9 redox Flashcards

1
Q

what is corrosion called in the case of iron and steel

A

rusting

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2
Q

what is rust chemical formula

A

hydrated iron(III) oxide (Fe2O3.xH2O)

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3
Q

what is essential for iron to rust

A

water and oxygen

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4
Q

what increases rate of corrosion

A

salt and acid rain

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5
Q

what is sacrifical protection

A

an alternative method of rust prevention in which blocks of a more reactive metal are attatched to the iron surgace. these mtals are more reactive than iron and will be corroded in preference to it

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6
Q

what is galvanising

A

a layer of more reactive metal coats the object. It has the advantage over other plating methods in that the protection still works even if the zinc layer is badly scratched. The zinc layer can be applied by several different methods. These include electroplating or dipping the object into molten zinc. The bodies of cars are dipped into a bath of molten zinc to form a protective layer.

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7
Q

what type of reaction is a corrosion

A

redox, involving both oxidation and reduction

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8
Q

oxidation is

A

the loss of electrons and increase in oxidation state

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9
Q

reduction is

A

the gain of electrons and decrease in oxidation state

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10
Q

oxidising agent

A

is a species that oxidises another species

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11
Q

a reducing agent is

A

a species that redudces another species

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12
Q

a positive oxidation state means

A

it has lost electron control, and is consequerntly oxidised

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13
Q

a negative oxidation state means

A

it has gained control over electrons, and is consequently reduced

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14
Q

oxidation state is

A

a number which, with its sign, indicates the gain or loss of electron control of an atom during a reaction.

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15
Q

an oxidation number is

A

the numerical part of the oxidation state

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16
Q

Free elements such as O2, Cl2, N2, are assigned an oxidation state of

A

0

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17
Q

the sum of the oxidation states of all the atoms in a compound must be equal to

A

the net charge on the compound

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18
Q

The alkali metals (Li, Na, K, Rb and Cs) in compounds are always assigned an oxidation state of

A

+1.

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19
Q

Fluorine in compounds is always assigned an oxidation state of

A

−1.

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20
Q

The alkaline earth metals (Be, Mg, Ca, Sr, Ba and Ra) and Zn in compounds are always assigned an oxidation state of

A

+2

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21
Q

Hydrogen in compounds is assigned an oxidation state of X except in certain metal hydrides (e.g. NaH), where it is Y

A
X = +1
Y = -1
22
Q

Oxygen in compounds is assigned an oxidation state of X, except in peroxides (e.g. H2O2), where it is Y, or when it is combined with fluorine.

A
X = -2
Y = -1
23
Q

Chlorine in compounds is assigned an oxidation state of WHAT unless

A

-1, unless it is combined with oxygen or fluorine.

24
Q

The charge on a metal ion is the same as

A

its oxidation state, e.g. Zn2+ has an oxidation state of +2.

25
The sum of the oxidation states in a polyatomic ion (such as CO32−) must add up to
the charge on the ion
26
what is the average oxidation state
the average of the oxidation states of the same atom in a compound.
27
what do roman numerals signify
the oxidation state. | For example, in copper(I) oxide, the copper has an oxidation number of +1, whereas in copper(II) oxide, it is +2.
28
when does disporportionation occur
when the same species is oxidised and reduced simultaneously
29
example of disproportionation
catalytic decomposition of hydrogen peroxide 2H2O2 (aq) → 2H2O (l) + O2 (g)
30
what is the winkler method
uses a series of redox reactions to determine the amount of dissolved oxygen in water
31
what is BOD
biological oxygen demand
32
describe what BOD is
a measure of the dissolved oxygen (ppm) required to decompose the organic matter in was over a set period of time, usually five days
33
how is BOD measured
a measured sample of water is then incubated in the dark at a fixed temperature for five days while microorganisms in the water oxidise the organic material. the oxygen content of the water sample is fixed by adding an excess of manganese sulfate
34
first step of the winkler method
an excess of manganese salt is added of the sample under alkaline conditions
35
second step of the winkler method, following adding an excess of manganese salt
potassium iodide is then added which is oxidised by the manganese (IV) oxide to form iodine
36
what is the ratio between O2 and S2O3 2-
1:4
37
what do you use to test for iodine
starch
38
what is ppm
``` parts per million g/1000000g water g/1000dmcubed mg/dmcubed so ppm is just mg/dmcubed ```
39
why can metals conduct electricity
cations in a sea of delocalised electrons that are free to move around the structure and carry charge
40
why can ionic substnaces only someitmes conduct electricity
when molten or liquid the ions dissociate so the ions are free to move and carry charge about the structure
41
what is the negative electrode
anode | where oxidation happens
42
what is the postive electrode
cathode | where reduction happens
43
describe electroysis
ionic solid heated in water. two metal rods (electrodes) inserted the cations attract to the anode and the anions attract to the cathode
44
what is BOD
biological oxygen demand
45
what does a BOD mean
measure of dissolved O2 in ppm required to decompose the organic matter in water over a set period of time
46
polluted water with a high bOD means
it cannot sustain aquatic life
47
what does a high bod lead to
eutrophication
48
how do you calcuate BOD
sample of water saturated with O2 so iniatl conc of dissolved O2 is known incubated in the dark at a fixed temp for five days while microorganisms in the water oxidise the organic material O2 content is fixed with excess of MgS - excess maganese salt added - potassium iodide which is oxideised by the manganese oxide to form iodine - iodine released is titrated with the standard sodium thiosulfate
49
mole ratio of winkler method
1 mol O2 --> 2 mol I2 --> 4 mol S2O3 2-
50
outline reasosn taht BOD may be different along downstream
oxygen demanding wastes broken down downstream decreasing BOD as oxygen demanding wastes are higha t the form BOD is high oxygen levels dcrease as oxygen is used up in the decomposition of plants
51
what happens to O2 in step 1 of the winkler mthod
gets reduced as it gains electrons