Ch. 4 Flashcards
formulas to know
explicit arithmetic → an = a1 + d(n - 1)
recursive arithmetic → a1 = first term; an = an-1 + d
explicit geometric → an = a1rn-1
recursive geometric → a1 = first term; an = (an-1)r
sum finite arithmetic series → S = n(a1+an) / 2
sum finite geometric series → S = a1- anr / 1-r
sum geometric infinite series → S = a1 / 1-r; |r| < 1
sequence
an ordered list of numbers
terms
the numbers in a sequence
finite sequence
a sequence with a last term
infinite sequence
a sequence with no last term
graphing sequences
each term is paired w/ a number that gives its position in the sequence
by plotting points with coord’s (position, term), u can graph a sequence on a coord plane
limit of a sequence
when the terms of an infinite sequence get closer and closer to a single fixed number L, then L is called the limit
not all infinite sequences have limits; repeating ones, for example, like 1, 2, 3, 1, 2, 3,…
graphing it often helps
explicit formula
gives the value of any term an in terms of n
finding explicit formulas
Ex: Given 90, 83, 76, 69,…, find a formula for the sequence
- Find a pattern. || a repeated subtraction of 7
- Write the 1st few terms. Show how you found each term. ||
a1 = 90
a2 = 83 = 90 - 1(7)
a3 = 76 = 90 - 2(7)
a4 = 69 = 90 - 3(7)
- Express the pattern in terms of n. ||
an = 90 - (n - 1)7
subscript 0
when the 1st term of a sequence represents a starting value before any change ocurs, subscript 0 is often used
Ex: monthly ank account balances, 1st term is v0 for initial deposit. Next term = v1, for 1st month’s interest, etc. etc.
percentage explicit formulas
Ex: bacteria count increases 10% each day; 10,000 now; Find formula for bacteria count after n days
- d + .1d {if annual interest, compounded monthly, then d + (.1/12)d}
d(1 +.1)
d(1.1)
- d0 = 10,000
d<sub>1</sub> = 10,000(1.1) d<sub>2</sub> = d<sub>1</sub>(1.1) = 10,000(1.1)(1.1) = 10,000(1.1)<sup>2</sup> d<sub>3</sub> = d<sub>2</sub>(1.1) = 10,000(1.1)<sup>2</sup>(1.1) = 10,000(1.1)<sup>3</sup> • • • d<sub>n</sub> = 10,000(1.1)<sup>n</sup>
basically, x(1 + rate)n
self-similarity
the appearance of any part is similar to the whole thing
recursive formula
tells how to find the nth term from the term(s) before it
2 parts:
- a1 = 1 ⇔ value(s) of 1st term(s) given
- an = 2an-1 ⇔ recursion equation
recursion equation
shows how to find each term from the term(s) before it
finding recursive formulas
Ex: 1, 2, 6, 24
- Write several terms of the sequence using subscripts. Then look for the relationship b/w each term & the term before it
a1 = 1
a2 = 2 = 2 • 1
a3 = 6 = 3 • 2
a4 = 24 = 4 • 6
- Write in terms of a
a2 = 2 • a1
a3 = 3 • a2
a4 = 4 • a3
- Write a recursion equation
an = nan-1
- Use value of 1st term & recursion equation to write recursive formula
a1 = 1
an = nan-1
percentage recursive formulas
Ex: 650mg of aspirin every 6h; only 26% of aspirin remaining in body by the time of new dose; what happens to amount of aspirin in body if taken several days?
- Write a recursion equation
amount aspirin after nth dose = 26% amount after prev. dose + new dose of 650mg
an = (0.26)(an-1) + 650
- Use a calculator
Enter a1 → 650
Enter recursion equation using ANS for an-1 → .26ANS + 650
Keep pressing Enter
sequence appears to approach limit of about 878
arithmetic sequence
a sequence in which the difference b/w any term & the term before it is a constant
Ex: 2, 4, 6, 8
+2, +2, +2