2.21 - Group 2 Flashcards

1
Q

Write an equation for the first ionisation energy of magnesium…

A

Mg (g) → Mg⁺(g) + e‾

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2
Q

Explain the shape of this graph:

A
  • first ionisation energy increases across group 3 because of increased nuclear charge, decreased atomic radius and similar electron shielding means more energy is needed to removed the first electron.
  • dips at Al because: outer electron is in the 3p orbital, so further from the nucleus and increased shielding from 3s sub level.
  • dips at S because the orbital the electron is being removed from contains 2 electrons, meaning there is repulsion between them, so less energy is required to remove one.
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3
Q

What happens to the first ionisation energy as you go down group 2? Why?

A
  • decreases
  • number of electrons shells increases down the group
  • causing increased shielding and atomic radius
  • therefore weaker force between outer electron and nucleus
  • therefore less energy is required to remove an electron
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4
Q

How does reactivity with water change as you go down group 2?

A
  • increases (Mg least → Ba most)
  • because outer electrons further from nucleus and more electron shielding, so electrons are lost more easily.
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5
Q

Write an equation for the reaction of Barium and water…

A
  • Ba (s) + 2H₂O (l) → Ba(OH)₂ (aq) + H₂ (g)
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6
Q

Write an equation for the reaction of Magnesium and steam…

A
  • Mg (s) + H₂O (g) → MgO (s) + H₂ (g)
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7
Q

What is the trend in hydroxide solubility down group 2?

A
  • increases down the group
    Mg(OH)₂ is almost insoluble
    Ba(OH)₂ creates a strong alkaline solution
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8
Q

What is the trend in sulphate solubility down group 2?

A
  • decreases down the group
    MgSO₄ is soluble
    BaSO₄ is insoluble
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9
Q

What is the trend in melting point down group 2? Why?

A
  • decreases down group
  • because the delocalised electrons are further from the positive nucleus
  • therefore weaker metallic bonds / forces of attraction so less energy is required to overcome these bonds.
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10
Q

What is the trend in atomic radius down group 2?

A
  • increases as there are more occupied electron shells down the group
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11
Q

Write the equations for the extraction of Titanium using Magnesium…

A
  • TiO₂ + 2Cl₂ + C → TiCl₄ + CO₂
  • TiCl₄ (l) + 2Mg (s) → 2MgCl₂ (s) + Ti (s)
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12
Q

What are flue gases?

A
  • gases produced by power stations which are harmful to the environment
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13
Q

How can CaO or CaCO₃ be used to remove flue gases? Write equations.

A
  • CaCO₃ (s) + SO₂ (g) → CaSO₃ (s) + CO₂ (g)
  • CaO (s) + SO₂ (g) → CaSO₃ (s)
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13
Q

What is Ca(OH)₂ used for? Write an equation related to one of its uses.

A
  • used to neutralise soil
  • Ca(OH)₂ (aq) + 2HCl (aq) → 2H₂O (l) + CaCl₂ (aq)
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14
Q

What is Mg(OH)₂ used for?

A
  • milk of magnesia - antacid to treat indigestion, heartburn, wind etc.
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15
Q

What is a use of BaSO₄? Why is this safe?

A
  • In barium meals to outline gut in X-rays
  • Ba²⁺ is toxic but is fine as Barium sulphate is insoluble so cannot enter the bloodstream.
16
Q

How can BaCl₂ be used to test for sulfate ions?

A
  • add your sample with HCl first to acidify the solution, then add BaCl₂
  • white precipitate will form if sulfate ions are present
  • Ba²⁺ + SO₄²‾ → BaSO₄
17
Q

Describe how a student could distinguish between aqueous solutions of potassium nitrate (KNO₃) and potassium sulfate (K₂SO₄) using one simple test tube reaction.

A
  • Reagent: BaCl₂
  • KNO₃: colourless solution
  • K₂SO₄: white precipitate
18
Q

Describe how a student could distinguish between aqueous solutions of MgCl₂ and AlCl₃, using one simple test tube reaction.

A
  • Reagent: NaOH
  • MgCl₂: white precipitate
  • AlCl₃: white ppt which dissolves in excess
19
Q

Describe how a student could distinguish between aqueous solution of MgCl₂ and AlCl₃ using a simple test-tube reaction (alternative).

A
  • Reagent: Group 1 carbonate e.g Na₂CO₃
  • MgCl₂: white precipitate
  • AlCl₃: white precipitate and effervescence
20
Q
A