Alkanes. Flashcards

1
Q

What are alkanes?

A

CnH2n+2.
Saturated hydrocarbons.
Single C-C bonds and C-H bonds as sigma bonds.

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2
Q

Bonding in alkanes.

A

Only C and H atoms joined by single covalent bonds.
Each C atom joined to 4 other atoms by single covalent bonds-sigma bonds(overlap of 2 orbitals, one from each bonding atom).
Each overlapping orbital has one electron.
Sigma bond has 2 electrons shared between bonding atoms.
Each C atom has 4 sigma bonds(C-C or C-H).
Sigma bond on line directly between bonding atoms.

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3
Q

Explanation of the shape of alkanes.

A

Each C atom surrounded by 4 electron pairs in 4 sigma bonds.
Repulsion between electron pairs=tetrahedral shape around each C atom.
Bond angle=109.5 degrees.
Sigma bond acts as axis which atoms can rotate freely.
Non-rigid shapes.
Free rotation of sigma bond.

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4
Q

Explanation of varying boiling points of alkanes.

A

Boiling points increase as alkanes chain length increases.
Higher chain length=greater IMFs(london forces)= more energy needed to break apart=higher boiling point.

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5
Q

Effect of chain length on boiling point.

A

London forces act between molecules that are close in surface contact.
Higher chain length=larger molecule surface area=more surface contact possible between molecules=London forces between molecules greater=more energy needed to overcome forces.

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6
Q

Effect of branching on boiling point.

A

Branched isomers have a lower boiling point than straight-chained isomers.
Fewer surface points of contact in branched alkanes=fewer/weaker London forces.
Branches get in way and prevent branched molecules being as close as straight chained ones, decreasing IMFs even more(London forces).

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7
Q

Reasons for the low reactivity of alkanes.

A

C-C and C-H sigma bonds are very strong.
C-C bonds are non-polar.
Electronegativity of C and H is so similar that the C-H bond is considered non-polar.
High bond enthalpy of bonds present= not often enough energy to react.

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8
Q

Complete combustion of alkanes.

A

Burn completely to form CO2 and water.
In plentiful oxygen supply.
Used as fuels.
Readily available. easy to transport, don’t release toxic products.

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9
Q

Incomplete combustion of alkanes.

A

Limited O2, not enough for complete combustion.
H atoms are oxidised to water.
Combustion of carbon may be incomplete=toxic CO or soot.

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10
Q

Reactions of alkanes w/ halogens.

A

In presence of UV.
Provides initial energy needed for a reaction to take place.
Substitution reaction.

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11
Q

Mechanism for the bromination of alkanes.

A

Radical substitution.
Step1:initiation.
Covalent bond in Br broken by homolytic fission.
Each Br takes of electron from the pair=2 highly reactive Br radicals.
Full stop=radical.
Br-Br–>Br.+Br.
Step2:propagation.
2 steps=chain reaction.
1:CH4+Br.–>.CH3+HBr
2:.CH3+Br2–>CH3Br+Br.
Br radical reacts w/ C-H in methane=methyl radical(.CH3) and hydrogen bromide HBr.
Each methyl radical reacts w/ another Br molecule=bromomethane+new Br radical.

New Br radical reacts w/ CH4 molecule like prop step 1 and 2 steps continue to cycle through in chain reaction.
Continue until reactants used up/termination.
Step 3:termination.
2 radicals collide=molecule w/ all electrons paired.
Br.+.Br–>Br2 or
.CH3+.CH3–>C2H6 or
.CH3+.Br–>CH3Br.
When collide and react, both radicals removed from reaction mixture =stop reaction.

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12
Q

Limitations of radical substitution in organic synthesis.

A

Further substitution-
Another Br radical can collide w/ bromomethane molecule=subs another H molecule–>dibromomethane.
Can continue until all H have been subbed.
Substitution at different points in the carbon chain-
If carbon chain is longer, get a mix of monosubbed isomers by substitutions at diff pints of chain= different isomers formed.

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13
Q
A
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