5.2 - The Behaviour Of Waves

Question 1

What’s the wave phase

Answer 1

All points on a wave will be at some position through their cycle of oscillation, some positions have their own names eg peak, crest, rarefaction or compression

We describe any position through a cycle by a number, referred to as the phase

Question 2

What is a complete cycle or a wave equal to

Answer 2

It’s considered equivalent to rotation through a complete circle - so the phase position will be an angle measurement, where a complete cycle is equal to 360 degrees

Question 3

What’s the alternative angle units to degrees

Answer 3

Radians

Question 4

What’s one cycle equal to in raisins

Answer 4

One cycle is 2 pi radians

Radians can be shortened to rad

Question 5

What are wavefronts

Answer 5

Diagrams of waves are often drawn as lines, where all the points in a line represent points on the wave that are exactly the same phase position, perhaps a wave crest for example

These lines on a diagram are call wavefronts

Question 6

What is a ray on a wave diagram

Answer 6

The line showing the direction of travel is called a ray, rays must be perpendicular to wavefronts

Question 7

What happens with wave superposition

Answer 7

When waves meet, each wave will be trying to cause a displacement at that point of intersection, according to its phase at that location. The net effect is that the overall displacement will be the vector sum of the displacements caused by the individual waves

After the encounter, each wave will continue past eachother, as the energy progresses in the same direction it was originally travelling - this can be simply illustrated if we consider just wave pulses passing each other - waves go back to original displacement after the intersection

Question 8

What happens with the superposition of continuous waves

Answer 8

If rather than a single point along the path of the waves, we consider waves superposing over an extended space, the outcome is a continuous wave that is the sum of the displacements over time in each location

Question 9

What’s constructive interference

Answer 9

If the two continuous waves are in phase, their effect will be to produce a larger amplitude resultant wave

Question 10

What’s destructive interference

Answer 10

If identical waves meet and are exaclty out of phase, phase difference is 180 degrees, then the resultant is a zero amplitude wave

Question 11

Define wavefronts

Answer 11

Wavefronts are lines connecting points on the wave that are at exaclty the same phase position

Question 12

Define constructive interference

Answer 12

It’s the superposition effect of two waves that are in phase, producing a larger amplitude resultant wave

Question 13

Define destructive interference

Answer 13

It’s the superposition effect of two waves that are out of phase, producing a smaller amplitude resultant wave

Question 14

How can a stationary or standing wave be set up

Answer 14

Continuous waves travelling in the opposite directions will superpose continuously, this can set up a standing wave.

The waves need to be if the same speed and frequency with similar amplitudes and have a constant phase relationship

Question 15

What’s coherent

Answer 15

Waves with the same frequency and a constant phase relationship are said to be coherent

Thus waves must be coherent in order for a standing wave to occur

Question 16

What do stationary waves do

Answer 16

They are so called stationary waves as the profile of the wave does not move along, it only oscillates. This also means that wave energy doesn’t pass along a standing wave - they kind of don’t meet definition of waves, which do transfer energy and are more precisely called progressive waves

Question 17

What are progressive waves

Answer 17

Waves that transfer energy

Question 18

What are nodes and antibodies

Answer 18

On a standing wave,

Nodes are the points where the resultant displacement is always zero, thus points never move

Antibodies are points of maximum amplitudes

All points between one node and the next are In the same phase at all times although their amplitude of vibration varies up to the antipode and back to zero at the next node

This can be demonstrated in school, with a vibration generator and a rubber cord

Question 19

At the end points on a stationary wave what happen

Answer 19

If the string / wave thing is fixed at each end, these points must always be nodes!!!

A standing wave can only occur if its wavelength exaclty allows one node at each end

Question 20

Tell me about

Answer 20

U

Question 21

What are modes of a stationary wave

Answer 21

They are harmonics - pls search up a pic so you understand

There are a quanised (limited/finite) number of half wavelengths that a standing wave can have as the fixed ends of the waves must be nodes

Question 22

List the different modes

Answer 22

Fundamental (1st harmonic) wavelength is equal to 2L

Then it’s the 1st overtune (2nd harmonic) and wavelength is equal to L

Then the 2nd overtune (3rd harmonic) and wavelength is equal to 2L/3

And 3rd overtune (fourth harmonic) where wavelength is L/2

Question 23

How do string waves travel

Answer 23

Waves on a stretched string travel at a speed that is affected by the tension in the spring(newtons) and the mass per unit length of the string, weird u symbol in kg/m

