Atomic structure Flashcards

1
Q

Define Atomic Number

A

Equal to the number of protons

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2
Q

Define mass number

A

Equal to the number of protons and neutrons combined

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3
Q

define isotopes

A

Same number of protons, different number of neutrons

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4
Q

why do isotopes have the same chemical property

A

They have the same electron configuration

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5
Q

What did Rutherford’s model prove

A

Atom mostly made up of empty space, most passed through. Alpha particles have positive charge. Atom should have a small positive nucleus

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6
Q

What did the Bohr model state

A

A small positive nucleus with electrons surrounded in shells. Neutrons in the nucleus

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7
Q

Define Ionisation energy

A

The amount of energy required to remove one mole of electrons from a mole of atoms in a gas state. * always include the state symbol (g)

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8
Q

Factors that influence IE

A
  • Nuclear charge, number of protons- more protons, stronger attraction to nucleus, requires more energy
  • Distance from the nucleus- Electron closer to nucleus, stronger attraction, more energy required.
  • Shielding- Electron on shell further from the nucleus- more shielding, weaker attraction. Less energy to remove.
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9
Q

Trend in IE across the group: why is second IE high then first? include deviations

A

Why- the attraction between the electron and protons becomes stronger as there a less electrons being attracted by the same number of protons.- 2nd electron is removed from an ion that already has a positive charge
Trends: general increase, same shielding, more protons.
Deviations P2: Electron to be removed from Be is from a 2s sub-shell, from B it is in a 2p sub-shell. 2p is higher, less energy required to remove.
Electron to be removed from N is unpaired, O is paired. Electron pairs repel, requires less energy to remove.
P3: electron to be removed from Mg is 3s, Al is 3p. 3p= higher sub-shell, requires less energy to remove.
Electron to be removed from P is unpaired, S is paired. Electron pairs repel, Sulfur has lower IE due to less energy being required to move

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10
Q

Change in atom size

A

factors affecting- same shielding, more protons so greater nuclear attraction on outer electrons- smaller ion
more shielding, further from the nucleus, weaker nuclear attraction, more shielding.

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11
Q

Electron configuration

A

Cr: 1s2 2s2 2p6 3s2 3p6 4s2 3d9
Cu: 1s2 2s2 2p6 3s2 3p6 4s1 3d10

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12
Q

trends in IE down the group, atomic size trend across the period

A

Atomic radius increases, the number of shells increases so amount of shielding increases.
Atomic radius gets smaller, nuclear charge increases, greater attraction between electrons and nucleus, shielding remains the same.

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13
Q

TOF spectrum

A

Vacuum to prevent particles colliding with air.
acceleration: positive ions attracted to a negatively charged plate and accelerate towards it. Once accelerated all have the same KE.
Ion Drift- particles separate based on their masses.
Detection: generates a current once hits the detector- generating a current proportional to the number type of each ion.

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14
Q

Why are the sample particles ionised?

A

So they can be accelerated towards the negatively charged pate and generate a current once hit the detector

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15
Q

How is the ion accelerated? and how are they separated? How are they detected?

A

Positive ions are attracted to negatively charged plate, all have the same kinetic energy.
Ions travelling at higher speeds reach the detector first.
detection: Each ion hits the detector, gains an electron, generated a current which is proportional to abundance of ion.

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16
Q

How to calculate KE

A

Ke= 1/2 x mass x v2

17
Q

How to calculate mass

A

KE/0.5V2

18
Q

How to calculate V2

A

Ke/0.5M