Bonding Flashcards
What are valence electrons?
How would you quickly find the number of valence electrons, by using the periodic table?
Valence electrons are all electrons in the outermost energy level.
Ex: in Nitrogen we have 1s22s22p3, n=2 is the outermost energy level. Add all of those electrons (2 from the s, 3 from the p) to get valence = 5.
Valence electron number can quickly be read off of the periodic table as it will be the column number (counting from the left) that the element is in.
Ex: Nitrogen is in the 5th column from the left, so it must have 5 valence shell electrons.
What are Valence Electrons, and how do they affect an atom’s chemistry?
Valence Electrons are the electrons in the atom’s highest energy subshells. They are chemically relevant because they are the electrons that form chemical bonds.
To find the number of valence electrons, simply count across from the left edge of the Periodic Table to the element in question.
What is the difference in valence electrons for:
Oxygen (O) vs Silicon (Si)?
Oxygen has 6 electrons in the outermost energy level (2 in the 2s and 4 in the 2p).
Silicon has more electrons total, but it only has 4 valence electrons (2 in the 3s and 2 in the 3p).
Define:
The octet rule
The octet rule states that atoms desire eight electrons in their valence shells, as this gives them the electron configuration of a noble gas.
An atom will usually have to bond with other atoms to aquire this electron structure.
According to energy rules, what will cause two atoms to form a bond between them?
Chemical bonds form because they lower the potential energy of the electron clouds. Electrons are shared between atoms across the bond, allowing the final state to be more stable than the two were alone.
In general: bonding proceeds so that as many atoms as possible gain a full octet of valence shell electrons.
What are the three strengths of bond possible between atoms?
Give examples of each.
- single bond: one pair of electrons is shared between two atoms
Ex: O-H bond in H2O, or C-H bond in CH4 - double bond: two pairs of electrons are shared between atoms
Ex: O=O bonds in O2, or C=O bonds in CO2 - triple bond: three pairs of electrons are shared between atoms
Ex: N≡N bonds in N2, or C≡N bonds in CNOH
What are the three noteable exceptions to the octet rule?
- odd-electron species. Molecules which have an odd total number of electrons to distribute (hence some atom will come up lacking)
- incomplete octets. Atoms where attaining a full octet would require too many bonds. H, He, Li, Be, B are all considered incomplete octet species due to the high number of electrons they would need.
- expanded octets. Atoms in period 3 or higher that expand to fill their d-block. The term is a misnomer, as this is no longer an octet, but will have 10, 12, or 14 electrons depending on the central atom being bonded.
Why does Nitrogen not succeed in getting a full octet in Nitric Oxide (NO)?
The most electronegative atom will always gain a full octet first.
Nitric Oxide has 11 valence electrons. Oxygen is more electronegative, so will end up with a full octet (two sets of lone e-pairs and a double bond with N). Nitrogen will be left with 3 lone electrons (and two bonds), as it is less electronegative, for a total of 7 electrons.
Why will it be unlikely for Li to ever attain a full octet?
Lithium has only one valence electron. It would need to acquire 7 additional electrons in order to havea full octet. This is statistically (and structurally) unlikely.
H, He, Li, Be, B are all elements that will from incomplete octets due to the improbability of them acquiring enough electrons.
Why can Phosphorous expand its octet to form 5 bonds to Chlorine in PCl5?
P has expanded all of its electrons into the 3d block, in order to create as many stable bonds with chlorine (and complete chlorine’s octets instead) as possible.
Elements in the third row of the periodic table and beyond often exhibit expanded octets of 10, 12, or 14 electrons. This is due to them expanding into the d-block for greater bonding stability.
Common examples of elements that will expand their octets are P, Cl, S, Xe, and Ar.
What are the three major types of chemical bonds?
- ionic bonds: electrons are transferred from a metal to nonmetal
- covalent bonds: electrons are shared between nonmetals
- metallic bonds: electrons ‘“float” between metals in a lattice
Define and give an example of:
ionic bond
An ionic bond is formed when a metal transfers one or more electrons to a nonmetal. Often on the MCAT this will be column I and II transfering electrons to a halogen.
