Alkane And Alkene Flashcards

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1
Q

Free radical substitution of alkane
Reagent :
Condition :
Product :

A
R : chlorine (Cl2) or bromine (Br2) 
C : UV light
Product : depends
1. Remove H
2. Add Cl
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2
Q

Combustion of alkane

A

R: excess Oxygen (O2)
C: no condition
Product : CO2 and water

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3
Q

Cracking of alkane

  1. Thermal cracking
  2. Catalytic cracking
A
1. Thermal cracking
NO reagent
Conditon : high temp - (600 - 900)
2. Catalytic cracking
Condition : presence of catalyst ( silica or alumina)
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4
Q

Hydrogenation of ALKENE

A

Reagent : hydrogen
Condition : 1. Nickel ( 180)
2. Platinum and palladium ( room temp)

Product : Alkane

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5
Q

Halogenation of ALKENE

A

Reagent : halogen in CCl4
Condition : room temp
Product : dihaloalkane

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6
Q

Hydrohalogenation of ALKENE

A

Reagent : HCl or HBr or HI
C: room temperature and AlCl3 / AlBr3 / AlI3
Product : haloalkane
Remember this need to use Markonikov rule

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7
Q

Hydration of Alkene

A

Reagent : H2O
Condition : H3PO4, 300, 60atm
Product : alcohol

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8
Q

Addition of concentrated sulphuric acid

A

Reagent : concentrated H2SO4
Condition : Room temp
Product : Alcohol

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9
Q

Combustion of alkene

A

Reagent : O2

Product : CO2 and H2O

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10
Q

Addition of bromine water to alkene

A

Reagent : BrOH
Condition : room temp
Product : break double bond
Add OH and Br

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11
Q

Mild oxidation of alkene

A

Reagent : no
Condition : cold acidic or alkaline KMnO4
Product : diols

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12
Q

Vigorous oxidation of alkene

A

Reagent : no
Condition : alkene reflux or heated with acidified KMnO4
Product : ketone or aldehyde

If got one C at terminal will produce CO2 and H2O

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13
Q

Catalytic oxidation of alkene

A

Reagent : 1. O2
2. H2O
Condition :1. silver catalyst
200 to 300
2. H+ (acid hydrolysis)
Product : 1. One O between the double bond
2. Two OH

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14
Q

Ozonolysis of alkene

A

Reagent : O3, ozone
Condition : room temp
Product : ketone or aldehyde

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15
Q

Addition Polymerisation of alkene

A

Double bond become single

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16
Q

Mechanism of alkene

A

Step 1 : Attack of electrophile on the pie element of C=C to form a carbonium ion which is unstable

Step 2 :Carbonium ion accepts a nucleophile to form a stable addition product.