3 — atomic structure Flashcards

1
Q

Atom

A

An atom is the smallest particle that can still have the chemical characteristics of an element.

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2
Q

Nucleon number

A

Nucleon number or relative atomic mass (A) = number of protons + number of neutrons in the nucleus (N)

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3
Q

Isotopes

A

Isotopes are atoms of the same element with the same number of protons and electrons but different number of neutrons.

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4
Q

Characteristics of isotopes

A
  1. Similar chemical properties because chemical reactions only involve the outermost electrons and not the protons and neutrons. (Same kind of chemical reactions can occur)
  2. Different physical properties because physical properties are affected by mass. (Eg density, melting or boiling point)
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5
Q

Groups and periods in the periodic table

A
  1. Elements in the same group have the same number of valence electrons. Hence they tend to exhibit similar chemical properties.
  2. Elements in the same period hav the same number of electron shells.
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6
Q

Ions

A

An ion is a charged particle formed from an atom or a group of atoms by the loss or gain of electrons.

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7
Q

Noble gases

A

Elements in group 0 have stable octet electronic configuration since their valence electron shell is fully filled with electrons thus they do not gain, lose or share electrons to form compounds. Hence, they are inert.

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8
Q

Why are atoms reactive?

A

Atoms form ions to achieve stable electronic configuration.

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9
Q

Explain why helium and argon are chemically similar

A

Both helium and argon are inert gases as they do not lose, gain or share electrons since both have stable octet electronic configurations with fully filled valence electron shell.

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10
Q

Suggest the trend in the melting points of elements oxygen, Sulfur and zinc. Explain. [3]

A

Lowest: oxygen < Sulfur < zinc (highest)

Both oxygen and Sulfur have a simple molecular structure in which small amount of energy is needed to overcome weak intermolecular forces of attraction. Hence they have a lower melting point as compared to zinc.
As Sulfur has a larger molecular size than oxygen, more energy is needed to overcome the stronger intermolecular forces of attraction. Thus, Sulfur has a higher melting point than oxygen. Zinc has a giant metallic structure where larger amount of energy is needed to overcome strong electrostatic forces of attraction betw positive ions and a “sea of delocalised mobile electrons”. Thus, zinc has the highest melting point.

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11
Q

Discuss the differences betw the way that bonds are formed in MgO and O2.

A

Mg loses 2 valence e- readily to oxygen to form Mg2+ and O2-. Electrostatic forces of attraction between oppositely charged ions result in the formation of an ionic bond in MgO.
Two oxygen atoms each share 2 of their valence electrons which results in the formation of a covalent bond in oxygen molecule.

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12
Q

Describe the similarities and differences betw the bonding and structures in diamond and graphite [4]

A
  1. Both diamond and graphite are made up of carbon atoms covalently bonded tgt.
  2. Both diamond and graphite have giant covalent structures.

Differences:
1. The carbon atoms in diamond are arranged in a tetrahedral structure held together by strong covalent bonds but the carbon atoms in graphite r arranged in layers of hexagons with weak intermolecular forces of attraction between graphite molecules.
2. In diamond, each carbon atom is bonded to four other carbon atoms but in graphite, each carbon atom is bonded to three other carbon atoms covalently, leaving a free electron in its valence electron shell.

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13
Q

Explain why graphite and carbon dioxide have different properties. [4]

A
  1. Graphite has a high melting and boiling point as there r strong covalent bond betw the carbon atoms in its giant covalent structure. A large amount of heat energy is needed to overcome the strong covalent bonds.
  2. CO2 has a lower melting and boiling point as it has a simple molecular structure made up of small carbon dioxide molecules held tgt by weak intermolecular forces of attraction. A small amt of heat energy is needed to overcome the weak intermolecular forces of attraction between the CO2 atoms.
  3. For graphite, each carbon atom has a mobile outer electron that is not involved in bonding, allowing graphite to conduct electricity.
  4. In CO2, all outer electrons of the carbon atoms r used in bonding w oxygen, thus there r no presence of mobile electrons or ions to conduct electricity.
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14
Q

Suggest why the radius of a lithium atom decreases when it forms a lithium ion.