Ex: The classic example is an “ionic salt” like NaCl. Sodium transfers its electron to chlorine.
How does Coulomb’s law apply to ionic bonds?
Coulomb’s law states that the magnitude of the electrostatic force between two charged particles is directly proportional to the product of the magnitude of each of the charges, and inversely proportional to the square of the distance between the two particles.
This holds for all charged particles, hence can be applied to calculate force between the atoms in an ionic bond.
F ∝ q1*q2 / r2
- q1 and q2: charge magnitude of the atom
- r = distance
If we know that NaCl has a higher Electrostatic force between atoms in its lattice than does KBr, what does that tell us about the strength of the bonds?
NaCl will have stronger bonds between adjacent atoms than KBr, due to the stronger force between atoms.
What would be the result in Force between ions in an ionic compound if we were to 1/2 the distance between adjacent ions?
The Force would be increased by a factor of 4, or quadrupled from the original value.
E ∝ q1*q2 / r2
- q1 and q2: charge magnitude of the atom
- r = distance
Define:
Lattice energy
The lattice energy of an ionic compound is the energy associated with forming a crystalline lattice of the compound from the gaseous ions. This may also be refered to as “heat of formation”.
Note: The value of lattice energy is negative, showing that the formation of an ionic compound is exothermic.
How could we evaluate the Electrostatic energy between ionic bonds?
E ∝ q1*q2 / r
- q1 and q2: charge magnitude of the atom
- r = distance
This holds for all charged particles, hence can be applied to calculate energy between the atoms in an ionic bond.
Note: this value will always be negative, due to the charges always being opposite in an ionic compound.
What will be the result in energy if we double the distance between two atoms in an ionic bond?
The energy will be decreased by a factor of 2, or halved from the initial value. Notice that doubling r in the denominator will effectively be the same as dividing by two.
E ∝ q1*q2 / r
- q1 and q2: charge magnitude of the atom
- r = distance
What type of bond would we expect between atoms in molecules like KBr, CaF2, and LiCl?
These are all ionic compounds, commonly referred to as salts. We expect highly ionic bonds between metals and nonmetals in general.
Classic MCAT examples usually include column I and II bonded with the halogen family.
Define:
covalent bond
A covalent bond forms when a nonmetal bonds with another nonmetal by sharing electrons between them, resulting in an overlap of their electron orbitals.
The image below of methane shows the polar covalent C-H bonds.
What are the three types of covalent bonds?
- polar covalent (electrons are held more closely by the higher electronegative species)
- non-polar covalent bond (electrons are perfectly shared between atoms of the same element)
- coordinate covalent bond (molecules share electrons for greater net stability)
What is the difference in bond strength between molecules in an ionic-bonded compound vs a covalent-bonded compound?
What will this do to melting point and boiling point?
Ionic bonds create stronger intermolecular forces than pure covalent bonds. This is due to ionic bonds being extremely polar (more so than ANY covalent bond, by definition), hence it will attract its substituent molecules more strongly.
The melting point and boiling point will both be higher for the ionic compount, since it will require more energy to pull the molecules apart.
Define and give examples of:
Nonpolar (or pure) covalent bond
In a nonpolar covalent bond, both atoms are the same element hence the electron pair is shared equally. On the MCAT, pure covalent can only be the following diatomics: Br2, I2, N2, Cl2, H2, O2, F2.
(BrINClHOF)
Note: though some Chemistry texts will also include bonds like the C-H bond (since it only measures .4 on the Pauling scale), this is clearly still polar since electrons favor Carbon over Hydrogen.
Define and give examples of:
Polar covalent bond
In a polar covalent bond, the electron pair is pulled closer to the more electronegative atom. The result of this is a bond dipole (one end positive, one end negative), hence where we get the term “polar”.
The atom that is more electronegative has a partial negative charge and the atom that is less electronegative has a partial positive charge.
Any bond between different elements will create some value of bond dipole. While some are rather small dipoles (C-H bond dipole is very slight) the only cases where a bond dipole will NOT form are the diatomics (Br2, I2, N2, Cl2, H2, O2, F2).