Ch 24 + 10-11 VB+MO Desc, Coordinization Comples, Nuclear Rxns Flashcards
2(non stationary lone pairs + pi bonds)
Pi electrons
Lewis acids
Accepts electron pairs (transition metals and boron column)
Lewis bases
Donates Electron pairs called Ligands (p block elements usually have lone pairs)
Coordination number
Number of bonds Ligands form
Bidentate Ligands
Oxalate =2 bonds formed and 2- charge
En =2 bonds formed and no charge
Carbanato= CO3 forms 2 bonds 2- charge
Naming coordination complexes 1. 2. 3. 4. 5.
- Link Ligands and metals together. Ligands alphabetically. Metal last (include oxi # at end for metal)
- Ionic compounds with complexes is cation (space) anion
- Anionic Ligands- end with o
- Use Greek prefixes di,Tri, tetra etc. or bis,tris, tetrakis for Ligands that have prefixes in the name
- Anionic metal complexes- add ate to latin word for metal
Bromide
Bromo
Chloride
Chloro
Hydroxide
Hydroxo
Cyanide
Cta I
Nitrite (NO2-)
Nitro
Oxalate (C2O4)2-
Oxalato
Water (no charge)
Aqua
Ammonia (no charge)
Ammine
Carbon monoxide (CO) no charge
Carbonyl
En (no charge)
En
Chromium metal
Chromate
Cobalt metal
Cobaltate
Copper metal
Cuprate
Iron metal
Ferrate
Nickel metal
Nickelate
Platinum metal
Platinate
Zinc metal
Zincate
Geometric isomers
Same atoms same bond but different spatial arrangement
Cis/trans- sets of 2
Mer/fac- sets of 3
To check for optical/chiral/enantimer
If no plane of symmetry or is not super impossible then it is an optical/chiral
VB theory for CC linear
Sp
VB theory for CC for tetrahedral
Sp3 (d10 or d5 config)
VB theory for CC for square planar
dsp2 (d8 config)
VB theory for CC for octahedral
d2sp3 (all partially filled d)
Strong field
Electrons stick together
Short wavelength
Large delta
Weak field
Electrons split up
Small delta
Long wavelength
Halogens and water are
Weak field
Octahedral crystal field
______ _______ dz2,dx2-y2
______ _______ _______ dxy, dyz, dxz
Tetrahedral crystal field
______ _______ ______
\_\_\_\_\_\_ \_\_\_\_\_\_
Simple cubic
CN = 6
Atoms are 1
Body centered
CN=8
Atoms are 2
Face centered
CN=12
Atoms are 4
Mass
atoms(molar mass)(1/ Avogadro’s #)
Alpha decay
4
He
2
Beta decay
0
e
-1
Positron emssion
0
e
+1
Nuclear decay
On products side
0
e
-1
Joules =
Kg(m/s)^2
Binding energy
In kj per mol so
After finding E you have to divide by number of nucleons/atoms
For units that are in days or years or months
Don’t round because you can’t have a part of a year
2(Stationary lone pairs +sigma bonds)
Sigma electrons