A

A lithium ion loses its valence electron in order to form a lithium ion. When its valence electron is lost, the number of electron shells in lithium decreases from 2 to 1, thus distance between valence electron shell to positive nucleus decreases, atomic radius decreases.

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15
Q

Compare the bonding and structures of the poly(propene), silicon dioxide and propanol [4]

A

Structure:
All 3 compounds contain strong covalent bonds between atoms.
Propanol has a simple molecular structure while SiO2 and poly(propene) has giant covalent structures.

Weak intermolecular forces of attraction exists between the molecules of propanol and between chains of poly(propene) while only strong covalent bonds exist between atoms in SiO2 to form a tetrahedral structure where each Si atom is covalently bonded to 4 other O atoms.

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16
Q

Explain why the melting points of the 3 compounds differ from each other. [4] (Silicon dioxide, propanol and poly(propene)

A

Propanol and poly(propene) have low melting points because very small amount of energy is required to overcome the weak intermolecular forces of attraction betw propanol molecules and between the chains of poly(propene).

Melting point of poly(propene) is higher than propanol because more energy is required to overcome the stronger intermolecular forces of attraction betw long-chained poly(propene) molecules than that betw simple propanol molecules, due to its larger molecular size.

Silicon dioxide has the highest melting point because very large amount of energy is required to break the strong covalent bonds betw atoms.

17
Q

Explain why neither the ‘dot-and-cross’ diagram nor the ball and stick model is an accurate representation of an ethanol molecule. [3]

A
  1. The ‘dot-and-cross’ diagram does not show the length of bond betw the atoms.
  2. The ‘dot-and-cross’ diagram does not show the 3 dimensional arrangement of the atoms in the ethanol molecule.
  3. The ball and stick model does not show the differences in atomic radii of the atoms.
  4. The ball and stick model does not show the valence electrons which r not involved in bonding in the oxygen atom.
18
Q

Using ideas about structure and bonding to explain the differences in melting point and electrical conductivity of lithium, graphite and oxygen. [5]

A

Melting points:
1. O2 has the lowest melting point as it is a simple molecule with weak intermolecular forces of attraction which require little energy to overcome.
2. Lithium has a metallic structure that has strong electrostatic forces of attraction betw positively charged cations and ‘sea of delocalised mobile electrons’ which require more energy to overcome
3. Graphite has a giant covalent structure with strong covalent bonds betw its atoms. Since a lot of energy is needed to overcome the forces of attraction, it has very high melting point.

Electrical conductivity:
1. There r no mobile electrons in oxygen to conduct electricity. Hence, it does not conduct electricity in any state.
2. There is a ‘sea of delocalised mobile electrons’ where presence of mobile electrons conduct electricity in lithium
3. Each carbon atom in graphite is covalently bonded to 3 carbon atoms, leaving 1 mobile electron per carbon atom to conduct electricity.

19
Q

Conduction of electricity can have a different effect on metals and on solutions of ionic compounds. Describe this difference.

A

When electricity is passed thru, solutions of ionic compounds can be decomposed and broken down but metals remains chemically unchanged.

20
Q

Electrical conductivity of molten ionic compounds

A

Depends on the number of mobile ions and not the number of delocalised mobile electrons.

21
Q

Main reason why densities of chlorine and bromine are so different [ 1]

A

Chlorine is a gas and bromine is a liquid at rtp.

22
Q

Explain why Carbon is added to iron and why the amounts added must be carefully controlled [2]

A

Carbon is added to iron to make steel which is harder and stronger than pure iron which is soft as the different sized carbon atoms disrupt the regular arrangement of pure iron atoms. [1]
However, the amounts added must be carefully controlled as the higher the percentage of carbon in the steel, the less malleable, less ductile, harder and more brittle the steel will be. [1]