BELONIO Flashcards
Amount of moisture in the grains
expressed as a percentage of the
total weight of the samples.
a. Moisture content dry basis
b. Moisture content wet basis
c. Moisture content
d. All of the above
b. Moisture content wet basis
Amount of moisture in the grains
expressed as a percentage of the
weight of dry matter.
a. Moisture content dry basis
b. Moisture content wet basis
c. Moisture content
d. None of the above
a. Moisture content dry basis
Moisture meter that determines
the moisture content of the product
based on the ability of the current to
pass through the material.
a. Capacitance-type moisture
meter
b. Resistance-type meter
c. Infrared moisture meter
d. All of the above
a. Capacitance-type moisture
meter
When the amount of water in a
product is determined based on its dry
matter content, the moisture content is
expressed in ____.
a. wet basis
b. dry basis
c. semi wet basis
d. None of the above
b. dry basis
A product has 25% moisture
content expressed in dry basis. What
is the percentage moisture content of
the product in wet basis?
a. 20%
b. 22%
c. 26%
d. None of the abov
a. 20%
MCwb = 25%/(100% + 25%)
MCwb = 20%
Method of measuring the moisture
content of the product by direct
extraction of water.
a. Primary method
b. Secondary method
c. Tertiary method
d. None of the above
a. Primary method
Which of the following is
considered primary method in
determining moisture content?
a. Oven method
b. Distillation method
c. Infrared method
d. All of the above
e. None of the above
d. All of the above
If a product has 12% moisture
content expressed in wet basis, the
equivalent percentage moisture
content in dry basis is ____.
a. 13.6%
b. 16.3%
c. 13.4%
d. None of the above
a. 13.6%
MCdb = 12%/(100% - 12%)
MCdb = 13.63%
Expression of moisture content
commonly used in commercial scale.
a. Moisture content wet basis
b. Moisture content dry basis
c. Moisture content
d. All of the above
a. Moisture content wet basis
Which of the following is
considered secondary method in
determining moisture content?
a. Electrical-resistance method
b. Electrical-capacitance method
c. Chemical method
d. Hygrometric method
e. All of the above
f. None of the above
e. All of the above
Moisture found on the surface of
the material.
a. Unbound water (Free moisture)
b. Bound water
c. Chemically bound
d. All of the above
a. Unbound water (Free moisture)
Important index to determine
whether the paddy is ready for
harvesting, storage or milling.
a. Color
b. Moisture content
c. Hardness
d. None of the above
b. Moisture content
Moisture inside the tissue of a
material that can only be removed by
heating or reducing the vapor pressure
within the material.
a. Chemically-bound moisture
b. Bound moisture
c. Unbound
d. All of the above
b. Bound moisture
Difficult-to-remove moisture from
the product that requires other method
than heating in order to remove it.
a. Chemically-bound moisture
b. Bound moisture
c. Free moisture
d. All of the above
a. Chemically-bound moisture
Plot or graph representing the
equilibrium moisture content of grains
at different relative humidity but with
constant temperature.
a. Isothermal graph
b. Sorption isotherms
c. Isothermal humidity
d. None of the above
b. Sorption isotherms
Device usually used in calibrating
resistance- and capacitor-type
moisture meters.
a. Oven
b. Distillation
c. Infrared
d. All of the abov
a. Oven
Device used by the industry in
determining moisture content of
grains.
a. Oven
b. Electrical resistance- and
capacitance-type meter
c. Infrared moisture meter
d. All of the above
b. Electrical resistance- and
capacitance-type meter
If 20 kg of water is to be
removed from 110kg paddy, what is
the percentage moisture content of
the paddy in wet basis?
a. 14.5%
b. 16.9%
c. 18.18%
d. None of the above
c. 18.18%
MCw = 1 - [(110kg - 20kg)/110kg]
MCw = 18.18%
What is the percentage moisture
content of the paddy in Item 18 when
expressed in dry basis?
a. 16.4%
b. 19.9%
c. 22.2%
d. None of the above
c. 22.2%
MCd = 20kg/(110kg - 20kg)
MCd = 22.22%
Determine the amount of moisture
that can be removed from 9 tons of
paddy with 24% initial moisture
content dried to 14%.
a. 1.05 tons
b. 1.26 tons
c. 1.57 tons
a. 1.05 tons
Wf = [9 tons(1 - 0.24)/(1 - 0.14) = 7.95 tons
WL = Wi - Wf = 9 tons - 7.95 tons
WL = 1.05 tons
- What is the amount of moisture to
be removed from a material with
14.5% moisture content and 76 kg dry
matter weight?
a. 10.45 kg
b. 12.89 kg
c. 14.32 kg
d. None of the above
b. 12.89 kg
Wmr = 0.145(Wmr + 76kg)
0.855 Wmr = 11.02 kg
Wmr = 11.02 kg/0.855
Wmr = 12.89 kg
What is the percentage
moisture content of paddy in Item
21 when expressed in dry basis?
a. 16.95%
b. 13.23%
c. 15.67%
d. None of the abov
a. 16.95%