6.1.1 Aromatic Compounds Flashcards
Evidence for Kekulé vs Delocalised Model of Benzene
- Benzene is resistant to electrophilic attack (only reacts with Br2 at a high temp / halogen carrier)
- Bond length in between short C=C and long C–C
- Enthalpy change of Hydrogenation less exothermic than expected (compared to cyclohexene)
Delocalised Model of Benzene
- planar cyclic hydrocarbon with 6 carbons and 6 hydrogens in a ring
- sideways overlap of adjacent p-orbitals to form π-bonds
- π-bonds are delocalised into the ring
Benzene → Nitrobenzene
Reaction: Nitration
Mechanism: Electrophilic substitution
Reagents: HNO3, acid catalyst e.g. H2SO4, heat (50°C)
C6H6 + HNO3 → C6H5NO2 + H2O
Benzene → Bromobenzene
Reaction: Halogenation Mechanism: Electrophilic substitution Step 1: Br2 + FeBr3 → FeBr4- + Br+ Step 2: C6H6 → C6H6Br+ → C6H5Br + H+ Step 3: FeBr4- + H+ → FeBr3 + HBr
Benzene → Alkylbenzene
Reaction: Alkylation
Mechanism: Electrophilic substitution (Friedel-Crafts reaction)
Reagents: haloalkane, halogen carrier e.g. AlCl3
C6H6 + RCl → C6H5R + HCl
Benzene → Ketone
Reaction: Acylation
Mechanism: electrophilic substitution
Reagents: Acyl chloride, halogen carrier e.g. AlCl3
C6H6 + RCOCl → C6H5C(O)R + HCl
Reactivity of alkenes vs arenes vs phenol
- Benzene π-bond electrons delocalised
- Phenol a lone pair of electrons on the oxygen of the OH group is partially delocalised into the ring
- Cyclohexene electrons localised between 2 carbons in the π-bond
- benzene has a lower electron density/phenol has a higher electron density/cyclohexene has a higher electron density
- benzene cannot polarise Br2/phenol can polarise the Br2/cyclohexene can polarise the Br–Br bond
Acidity of phenol
Alcohol < Phenol < Carboxylic acid
- Ethanol does not react with NaOH (strong) / Na2CO3 (weak)
- Phenol reacts with NaOh (strong) but not Na2CO3 (weak)
- Carboxylic acids react with NaOH (strong) / Na2CO3 (weak) → CO2 gas produced
Phenol → 2,4,6-tribromophenol
Reaction: Bromination
Reagents: Br2 water decolourised → white ppt
C6H5OH + 3Br2 → C6H2Br3OH + 3HBr
Phenol → 2/4-Nitrophenol
Reaction: Nitration
Reagents: dilute HNO3
C6H5OH + HNO3 → C6H4NO2OH + H2O
2 and 4- directing groups (activating)
–NH2 or –NHR
–OH or –OR
–C6H5 or –R
–F, –Cl, –Br, –I
3- directing groups (deactivating)
–COOR or –COOH –CHO –RC(O)R –CN –NO2 or –NR3+ –SO3H