Bonding Flashcards
Magnesium sulphate is an ionic compounds
with reference to its bonding explain whether you would expect magnesium sulphate to have a high or low melting point
Magnesium sulphate is an ionic compound so will have a giant ionic lattice structure where the ions are held together by a very strong electrostatic forces these bonds require a lot of energy to break some magnesium sulphate will have a very high melting point
What is sulphate compound ion formula
SO42-
Gives the formula of ammonium
NH4 plus
What effect does electrostatic attraction have on oppositely charged ion
It holds positive and negative ions together
Explain what an ionic lattice is
A regular structure made up of ions
Draw the structure of sodium chloride showing at least 12 ions
Cjck
Explain why ionic compounds conduct electricity when molten
The ions in the liquid are free to move and carry charge
Magnesium oxide is an ionic compound apart from electrical conductor conductivity when molten or dissolved describe to physical properties you would expect magnesium oxide to have
It should have a high melting points and dissolve in water
Hydrogen peroxide dissolves in water state the strongest type of interaction that occurs between molecules of hydrogen peroxide and water
Hydrogen bonding
Explain in terms of electronegativity why the body and boiling points of H2S2 is lower than H202
The electronegativity of S is lower than O
is no hydrogen bonding between H2S2 molecules only Vanderwall’s
States the meaning of the term electronegativity
The power of an atom to withdraw or attract electrons
Suggest why the electronegativity of the elements increase from lithium to fluorine
More protons bigger nuclear charge
State the type of bonding in lithium fluoride explain why a lot of energy is needed to melt a small sample of solid lithium fluoride
Bonding : ionic
Explanation : Strong or many electrostatic attraction between + and - ions
Whys is the bonding nitrogen oxide is covalent rather than ionic
Small electronegativity difference
oxygen forms several different compounds with FluorineSimple molecular suggest the type of crystal shown by OF2
Simple molecular
Write an equation to show how OF2 reacts with steam to form oxygen and hydrogen fluoride
O2 + H2O —> O2 + 2HF
One of these compounds of oxygen and flooring has a relative molecular mass of 70 and contains 54.3% by mass of fluorine calculate the empirical formula and the molecular formula of this compound
Empirical formula : start with % , 54.3% is F so 45.7 is O2
Divide each % by the relative mass of each you should get 2.85 for F
and 2.85 for O
ratio of 1 to 1
so empirical formula is just FO
Molecular formula: as for molecular formula it would be F202 as the molecular mass of that molecule is 70
Ammonia gas readily condenses to form a liquid when cooled
name the strongest attractive force between two ammonia molecules
H bonds
Ammonia reacts with boron trichloride to form a molecule with the following structure
state how the bonds between ammonia and boron trichloride is formed
Electron pair on the ammonia is donated to boron trichloride
ethanedioic acid is a weak acid ethanedioic acid acts initially as a monoprotic acid
use the concept of electronegativity to justify why the acid strengths of ethanedioic and ethanoic acid are different
Both acids contain A carboxylic acid group however in ethanoic acid R=CH3 and ethanedioic acid and carboxylic acid
The oxygen atom in the carboxylic acid group of ethanedioic acid are highly electronegative so draw electrons towards them from the neighbouring carboxylic acid
causes the hydroxyl group to become more polarised
this makes bond fission more likely
so hydrogen ions More likely to dissociate.
in ethanoic acid the CH3 group is not electron drawing so has no effect on hydroxide polarity ethanedioic is therefore a stronger acid than ethanoic acid
A buffer solution is made by adding 6.00 × 10–2 mol of sodium hydroxide to a
solution containing 1.00 × 10–1 mol of ethanedioic acid (H
Assume that the sodium hydroxide reacts as shown in the following equation and that in this buffer solution, the ethanedioic acid behaves as a monoprotic acid.
H2C2O4(aq) + OH–(aq)—->HC2O4–(aq)+H2O(l)
The dissociation constant Ka for ethanedioic acid is 5.89 × 10–2 mol dm–3.
Calculate a value for the pH of the buffer solution.
Give your answer to the appropriate number of significant figures.
Moles of NaOH = Moles of HOOCCOO– formed = 6.00 × 10–2
Moles of HOOCCOOH remaining = 1.00 × 10–1 – 6.00 × 10–2 = 4.00 × 10–2
Ka =[H+][A–]/[HA]
[H+]=Ka ×[HA]/[A–]
[H+]=5.89×10–2 ×(4.00×10–2 /V)/(6.00×10–2 /V)=3.927×10–2
pH = –log10(3.927 ×10–2) = 1.406= 1.41
In a titration, the end point was reached when 25.0 cm3 of an acidified solution containing ethanedioic acid reacted with 20.20 cm3 of 2.00 ×10–2 mol dm–3 potassium manganate(VII) solution.
Deduce an equation for the reaction that occurs and use it to calculate the original concentration of the ethanedioic acid solution.
Equation ……………………………………………………………………………………………
Original concentration = …………………………. mol dm-3
5H2C2O4 + 6H+ + 2MnO4– 2Mn2+ + 10CO2 + 8H2O
OR 5C2O42– + 16H+ + 2MnO4– 2Mn2+ + 10CO2 + 8H2O Page 7
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Stage 1: difference in structure of the two acids • The acids are of the form RCOOH
• but in ethanoic acid R = CH
• whilst in ethanedioic acid R = COOH
Stage 2: the inductive effect
• The unionised COOH group contains two very electronegative oxygen
atoms
• therefore has a negative inductive (electron withdrawing)effect
• The CH 3
group has a positive inductive (electron pushing) effect
3
(c)
PhysicsAndMathsTutor.com
Moles of KMnO4 = 20.2 × 2.00 × 10–2 / 1000 = 4.04 × 10–4
Moles of H2C2O4 = 5 / 2 × 4.04 × 10–4 = 1.01 × 10–3
Concentration = moles / volume (in dm3) =1.01×10–3 ×1000/25=4.04×10–2 (moldm–3)
If 1:1 ratio or incorrect ratio used, M2 and M4 can be scored
Silicon dioxide (SiO2) has a crystal structure similar to diamond.
Give the name of the type of crystal structure shown by silicone dioxide
Suggest why silicon dioxide does not conduct electricity when molten. ………………………………………………………………………………………………………… ………………………………………………………………………………………………………… …………………………………………………………………………………………………………
Silicon dioxide reacts with hydrofluoric acid (HF) to produce hexafluorosilicic acid (H2SiF6) and one other substance.
Write an equation for this reaction.
Giant covalent
No delocalised electrons
SiO2 + 6HF H2SiF6 + 2H2O
Some airbags in cars contain sodium azide (NaN3).
(a)
Sodium azide is made by reacting dinitrogen monoxide gas with sodium amide (NaNH2) as shown by the equation.
2NaNH2 + N2O NaN3 + NaOH + NH3
Calculate the mass of sodium amide needed to obtain 550 g of sodium azide, assuming there is a 95.0% yield of sodium azide.
Give your answer to 3 significant figures.
……………………………………………………………………..
550 x 100/95
So 100% would b 8.46 x 100/95 = 8.91 moles of NaN3
Then M3 Moles NaNH2 = 8.91 × 2 = ( 17.8(2) moles)
M4 mass NaNH2 = 17.8(2) × 39 M5 693 (g)