Aromatic Flashcards

1
Q

Describe the shape of, and bonding in, a molecule of benzene

A
  • Planar (Flat) ring of six C atoms
  • Each carbon atom is bonded to one hydrogen atom and two other carbon atoms.
  • The angle between all the bonds is 120.
  • The unused 4th C electron is in the p orbitals, perpendicular to the plane of the ring
  • The p orbitals overlap and the 6 electrons move freely within the overlapping orbitals
  • there are delocalised electrons above and below the plane of benzene
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2
Q

Explain why benzene does not readily undergo addition reactions

A
  • -The delocalised electrons give stability to the benzene molecule that normal “double bonds” do not.
  • -Addition reactions break the delocalised ring, so are not favoured.
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3
Q

Explain why phenylamine is a weaker base than ethylamine

A
  • The lone pair
  • on the N is spread into the ring
  • So it is less available for bonding with a proton
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4
Q

Why does methylbenzene undergo faster substitution reactions than benzene

A
  • 1 methyl group has (positive) inductive effect as it increases electron density on benzene ring
  • 2 this makes the electrophile more attracted, making the Benzene ring a better nucleophile
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5
Q

Why doesn’t benzene undergo nuc sub

A
  • Delocalised structure repels nucleophile
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6
Q

Explain the stability of benzene compared to hypothetical cyclohexatriene

  • ΔH for cyclohexene= -120
  • ΔH for Benzene= -208
A
  • Benzene is more stable than cyclohexatriene
  • Expected ΔH hydrogenation of triene is 3(–120) = –360 kJ mol
  • Actual ΔH hydrogenation is 152 kJ mol-1 different from expected
  • This means benzene is lower in energy
  • Difference is due to delocalisation
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