Aromatic Flashcards
1
Q
Describe the shape of, and bonding in, a molecule of benzene
A
- Planar (Flat) ring of six C atoms
- Each carbon atom is bonded to one hydrogen atom and two other carbon atoms.
- The angle between all the bonds is 120.
- The unused 4th C electron is in the p orbitals, perpendicular to the plane of the ring
- The p orbitals overlap and the 6 electrons move freely within the overlapping orbitals
- there are delocalised electrons above and below the plane of benzene
2
Q
Explain why benzene does not readily undergo addition reactions
A
- -The delocalised electrons give stability to the benzene molecule that normal “double bonds” do not.
- -Addition reactions break the delocalised ring, so are not favoured.
3
Q
Explain why phenylamine is a weaker base than ethylamine
A
- The lone pair
- on the N is spread into the ring
- So it is less available for bonding with a proton
4
Q
Why does methylbenzene undergo faster substitution reactions than benzene
A
- 1 methyl group has (positive) inductive effect as it increases electron density on benzene ring
- 2 this makes the electrophile more attracted, making the Benzene ring a better nucleophile
5
Q
Why doesn’t benzene undergo nuc sub
A
- Delocalised structure repels nucleophile
6
Q
Explain the stability of benzene compared to hypothetical cyclohexatriene
- ΔH for cyclohexene= -120
- ΔH for Benzene= -208
A
- Benzene is more stable than cyclohexatriene
- Expected ΔH hydrogenation of triene is 3(–120) = –360 kJ mol
- Actual ΔH hydrogenation is 152 kJ mol-1 different from expected
- This means benzene is lower in energy
- Difference is due to delocalisation