4th Flashcards

1
Q

constitutional isomer🌷

A

same empirical formula
atoms are connected differently

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2
Q

configurational isomerism🌷

A

cis/trans isomerism
not chiral
same empirical
same connectivity
not identical in 3d shape
can be called diastereomers

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3
Q

diastereomers

A

different chemical + physical properties

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4
Q

what leads to isomerism

A

restriction of rotation around the C=C bond

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5
Q

cis

A

same side
bucket looking
U

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6
Q

trans

A

different sides
stretched Z shape

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7
Q

E isomer

A

trans isomer

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8
Q

Z

A

cis isomer

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9
Q

priority of group is based on

A

atomic weight
heavier group gets priority

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10
Q

heaviest group on the same side

A

cis
z

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11
Q

heaviest group on opposite sides

A

trans
E

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12
Q

if groups directly bonded to the C are the same

A

keep moving down until they’re different

see which one has a higher atomic weight

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13
Q

double bonds are counted as

A

2 single bonds

C=O has priority over C-O

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14
Q

enantiomers🌷

A

different molecules as they cannot be overlayed

non superimposable mirror images of eachother

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15
Q

when do enantiomers occur most🌷

A

tetrahedral shape
(sp3 hybridised)
chiral Carbon

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16
Q

how to check similar enantiomers molecules are acc different molecules

A

rotate one around and see if it ‘forms’ the other one

17
Q

chiral centre can also be called a

A

stereogenic centre

18
Q

rules that help us name enantiomers

A

cahn ingold prelog rules
CIP

19
Q

cahn inlog prelog rule steps

A
  • assign a priority number 1=heaviest 4=lightest, normally H
  • make sure number 4 is facing away from u
  • draw an arrow from 1 to 2 to 3 etc
  • clockwise = R, anti-clockwise = S
20
Q

what if number 4 isn’t pointing away??

A

we must rotate the molecule so that 4 is dashed + pointing away from us.

keep the bonds in the same place and just move the atoms around to the next bond until 4 is on the dashed one.

21
Q

if 4 isn’t pointing away or towards u, what do u do

A

invert the molecule so it’s pointing away

22
Q

trick to save time when 4 is coming towards us

A

do the opposite answer // inverted answer
R->S
S->R