Question 24

What’s the equation for the speed of a wave In a string

Answer 24

V = square root T/ weird u

T = tension 
u = mass per unit length 
V = speed

Question 25

How can the wave speed equation for a string be combined with the wave equation

Answer 25

V = f x lamder F x lamder = square root T/weird u F = 1/lamder x square root T/u In the fundamental mode of vibration(first harmonic), fundamental frequency, f subscript 0, depends on the length of the string, tension and mass per unit length from F subscript 0 = 1/2L x square root T/u

Question 26

How can we investigate the factors affecting fundamental frequency of a string

Answer 26

We can verify the equation F subscript 0 = 1/2L x square root T/u Experimentally. Need to undertake 3 separate investigations to verify each part of the relationship, whilst maintaining other variables as control variables So need to verify F0is proportional to 1/L F0 is proportional to square root T F0 is proportional to square root 1/u We can use a microphone connected to an oscilloscope to monitor the sounds produced by a sonometer string and to measure its frequency of vibration . This can be easier if a datalogging computer is used instead of an oscilloscope, so the screen can be frozen fir close scrutiny 1) the string supports (bridges) on a sonometer are moveable, so that we can find the frequency with varying lengths, L whilst the same string (constant u) and hanging masses (T) keep the other variables controlled. We can plot a graph to verify f0 on the y axis is proportional tO 1/L on x axis 2) we can find the fundamental frequency using a fixed length of the same string throughout (constant L and constant u) for varying masses hung over the pulley - varying T. We can plot a graph to verify f0 on the y axis is proportional to square root T on the x axis 3) the final experiment requires a set of different strings (varying diameter metal wires could be used). Maintaining the same length and hanging mass keeps other variables controlled. Measure the mass of each wire using a digital balance and its full length, In order to calculate mass per unit length, u, for each wire or string used - we can plot a graph to verify f0 on the y axis is proportional to square root 1/ u on the x axis

Question 27

Define a stationary or standing wave

Answer 27

Consists of oscillation in a fixed space, with regions of significant oscillation and regions with zero oscillation, which remain in the same locations at all times

Question 28

When are waves said to be coherent

Answer 28

If they have the same frequency and have a constant phase relationship. Coherent waves are needed to form a stable standing Wave

Question 29

What’s a progressive wave

Answer 29

Is a means of transferring energy via oscillations

Question 30

What are nodes

Answer 30

Nodes are regions on a stationary wave where the amplitude of oscillation is zero

Question 31

What are antinodes

Answer 31

Are regions on a stationary wave where the amplitude of oscillation is at its maximum

Question 32

What’s a sonometer

Answer 32

A sonometer is an apparatus for experimenting with the frequency relationships of a string under tension, usually consisting of a horizontal wooden sounding box and a metal wire stretched along the top of the box

Question 33

How does diffraction change with objects

Answer 33

When a wave passes the edge of an obstacle, the wave energy spreads into the space behind the obstacle. If the obstacle is relatively small, this can mean wave energy will pass around both sides of it and continue travelling past the obstacle with no shadow, as if the obstacle was not there If the obstacle is larger, then there may be a shadow region behind it, but there will still be some diffraction around the edge If there are two close obstacles forming a gap, then there will be diffraction from each edge of the gap, causing the waves to spread out through the gap

Question 34

What is diffraction

Answer 34

Diffraction is a spreading of wave energy through a gap or around an obstacle

Question 35

What are 2 factors affecting diffraction for obstacles

Answer 35

The amount of diffraction around an obstacle depends on the size comparison between the obstacle and the wavelength

Question 36

How does the gap size affect diffraction

Answer 36

As the resulting diffraction through a gap is caused by the diffraction at each end of the gap, there is an optimum size for maximum diffraction, or spreading out through the gap. Diffraction happens most when the gap size is the same as the wavelength. If the gap size is too small, very little wave energy can pass through. If the gap is very large, there is little effect as the majority of the wave passes through undisturbed. When the wavelength matches the gap size, the wave energy is spread very effectively through the gap to fill the space behind. This is why we can hear around corners but not see around them - audible sound wavelength much larger so math more the gap of a doorway.

