Atomic structure - Ionisation Energies Flashcards

1
Q

What is first ionisation energy

A

Energy needed to remove one electron from each atom in one mole of gaseous atoms to for, 1 mol of gaseous 1+ ions

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2
Q

How do your write first ionisation energy

A

Element =Element+ + e-

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3
Q

What is second ionisation energy

A

Energy needed to remove 1 electron from each ion in one lobe of gaseous 1+ ions to form 1 mol of gaseous 2+ ions

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4
Q

What are the factors affecting ionisation energy

A

Nuclear charge
Distance from nucleus
Shielding

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5
Q

How does nuclear charge affect ionisation energy

A

The higher the nuclear charge the higher the ionisation energy because the greater the positive charge of the nucleus means more attraction between nucleus and outer electrons

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6
Q

How does atomic radius affect ionisation energy

A

The higher the atom of radius the lower the IE. This is because a higher atomic radius means the outer electrons are further from the nucleus and there is less attraction

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7
Q

How does shielding affect ionisation energy

A

The more shielding the lower the IE as there is less attraction

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8
Q

What does a high ionisation energy mean

A

A high attraction between outer electron and nucleus so more energy is needed to remove the electron

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9
Q

How do you write the equation for second ionisation energy

A

Element + = Element 2* + e-

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10
Q

What is the general formula for IE

A

X(n-1) = X(n+) + e-

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11
Q

What is the trend in first IE down a group

A

It decreases

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12
Q

What is the trend for IE along a period

A

Increase

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13
Q

Why does ionisation energy decrease down group 2

A

As you go down group 2 each element has an extra electron shell so more shells means more shielding and less attraction as the outer electrons are further away from the nucleus

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14
Q

Why does IE generally increase across period 3

A

The number of protons increased which means stronger nuclear attraction

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15
Q

Why is there a drop in ionisation energy between Mg and Al in the elements of period 3

A

Aluminiums outer electron is in 3p orbital rather then 3s and 3p has higher energy than 3s so it is further from the nucleus

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16
Q

Why is there a drop in IE between P and S

A

Due to election repulsion
In P the electron is being removed from a slightly occupied orbital but in sulfur the electron is being removed from a orbital with 2 electrons and so the repulsion there means it is easier to remove the electron from the orbital as it is shared