the first steps, we must produce one in the second step to be consistent with the overall equation
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12
Q

What should be the only thing changing when we work out the rate equation for a particular chemical reaction?

A

the only variable that changes should be conc

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13
Q

What is the Arrhenius equation?

A

k=Ae^(-Ea / RT)

k= rate constant
A = pre-exponential factor
T = temp in K
R = gas constant
Ea = activation energy

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14
Q

If concentrations are kept the same, what will happen to the value of k as the temp increases?

A

it will increase

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15
Q

What is the shape and bond angles of an oxonium ion?

A

pyramidal 107’

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16
Q

Where do acidic properties come from?

A

the reaction of H+ ions with water to make oxonium ions

17
Q

word equation for metal and acid

A

metal + acid -> salt + hydrogen

18
Q

word equation for metal oxide and acid

A

metal oxide + acid -> salt + water

19
Q

word equation for metal hydroxide and acid

A

metal hydroxide + acid -> salt + water

20
Q

word equation for metal carbonate and acid

A

metal carbonate + acid -> salt + water

21
Q

What happens when an acid is mixed with water?

A

when an acid donates a proton in the presence of water, the water behaves as a base however the water has become H3O+ which is now an acid

acid in reactants becomes conjugate base and base in reactants becomes conjugate acid in products

22
Q

What happens to bases and acids during neutralisation?

A
  • bases become acids
  • acids become bases
23
Q

What are all acid-base reactions?

A

REVERSIBLE
they are EQUILIBRIUM reactions

24
Q

What is Ka?

A
  • acid dissociation constant

if equation is
HA ⇌ H+ + A-
where A is an acid

Ka = ([H+][A-]) / [HA]

25
Q

How are the dissociations of strong and weak acids different?

A

strong= complete dissociation
weak= partial dissociation

26
Q

What is the general rule for which acids are strong and weak?

A

strong acids are inorganic and weak acids are organic (contain carbon)

27
Q

Describe the Ka values of strong and weak acids

A

strong = high Ka value (always >1)
weak= small (between 0 and 1)

28
Q

What is the formula for calculating pH?

A

pH= -log10[H+]

29
Q

Describe how monobasic, dibasic and tribasic acids behave in dissociation

A
  • monobasic= split apart completely to produce 1 H+ ion
  • dibasic = split apart completely to produce 2 H+ ions
  • tribasic = split apart completely to produce 3 H+ ions
30
Q

What is Kw?

A
  • the ionic product of water
    Kw = [H+][OH-] = 1x10^-14
31
Q

What assumptions are made for weak acid calculations?

A

2 CONTRADICTORY ASSUMPTIONS
- none of the weak acid dissociates (this isn’t as strange an assumption as it seems, for ethanoic acid, 1/1000 molecules dissociate)
- obviously some molecules have to dissociate and when they do, they give equal numbers of [H+] and [A-]

32
Q

After assumptions have been made about weak acid calculations, what conclusion can be made?

A

Ka= ([H+][A-])/[HA]

= [H+]^2/[HA]

33
Q

What is a buffer?

A
  • a solution which is capable of neutralising small additions of H+ and OH-
  • this maintains the pH of the solution
34
Q

Which 2 chemical processes are buffers important for and why?

A
  • most dyes are indicators, if pH isn’t kept constant while they’re being used then they change colour
  • many drugs exist as optical isomers (they have right and left handed forms). right-handed forms can be harmful so they need to be screened out during manufacture. using an enzyme in one of the reaction steps ensures that only left-handed isomers are produced. buffer needed so enzyme doesn’t denature
35
Q
A