3.7.1 Inheritance (Genetics , population , evolution and ecosystems 3.7) Flashcards

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1
Q

What is meant by the term genotype

A

Genetic constitution of an organism

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2
Q

What is meant by the term phenotype

A

The expression of this genetic constitution and its interaction with the environment

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3
Q

What are alleles and how do they arise

A

Variations of a particular gene - arise by mutation

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4
Q

How many alleles of a gene can be found in a diploid organism

A
  • 2 as dipole is organisms have 2 sets of chromosomes
    • but there may be many alleles of a single gene in a population
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5
Q

Describe the e different types of alleles

A

Dominant alleles : Always expressed
Recessive alleles : Only expressed when 2 copies present ( homozygous recessive )
Codominant alleles : Both alleles expressed

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6
Q

What is meant by the term homozygous and heterozygous

A

Homozygous:
Alleles at a specific locus are the same
Heterozygous:
Alleles at a specific locus are different

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7
Q

What do monohybrid and dihybrid crosses show

A
  • monohybrid cross = inheritance of one phenotypic characteristics coded for by a single gene
  • Dihybrid cross = inheritance of two phenotypic characteristics coded for by two different genes
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8
Q

Explain the evidence from a pedigree diagram which would show that the allele for [ named phenotype ] is dominant

A

• [Named phenotype] parents [n&n] have child [n] without [named phenotype]
• So both parents [n&n] must be heterozygous/ carriers of recessive allele
- if it were recessive , all offspring would have [ named phenotype]

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9
Q

Explain the evidence from a pedigree diagram which would show that the allele for [named phenotype ] is recessive

A

• Parents [n&n] without [named phenotype] have child [n] with [named phenotype]
• so both parents [n&n] must be heterozygous / carriers of recessive allele

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10
Q

What is a sex linked gene

A

A gene with a locus on a sex chromosome

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11
Q

Explain why males are more likely to express a recessive X- linked allele

A
  • Females (XX) have 2 alleles => only express recessive allele if homozygous recessive / can be carriers
  • Males (XY) have 1 allele -> recessive allele always expressed
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12
Q

Explain the evidence from a pedigree diagram which would show that the allele for [named phenotype ] on the X chromosome is recessive

A

• mother [n] without [named phenotype] has a child [n] with [named phenotype]
• so mother [n] must be heterozygous / carrier of recessive allele

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13
Q

Explain the evidence from a pedigree diagram which would suggest that [named recessive phenotype] is caused by a gene on the X chromosome

A

only males tend to have [named recessive phenotype]

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14
Q

Explain the evidence from a pedigree diagram which would show that the gene for [named phenotype] is not on the X chromosome

A

• [named phenotype] father [n] has daughter [n] without [named phenotype]
• father [n] would pass on allele for [named phenotype] on X chromosome so daughter [n] would have [named phenotype]

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15
Q

explain how autosomal linkage affects inheritance of alleles

A
  • two genes located on same autosome ( non - sex chromosome )
  • so allele on same chromosome inherited together
    • stay together during independent segregation of homologous chromosomes during meiosis
  • But crossing over between homologous chromosomes can create new combinations of alleles
  • if the genes are closer together on an autosomes , they’re less likely to be split by crossing over
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16
Q

What is epistasis

A

interaction of non linked genes where one masks / suppresses the expression of the other

17
Q

describe when a chi-square test (X^2) can be used

A
  • when determining if observed results are significantly different from expected results
  • data is categorical
18
Q

suggest why in genetic crosses , the observed phenotypic ratios obtained in the offspring are not often the same as the expected ratios

A
  • fertilisation is random
  • autosomal linkage / epistasis / sex linkage
  • small sample size - not representative of the whole population
  • some genotypes may be lethal
19
Q

describe how a chi-square value can be calculated

A

x^2 = sum of (O- E) ^2 / E

O = frequencies observed
E = frequencies expected

20
Q

Describe how a chi-squared value can be analysed

A

1) number of degrees of freedom = number of categories - 1
2) determine critical value at p=0.05% from a. table
3) if x^2 value is [greater / less] than critical value at p< 0.05
• difference [is/is not] significant so [reject / accept ] null hypothesis
• so there is [ less / more] than 5% probability that the difference is due to chance