8.6 Calculations Involving Acids And Bases Flashcards

1
Q

What information do the acid and base dissociation constants give?

A

The strength of acids and bases.

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2
Q

Using the equation
HA (aq) H+ (aq) + A- (aq)
what is the equation for Ka?

A

Ka = [A-(aq)] [H+(aq)] / [HA(aq)]

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3
Q

How are Ka and pKa related?

A
pKa = -logKa
Ka = 10^(-pKa)
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4
Q

What does a larger value for Ka indicate?

A

A stronger acid.

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5
Q

What does a smaller value for pKa indicate?

A

A stronger acid.

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6
Q

Using the equation
B (aq) + H2O (l) BH+ (aq) + OH- (aq)
what is the equation for Kb?

A

Kb = [BH+(aq)] [OH-(aq)] / [B(aq)]

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7
Q

How are Kb and pKb related?

A
pKb = -logKb
Kb = 10^(-pKb)
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8
Q

What does a larger value for Kb indicate?

A

A stronger base.

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9
Q

What does a smaller value for pKb indicate?

A

A stronger base.

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10
Q

What are the relationship between Ka, Kb and pKa and pKb?

A

Ka x Kb = Kw
pKa + pKb = pKw
at 25 degrees Celsius pKa + pKb = 14

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11
Q

How can pOH be used to simplify the calculations of the pH of a weak base?

A

pOH is basically the same as pH except it refers to the concentration of OH- ions rather than H+ ions.

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12
Q

What are the equations of pOH?

A
pOH = -log[OH-(aq)]
[OH-(aq)] = 10^(-pOH)
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13
Q

How can the ionic product constant expression be converted?

A

Kw = [H+(aq)][OH-(aq)] can be converted to pKw = pH + pOH or at 25 degrees Celsius pH + pOH = 14

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14
Q

How can you calculate the pH of a 0.1000 moldm-3 solution of ammonia with pKb of 4.75?

A

Use the expression for Kb to calculate [OH-(aq)]
Calculate pOH
Use pOH + pH = 14 to work out pH.

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15
Q

How does Kw vary with temperature?

A

The ionisation of water is endothermic and therefore the degree of ionisation increases as temperature increase. This means that the pH of water decreases s temperature increases (higher contraction of H+ (q) at higher temperature).

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