21.1 Defining an acid Flashcards

1
Q

What is a bronsted-lowry acid

What is a bronsted-lowry base

A

An acid is a substance that can donate a proton (H+ ion)

A base is a substance that can accept a proton

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2
Q

What do acids and bases react to produce

Eg in equation
HCl(g) + NH3(g) —> NH4Cl(s)

A

They make a salt.
Water is only produced when the acid has a H+ and the alkali has an OH-

So HCl is the acid here and donates a proton to the NH3 acting as a base by accepting this proton

Acids and bases react in pairs: One acid and one base

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3
Q

How do acids and bases react in equation

H2SO4 + HNO3 —> H2NO3+ + HSO4-

A

Sulfuric acid donates a proton to nitric acid so is acting as the acid in this reaction.

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4
Q

Why are OH- ions formed when reacting water with a base

A

Because the water must act as an acid so releases a H+ ion to give to the base.
So this makes OH- ions

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5
Q

How can water act as a base
What is a H3O+ ion

Explain reaction
HCl + H2O —-> H3O+ + Cl-

A

Oxonium ion aka Hydronium ion
It is formed when water acts like a base, so accepts a proton.

Here, HCl is donating a proton to water so water is a base

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6
Q

How can water act as an acid

H2O + NH3 —> OH- + NH4+

A

Here, water is donating a proton to ammonia so acts as an acid

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7
Q

What is a H+ ion

Why does it have unusual properties

A

It is simply a proton
Because hydrogen consists of one proton and one electron so when an electron is lost it only contains a proton.

It is tiny with an intense electric field so compared to other positive ions it has unusual properties

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8
Q

How do H+ ions act in solutions

A

They are never found on their own, it is always bonded to at least one water molecule to form ion H3O+ .

Since H+ ions have no electrons, they can only bind with molecules with a lone pair

However for simplicity we represent protons as H+ rather than H3O+

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9
Q

Write equation for ionisation of water

A

H2O(l) <–> H+(aq) + OH-(aq)

So equilibrium reaction

It also may be written as:
H2O(l) + H2O(l) –> H3O+(aq) + OH-(aq)

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10
Q

What is Kw

A

It is the ionic product of water, and at 298k it is 1 x 10^-14 mol^2dm^-6

Because you can write Kc expression for ionisation where it is [H+][OH-] divided by [H2O].
But the concentration of water is constant so Kw = Kc x [H2O]

So this makes [H2O] –> [OH-][H+]

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11
Q

What are the values for the ionic products of water

A

. Ionic product of water is 1 x 10^14
. Each H2O splits to make one H+ ion and one OH- ion.
So in pure water at 298K

[OH-] = [H+]
So (1 x 10^14) = [H+]^2
so [H+] = 1 x 10^7moldm^-3

And this is also the value for [OH-]

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