Alcohols Flashcards
Define Hydrolysis
Decomposition of a compound by reaction with water.
Define Alkaline Hydrolysis
Hydrolysis: splitting compound with elements of water, Alkaline: relating to an alkali/alkali metal/base (pH>7) Alkali metals are the first column Li, Na, K, etc
Define Reagent
Substance used in a chemical reaction to detect, measure, examine or produce other substances
What is formed from the alkaline hydrolysis of a halogenalkane?
An Alcohol (OH replaces the Halogen via Nucleophilic Substitution)
What is formed from adding NaOH(aq) and heat to a Halogenalkane?
An Alcohol (OH replaces the Halogen via Nucleophilic Substitution)
What is formed from Nucleophilic Substitution of a Halogenalkane?
An Alcohol (OH replaces the Halogen via Nucleophilic Substitution)
An alcohol is formed using NaOH(aq) and heat from what?
A Halogenalkane (OH replaces the Halogen via Nucleophilic Substitution)
An Alcohol is formed using Nucleophilic Substitution from what?
A Halogenalkane (OH replaces the Halogen via Nucleophilic Substitution)
What mechanism occurs in the alkaline hydrolysis of Halogenalkane?
Nucleophilic Substitution to form an Alcohol
What mechanism occurs when NaOH(aq) and heat are added to a Haolgenalkane?
Nucleophilic Substitution occurs to form an Alcohol
Write a balanced equation and name all reagents and conditions to form an Alcohol from a Halogenalkane
CH3CH2Br + OH- ->
CH3CH2OH + Br-
Reagent: NaOH(aq)
Condition: Heat
Define Reduction
A half reaction in which a chemical species decreases it’s oxidation number (usually by electron gain)
Define Reducing Agent
A Reducing Agent donates electrons and is itself oxidised
What are the reagents and conditions for the formation of alcohols from carbonyls?
Just a Reducing Agent: NaBH4
NaBH4 is used to form a Secondary Alcohol from what?
A Ketone is reduced by NaBH4 to form a Secondary Alcohol
NaBH4 is used to form a Primary Alcohol from what?
An Aldehyde is reduced by NaBH4 to form a Primary Alcohol
A Carbonyl is treated with NaBH4 to form what?
Either a Primary or a Secondary Alcohol depending on whether the Carbonyl is an Aldehyde or Ketone respectively.
A Secondary Alcohol will be formed from the reduction of what?
Only a Ketone forms a Secondary Alcohol by reduction (Haloalkanes can form them by Hydrolyis) Both Aldehydes and Carboxylic Acids reduce to form a Primary Alcohol
NaBH4 is used to form a Primary Alcohol from what?
An Aldehyde is reduced by NaBH4
What are the reagents and conditions to form an Alcohol from a Carboxylic Acid?
LiAlH4 in Dry Ether acts as a Reducing Agent on the Carboxylic acid forming a Primary Alcohol
(NaBH4 does not work, as an even stronger reducing agent is needed)
LiAlH4 with a Carboxylic acid forms what?
A Primary Alcohol is the result of reduction by the LiAlH4 of the Acid
An Alcohol is formed with LiAlH4 from what?
A Carboxylic Acid is reduced by LiAlH4 to form a Primary Alcohol
How many ways are the to form an Alcohol?
Five Ways: Alkaline Hydrolysis of a Haloalkane Reduction of an Aldehyde (But not a Ketone) Reduction of a Carboxylic Acid Electrophilic addition from an alkene Diazotisation of an amine
How can a Primary Alcohol be formed?
Five Ways: Alkaline Hydrolysis of a Haloalkane Reduction of a Carbonyl Reduction of a Carboxylic Acid Electrophilic addition from an alkene Diazotisation of an amine
How can a Secondary Alcohol be formed?
Two Ways:
Alkaline Hydrolysis of a Haloalkane
Reduction of a Ketone
(But not an Aldehyde)
How can a Tertiary Alcohol be formed?
Alkaline Hydrolysis of a Haloalkane is the only way
The Carbon attached to the Halogen has to have 3 R groups for this to occur
Draw Alkaline Hydrolysis of a Halogen Alkane
Br= any halogen R= carbon chain/H group
C-Br have (d+) and (-) respectively, C has 3 other R groups, HO- curvy-> C opposite to Br(d-), from C-Br bond curvy-> Br(d-), -------Across the Arrow------- Intermediate both dotted bond, All in straight brackets (-) sign -------Across the Arrow------- Br- formed separately OH bonded opposite Br original
Draw formation of Alcohol from Haloalkane
Br= any halogen R= carbon chain/H group
C-Br have (d+) and (-) respectively, C has 3 other R groups, HO- curvy-> C opposite to Br(d-), from C-Br bond curvy-> Br(d-), -------Across the Arrow------- Intermediate both dotted bond, All in straight brackets (-) sign -------Across the Arrow------- Br- formed separately OH bonded opposite Br original
Draw Haloalkane reacting woth NaOH(aq) in heat
Br= any halogen R= carbon chain/H group
C-Br have (d+) and (-) respectively, C has 3 other R groups, HO- curvy-> C opposite to Br(d-), from C-Br bond curvy-> Br(d-), -------Across the Arrow------- Intermediate both dotted bond, All in straight brackets (-) sign -------Across the Arrow------- Br- formed separately OH bonded opposite Br original
Draw formation of Alcohol using Nucleophilic Substitution Mechanism
Br= any halogen R= carbon chain/H group
C-Br have (d+) and (-) respectively, C has 3 other R groups, HO- curvy-> C opposite to Br(d-), from C-Br bond curvy-> Br(d-), -------Across the Arrow------- Intermediate both dotted bond, All in straight brackets (-) sign -------Across the Arrow------- Br- formed separately OH bonded opposite Br original
NaOH(aq) and heat are use to form an alcohol, draw this.
Br= any halogen R= carbon chain/H group
C-Br have (d+) and (-) respectively, C has 3 other R groups, HO- curvy-> C opposite to Br(d-), from C-Br bond curvy-> Br(d-), -------Across the Arrow------- Intermediate both dotted bond, All in straight brackets (-) sign -------Across the Arrow------- Br- formed separately OH bonded opposite Br original