Ch. 5 Flashcards
discrete exponential growth
represented by points
Ex: most species only reproduce once a year
continuous exponential growth
represented by a line or curve etc.
Ex: over-lapping generations. some species bred thruout the year
exponential function
y = abx
y - amount after x period
a - intial value
b - growth factor
x - time period
how to write exponential functions and predict
- 9 mill ppl in 1980, increasing 1.7% each yr
a. write an exponential function
b. when will pop reach 4.5 mill?
a. - find growth factor b
pop @ end of yr = 100% of pop @ start + 1.7% of pop @ start
pop @ end of yr = 101.7% pop @ start of year
b = 1.017
- y = abx
y = (2.9)(1.017)x
b.
- Use a graph
- Graph the equation y = (2.9)(1.017)x
- x-value of 0 = 1980, x-value of 26 = 2006
- Use recursion
- Enter initial amount 2.9 & repeatedly multiply by growth factor (1.017)
- Count # times pressed Enter (260
- 1980 + 26 = 2006
exponential growth
y = abx
b > 1
exponential decay
y = abx
0 < b < 1
negative exponents
b-x = (1/b)x
Ex: y = 52(6/5)-x = 52(5/6)x
half-life questions
1200 ppl; every 1/2 hour, 1/2 ppl leave
1 half-life → (1200)(1/2)
2nd half-life → (1200)(1/2)(1/2)
f(x) = 1200(1/2)x
how many ppl after 3 hrs?
about 18
fractional exponent rules
a1/n = n[a Ex: 41/3 = 3[4
am/n = (n[a)m or n[am Ex: 53/4 = (4[5)3 or 4[53
IF N IS EVEN, MUST USE ABSOLUTE VALUES
solving exponent algebraic equations
Find the value of b when f(x) = 4bx and f(3/4) = 32
4b3/4 = 32
b3/4 = 8
b3/4(4/3)= 84/3
b = 84/3 = (3[9)4 = 24 = 16
e
the number e is an irrational # that = approx. 2.718281828 <- this is also the limit of the sequence: (1+1/1)1, (1+1/2)2, (1+1/3)3, …
logistic growth function
a function in which the rate of growth of a quantity slows down after initially increasing/decreasing exponentially

solving e problems
spread of flue in 1,000 ppl modeled by y = 1000/(1 + 990e-0.7x), where y = the # of ppl after x days
a. how many ppl after 9 days?
Graph the equation
Read y when x = 9 -> abt 355ppl
b. horizontal asymptotes?
Trace along same graph
min. y-value gets close to but never reaches 0
max. y-value gets close to but never reaches 1000
y = 0, y = 1000
c. Estimate max # of ppl
max. of y = 1000 ppl
inverse functions
two functions f & g r inverse functions if g(b) = a whenever f(a) = b
graph = reflection of the graph of the original function over the line y = x
inverse of f(x) can be written f-1(x) or f-1 (although the exp. -1 usually means reciprocal, f-1(x) is NOT 1/f(x)

graphing inverse functions
a. y = 2x b. y = x2
- Plot pts to graph each function. Then interchange the coordinates of the original points and plot these points.
