[3.6.2.1] Nerve Impulses Flashcards

1
Q

Describe the structure of a myelinated motor neurone.

A
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2
Q

Describe resting potential.

A
  • Inside of axon has a negative charge relative to outside (-70mV).
    • i.e. more positive ions outside compared to inside.
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3
Q

Explain how a resting potential is established across the axon membrane in a neurone.

A
  • Na⁺/K⁺ pump actively transports:
    • 3 Na⁺ out of axon AND 2 K⁺ into axon.
  • Creating an electrochemical gradient:
    • Higher K⁺ concentration inside AND higher Na⁺ concentration outside.
  • Differential membrane permeability:
    • More permeable to K⁺ -> move out by facilitated diffusion.
    • Less permeable to Na⁺ (closed channels).
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4
Q

Explain how changes in membrane permeability lead to deplorisaiton and the generation of an action potential.

A
  1. Stimulus.
    • Na⁺ channels open; membrane permeability to Na⁺ increases.
    • Na⁺ diffusion into axon down electrochemical gradient (causing depolarisation).
  2. Depolarisation.
    • If threshold potential is reached, an action potential is generated.
    • As more voltage-gated Na⁺ channels open (positive feedback effect).
    • So more Na⁺ diffuse in rapidly.
  3. Repolarisation.
    • Voltage-gated Na⁺ channels close.
    • Voltage-gated K⁺ channels open; K⁺ diffuse out of axon.
  4. Hyperpolorisation.
    • K⁺ channels slow to close so there’s a slight overshoot = too many K⁺ diffuse out.
  5. Resting potential.
    • Restored by Na⁺/K⁺ pump.
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5
Q

Draw and label a graph showing an action potential.

A
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6
Q

Describe the all-or-nothing principle.

A
  • For an action potential to be produced, depolarisation must exceed threshold potential.
  • Action potentials produced are always same magnitude / size / peak at same potential.
    • Bigger stimuli instead increase frequency of action potentials.
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7
Q

Describe the nature of the refractory period.

A
  • Time taken to restore axon to resting potential when no further action potential can be generated.
  • As Na⁺ channels are closed / inactive / will not open.
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8
Q

Explain the importance of the refractory period.

A
  • Ensures discrete impulse are produced (action potentials don’t overlap).
  • Limits frequency of impulse transmission at a certain intensity (prevents over reaction to stimulus).
    • Higher intensity stimulus causes higher frequency of action potentials.
    • But only up to certain intensity.
  • Also ensures action potentials travel in one direction - can’t be propagated in a refractory region.
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9
Q

Explain how the passage of an action potential along non-myelinated and myelinated axons result in nerve impulses.

A

NON-MYELINATED AXON

  • Action potential passes as a wave of depolarisation.
  • Influx of Na⁺ in one region in increases permeability of adjoining region to Na⁺ by causing voltage-gated Na⁺ channels to open so adjoining region depolarises.

MYELINATED AXON

  • Myelination provides electrical insulation.
  • Depolarisation of axon at nodes of Ranvier only resulting in saltatory conduction (local currents circuits).
  • So there is no need for depolarisation along whole length of axon.
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10
Q

Suggest how damage to the myelin sheath can lead to slow responses and/or jerky movement.

A
  • Less / no saltatory conduction; depolarisation occurs along whole length of axon.
    • So nerve impulses take longer to reach neuromuscular junction; delay in muscle contraction.
  • Ions / depolarisation may pass / leak to other neurones.
    • Causing wrong muscle fibres to contract.
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11
Q

Describe the factors that affect speed of conductance.

A

Myelination

  • Depolarisation at nodes of Ranvier only resulting in -> saltatory conduction.
  • Impulse doesn’t travel / depolarise whole length of axon.

Axon diameter

  • Bigger diameter means less resistance to flow of ions in cytoplasm.

Temperature

  • Increases rate of diffusion of Na⁺ and K⁺ as more kinetic energy.
  • But proteins / enzymes could denature at a certain temperature.
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