Aromatics Flashcards

1
Q

Describe the verified structure of benzene

A

C6H6

circle = delocalised electrons

the bonds are somewhere between single to double bond strength due to the delocalised electrons, which forms regions of electron density above and below the ring

all bonds are equal length

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2
Q

Describe Kekule’s benzene structure and the problems with them

A
  • alternating single and double bonds (single bonds are longer than double bonds) = hexagon

Problems:

  • Since Benzene is hexagonal all the C-C bonds should be the same length
  • Benzene doesn’t undergo electrophilic addition reactions, but Kekule’s structure suggests that it should
  • kekule = -360, benzene= -208,the enthalpy of hydrogenation is 152 kJ mol-1 less than expected in this structure. Benzene is more stable since it is less exothermic, this suggests that the delocalised pi bonds in benzene are stronger, so the bonds being broken value is larger than Kekule (elower energy release during the reaction implies that the bonds in benzene are stronger and more difficult to break, making it a more stable compound.)
  • alternating single and double bonds (single bonds are longer than double bonds) = hexagon
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3
Q

What type of reactions can Benzene undergo and why? (mention the ones it can’t do)

A
  • very stable so it cant undergo electrophilic addition as this would destroy the delocalised rings of electrons
  • cant do nucleophilic reactions because nucleophiles are attracted to regions of strong positive charge and benzenes have electron-rich areas due to its delocalised electrons
  • ## it can do electrophilic substitution= due to the delocalised electrons creating region of high electron density attracting electron-deficient compounds/ electrophiles
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4
Q

What are the two different electrophilic substitution reactions that aromatic compounds can undergo?

A

Friedel-Crafts acylation and nitration

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5
Q

What are the physical properties of arenes?

A
  • high melting and boiling point due to having flat, hexagonal molecules pack together well in the solid state. So, they are harder to separate.
  • colourless liquid
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6
Q

What is delocalisation energy?

A

the extra energy provided by the ring orbitals of the delocalized electrons, from the “pi” bonds, that are spread out over the whole covalently bonded molecule

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7
Q

What are the conditions for nitration?

A

Warm benzene at 50 degrees with concentrated nitric and sulfuric acids (which is a catalyst)

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8
Q

Write equations showing how the nitronium ion,electrophile, is made

A
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9
Q

What is the mechanism for nitration?

A
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10
Q

What are the uses for nitrated arenes?

A
  • TNT
  • reduced to make primary amides (azo dyes)
  • making hair conditioner
    -making quaternary ammonium salts
  • making fabric softener
  • making detergents
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11
Q

What are the conditions for Friedel-crafts acylation?

A

reflux

alcl3 catalyst

non-aqueous solvent (like dry ether)

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12
Q

Why is AlCl3 used as a catalyst in acylation

A
  • AlCl3accepts lone pair of electrons from acyl chloride
  • As lone pair of electrons is pulled away, polarisation in acyl chloride increases and it forms a carbocation
  • Makes it stronger electrophile and gives it a strong enough charge to react with benzene ring
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13
Q

Draw the reaction between AlCl3 and acyl chloride

A
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14
Q

Draw and describe the Friedel-crafts Acylation with acyl chloride

A
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15
Q

Draw and describe the Friedel-crafts Acylation with an acid anhydride

A
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16
Q

Explain the bonding in and the shape of a benzene molecule

A
  • each carbon atom has three bonds with the spare electrons forming a delocalised pi system
  • benzene is planar in shape and hexagonal. Each carbon-carbon bond is of equal length
17
Q

Why must Friedel-Craft’s acylation be free from water?

A

because the aluminium chloride reacts vigorously with water, spoiling the production of the electrophile

18
Q

State, in terms of its bonding, why benzene is more stable than cyclohexa−1,3,5−triene.

A

electrons delocalised

lack of delocalization in cyohexa-1,3,5-triene means that the electrons are localized on the individual carbon-carbon double bonds, leading to a higher energy state compared to benzene.

The delocalization of electrons in benzene leads to a more uniform distribution of electron density around the ring, which stabilizes the molecule.

19
Q

The enthalpy of hydrogenation of cyclohexa−1,4−diene is more negative (exothermic) than that of cyclohexa−1,3−diene. Explain why in terms of the bonding in these two dienes.

A
  • Proximity − for 1,3 C=C bonds are close together
  • Delocalisation − for 1,3 some delocalisation/ some overlap of electrons, π clouds or p orbitals
  • some extra stability for the 1,3- isomer