Question 37

What are diffraction patterns observed when light passes through a narrow slit

Answer 37

The pattern shows a central maximum and then areas of darkness and further maxima of decreasing intensity, Eg using a laser with a diffraction grating with slits shows an example of an interference pattern Considering the waves being diffracted from each end of the slit, gives us two waves that will meet at the screen, they superpose to give a larger amplitude resultant wave and so would appear as a light spot on the screen At a differnt place on the screen, these two waves will be completely out of phase and the sum of their displacements will always be zero, so it appears as a dark spot - the diffraction pattern is an example of a standing wave on the screen, where there are dark spots of nodes and light spots of antinodes

Question 38

What happens when we alter the slit (single slit) to diffraction

Answer 38

If we change the width of diffraction slit, we will alter the diffraction pattern that we observe A narrower slit widens the central maximum, as well as the further maxima and minima

Question 39

What is a diffraction grating

Answer 39

A diffraction grating is a device that will cause multiple diffraction patterns, which overlap creating an interference pattern with a mathematically well defined spacing between bright and dark spots, it is a collection of a very large number is slits through which the waves can pass. These slits are parallel and have a fixed distance between each slit - can be used to examine line spectra

Question 40

What equation does the pattern produced by each colour passing through a diffraction grating follow

Answer 40

n lamder = d x sin theta Where theta is angle between the original direction of the waves and the direction of the bright spot Lamder is the wavelength of the light used d is the spacing between the slits on the grating n is the order. The order is the bright spot number from the central maximum which n = 0 The grating spacing is often quoted as a number of lines per metre, so to find d You do d = 1/ number per meter

Question 41

How can we investigate diffraction with a laser practical

Answer 41

You can use a laser pointer or laboratory experimental laser to demonstrate diffraction. A diffraction grating investigation allows careful study of the light making up the spectrum from any light source Astronomers use this to study spectra from stars Diffraction gratings are manufactured to have a fixed spacing, d, between lines on the grating, and this will be printed on the grating. By measuring the angle between each maximum brightness spot created by a diffraction grating, you can calculate the wavelength of the light used from the diffraction grating equation

Question 42

What is an interference pattern also known as

Answer 42

When a wave meets its own reflection, it would set up a standing wave pattern, also known as an interference pattern. Reflection is a convenient way to generate coherent waves that will produce a standing wave. However any combination of waves that have the same frequency and a constant phase relationship will produce this result

Question 43

Tell me about two slit interference / where Thomas young got his wave theory of light

Answer 43

Using a forth and two slits to make 2 coherent waves that produce a standing wave pattern, that showed a pattern of dark and light fringes that resemble the nodes and antinodes in a standing wave Young explained his experiment that light behaves as a wave, since in classical physics interference can only occur with waves - theory was controversial at the time as it was contradicting Newton’s theory that light was a steady stream of particles

Question 44

How can we investigate two- source interference

Answer 44

A ripple tank where plane waves are diffracted through two gaps will cause an interference pattern between the two water waves Another common experimental demonstration of two slit interference is with a last light Two source interference and two slit interference are the same thing, waves are brought together to produce an interference pattern. Two slit interference is a form of two source interference, where the slit diffract existing waves in order to act as new sources of waves

Question 45

How can we explain two slit interference

Answer 45

Each point in a two source interference pattern will have a superposition result that depends on the phase difference between the waves coming from each source to that point. Phase difference, will in turn, depend on the relative distances from the slit to where they meet If waves meet on the screen, the waves will constructively interfere and produce a maximum resultant as in an antinodes, if we passed a laser through the 2 slits, there would be a bright spot there

Question 46

How can we compare and thus convert to phase difference between waves

Answer 46

Points where the path difference is equal to n lamder exactly will have a phase difference of 2n pi exaclty and will be In phase, producing constructive interference Points where the path difference is equal to (2n+1)xlamder all divided by 2 will have a phase difference of (2n+1) lamder and will be in antiphase, producing destructive interference.

Question 47

Define interference

Answer 47

It’s the superposition outcome of a combination of waves. An interference pattern will only be observed under certain conditions, such as waves being coherent

Question 48

What are coherent waves

Answer 48

Waves must have The same frequency Constant phase relationship