5.1.3: Acids, Bases and Buffers Flashcards

1
Q

Bronsted Lowry acid

A

a species that is a proton donor

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2
Q

Bronsted Lowry base

A

a species that is a proton acceptor

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3
Q

Why use the pH scale rather than simply [H⁺]

A
  • [H⁺] deals with negative indices over a very wide range

* pH scale makes numbers used to measure acid concentration more manageable

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4
Q

Strong alkali

A

A fully ionic soluble base

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5
Q

Weak Bronsted Lowry acid

A

a proton donor that only partially dissociates

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6
Q

How to calculate pH strong acid?

A

1) [HA] = [H⁺] because strong acid fully dissociates

2) pH = -log₁₀[H⁺]

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7
Q

How to calculate pH weak acid?

A

NEED Ka

1) Ka = [H⁺] [A⁻] / [HA]
2) Ka = [H⁺]² /[HA]
3) Sub in Ka and [HA]
4) pH = -log₁₀[H⁺]

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8
Q

Assumptions when calculating pH weak acid?

A
  • [H⁺] = [A⁻] i.e. water dissociation does not increase the [H⁺]
  • [HA] is unaffected by dissociation, because so little dissociation occurs i.e. you keep all the [HA] you started with
  • The Ka value is small, approx. 1x10⁻⁵
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9
Q

Calculating pH of strong base

A

1) Kw = [H⁺] [⁻OH] = 1 x 10⁻¹⁴
2) [H⁺] = 1 x 10⁻¹⁴ / [⁻OH]
3) pH = -log₁₀[H⁺]

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10
Q

pKa =

A

–log₁₀Ka

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11
Q

Kw is known as

A

the ionic product of water

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12
Q

Calculating pH of diluted solution

A

1) Find [H⁺] in original solution (acid)
2) [H⁺] x (new volume / total volume )
3) pH = -log₁₀[H⁺]

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13
Q

Buffer

A

a solution of a weak acid and its conjugate base. Resists change in pH on addition of small quantities of acid/alkali

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14
Q

What happens when you add H⁺ to a buffer?

A
  • There is a large reservoir of A⁻

* So H⁺ reacts and pH doesn’t change much

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15
Q

What happens when you add ⁻OH to a buffer?

A
  • ⁻OH reacts with H⁺ to give H₂O
  • There is a large reservoir of HA, so equilibrium will shift to replace H⁺
  • The alkali can also react with HA
  • So the HA decreases, leading to equilibrium shift to replace the HA
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16
Q

Equivalence point is when

A

[H⁺] = [⁻OH]

17
Q

Where do you want the indicator to change colour?

A

In the vertical region

18
Q

What is the endpoint?

A

When pH 7 is crossed

19
Q

Type 1 buffer

A

Adding solid salt to acid solution
• Know the conc. of the acid
• Adding the solid doesn’t change this concentration
• Know the moles of the salt –> therefore can work out conc.

20
Q

Type 2 buffer

A

Adding solution of salt to a solution of acid
• Concentrations of both solutions change
• Need to use combined volume to work out new conc.s of both

21
Q

Type 3 buffer

A

Adding strong base to an excess of weak acid solution
• Some of the acid is neutralised by the base, forms salt
• Acid is in excess so some remains
• need to work out how much acid neutralised, thus how much used