**a. **(1,2) → (2,1)
(-1, 1/2) → (1/2, -1)
**b. **(2,4) → (4,2)
(-2,4) → (4,-2)
deciding existence of inverse functions
an inverse is a function. if a reflection of a function over the line y = x isn’t a function, then the inverse doesn’t exist
**a. **y = 2x **b. **y = x2
- Use the vertical line test to decide whether a reflection is the graph of a function (inverse)
-or-
- Just like vertical line tests, u can use the horizontal line test to see whether a function has an inverse (original)
writing inverse equations
Ex: Write an equation for the inverse function of f(x) = 2/3x - 4
- f(x) = 2/3x - 4
- y = 2/3x - 4
- x = 2/3y - 4
- x + 4 = 2/3y
- (3/2)x + (3/2)4 = (3/2)(2/3)y
- 3/2x + 6 = y
- f-1x = 3/2x + 6
so just interchange x & y, and solve for y
logarithmic function
the inverse of the exponential function f(x) = bx and written as f-1(x) = logbx
x = ba → a = logbx
x on outside, b in middle, a in center
base of a log can be any pos. # except 1
log4(-2) is undefined! can’t have neg log
logarithm
(of any pos. real # x) the exponent a when u write x as a power of a base b
x = ba iff a = logbx
base of a log can be any pos. # except 1
common logarithm
a log w/ base 10
common log of x written as log x
x = 10a → a = log x
natural logarithm
a log w/ base e
usually written as ln x
x = ea → a = ln x
evaluating logs
Evaluate each. (Find a). Round decimal answers to the nearest hundredth
a. log464
log464 = log443 → a = 3; has to be 43 cuz base = 4
log464 → 4a = 64 → a = 3
b. log(1/10,000)
log(1/10000) = log10-4 → a = -4
c. ln5.3
use calc; = abt 1.67
d. log145
use calc; = abt 2.16
solving logs
when solving these, remember that x isn’t necessarily the x in the formula. it can be a, b, *or *x
solve logx81 = 2
logb81 = 2
b2 = 81
b = 9
Solve. round decimal answers to nearest hundredth
a. 10x = 15
10a = 15
a = log 15 = abt 1.18
b. ea = 29
ea = 29
a = ln 29 = abt 3.37
c. log2x + log2(x-2) = 3
log2x + log2(x-2) = 3
log2x(x-2) = 3
x(x-2) = 23
x2 - 2x = 8
x2 - 2x - 8 = 0
(x+2)(x-4) = 0
x + 2 = 0 or x - 4 = 0
x = -2 x = 4
check for extraneous solutions! Sub possible solutions into the original equation to be sure they’re not extraneous
x = -2 is undefined, cuz no neg logs log2(-2)
properties of logs
M, N, and P are pos. #’s w/ b not equaling 1, and k is any real #
Product of Logarithms Property
logbMN = logbM + logbN
Quotient of Logarithms Property
logbM/N = logbM - logbN
Power of Logarithms Property
logbMk = k logbM
writing in terms of logM and logN
a. logM2N3
logM2 + logN3 = 2logM + 3logN
b. log(3[M/N4)
log3[M - logN4 = logM1/3 - logN4 = 1/3logM - 4logN
simplifying logs
ln18 - 2ln3 + ln4
ln18 - ln32 + ln4 → power prop.
ln18 - ln9 + ln4
ln18/9 + ln4 → quotient prop.
ln2 + ln4
ln(2•4) → product prop.
ln8
log and exp word problems
- L = 10log(I/I0) What is the change in loudness(L) when I is doubled?
L1= original loudness L2 = loudness after intensity is doubled
increase in loudness = L2 - L1
L2 - L1 = 10log(2I/I0) - 10log(I/I0)
10log(2•I/I0) - 10log(I/I0)
10(log2 + logI/I0) - 10log(I/I0)
10log2 + 10log(I/I0) - 10log(I/I0)
10log2 = abt 3
- A(t) = A0(0.883)twith A(t) - amount present t thousand yrs after death, A0 - amount @ time of death, and t - amount time since death (in 1000’s of yrs)
found in 1968, died 8000 yrs ago, 37% present now; estimate age of the bone
A0(0.883)t = A(t)
A0(0.883)t= 0.37A0
0.883t = 0.37
log(0.883)t = log0.37
t log 0.883 = log0.37
t = log0.37/log0.883
t = 8
Change of Base Property of Logs
For all pos. #’s with b and c not equaling 1,
logbM = (logcM)/(logcb)
using change of base prop.
Evaluate log38to three dec. places
log38 = log8/log3 = abt 1.893
graphing logs
Use a graphing calc to graph y = log6x
- Graph y = log6x or y = logx/log6
- You know that log66 = 1, so use TRACE to confirm by going to x=6