20.3 Electrochemical cells Flashcards

1
Q

Give two examples of
non-rechargeable cells

A

. Zinc/copper cells
. Zinc/carbon cells

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2
Q

What is the zinc/copper cell

Why is it not practical for portable devices

A

. used in 1800s to write telegraphs and morse code

. It is not practical for portable devices because of the liquids it contains

It works on the general principal of electrons being transferred from the more reactive metal to a less reactive one
Voltage is worked out from the difference between the electrode potentials in the electrochemical series

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3
Q

What are zinc carbon cells
What material is its positive electrode made of

What are its uses

A

The positive electrode is carbon, which acts like an inert platinum electrode in the hydrogen electrode.
Because it doesn’t react.

These cells are ordinary disposable batteries

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4
Q

What is an electrolyte

In zinc carbon cells, what consistency is the electrolyte and what is it

A

An electrolyte is the substance that dissociates in water to produce +ve and -ve ions.

It is a paste
Ammonium chloride (NH4Cl)

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5
Q

Describe the structure of the zinc carbon cell

A

.Central carbon rod
. A zinc canister is filled with NH4Cl paste and water, and this is the electrolyte
. The central carbon rod is surrounded by a mixture of MnO2 and carbon

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6
Q

What are the half equations for the zinc carbon electrodes

Why

A

At the zinc:
Zn(s) —> Zn2+ + 2e-
Because the

At the

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7
Q

How do you remember which half cell is being oxidised or reduced from the Eº given

A

Mnemonic No Problem

So negative oxidised
Positive reduced

So the more negative half cell is the one oxidised

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8
Q

How do you calculate the emf between two half cells with their Eº given

A

Think of Red – ox
So the reduction electrode subtract the oxidation electrode

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9
Q

How does increasing concentration of Ag+ ions affect the overall emf value of the reaction

In reaction
Sn2+ + 2e- —> Sn E= -0.14V
Ag+ + 2e- —> 2Ag E= +0.8V

A

normal emf would be reduction - oxidation, and we can see that the Ag+ is more positive so is reduction.
So normal emf is 0.94V

Increasing conc of Ag+ ions will shift equilibrium to the right, so less electrons will be formed, so E value of Ag+ is more positive.
This means the overall emf of the cell will increase because there is a more positive number subtracting the same less positive number, so emf is bigger

So reaction is more feasible

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10
Q

In reaction
Sn2+ + 2e- —> Sn E= -0.14V
Ag+ + 2e- —> 2Ag E= +0.8V

How would the emf value change if we increase concentration of Sn2+ ions

A

In the Sn2+ equation, if we increase concentration of it, the equilibrium will shift right so less electrons will be made for it, so this makes the E of the half cell more positive.
(when calculating this we don’t need to write out the equation in its oxidation form)
So normal emf of this cell is 0.94V, and now the new emf will be reduction - oxidation so there is a higher value for oxidation one (Sn2+) so 0.8V - 0.1V (example of higher value of E) will give an overall more negative emf

So reaction is less feasible

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11
Q

How does emf affect feasibility of a reaction

A

If emf has a higher value, the reaction is more feasible

If emf is lower, reaction is less feasible

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12
Q

What is a rechargable battery

A

You can reverse the cell reactions by applying an external voltage greater than the voltage of the cell to drive electrons in the opposite direction

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13
Q

What are lead acid batteries

What are the cells made of

A

Re-chargable batteries used to operate starter motor of cars
Consist of six 2v cells in series to give 12v

Each cell consists of two plates dipped in sulfuric acid
The positive plate is lead coated in lead oxide (PbO2), and the negative plate is just made of lead

The battery is driving electrons from the lead plate to the lead oxide coated one

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14
Q

Give the equations for the reactions occurring at the lead plate

What about at the lead dioxide plate

So overall reaction

A

Pb(s) + SO42- —> PbSO4 + 2e-

PbO2 + 4H+ + SO42- + 2e- –> PbSO4 + 2H2O

PbO2 + 4H+ +2SO42- +Pb –> 2PbSO4 + 2H2O

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15
Q

What is the alkaline hydrogen oxygen fuel cell

A

The cell has two electrodes made of porous platinum based material

They are separated by a semi permeable membrane
The electrolyte is sodium hydroxide solution

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16
Q

What is the reaction when hydrogen enters the NEGATIVE ELECTRODE

what about where oxygen enters at the POSITIVE ELECTRODE

So what is the overall reaction

A

2H2 + 4OH- —> 4H2O + 4e-
This releases electrons which flow through the circuit to the other electrode where oxygen enters..

O2 + 2H2O + 4e- –> 4OH-
This accepts electrons from the other electrode and

O2 + 2H2 —> 2H2O

It is the same reaction as burning hydrogen and oxygen, but it takes place at lower temperatures so no nitrogen oxides are produced which would usually form

17
Q

What is fuel from the hydrogen oxygen fuel cell used for

A

It is used to generate electricity on spacecraft because the only product is pure water which can be drunk
Produces no CO2 also

18
Q
A
19
Q

Problems with the hydrogen oxygen fuel cell

A

Consider the source of the hydrogen!
Eg made from crude oil which is non renewable
Electrolysis of water can also be used to make hydrogen, but the electricity for this would be from burning fossil fuels which emit CO2

Hydrogen is very flammable so an infrastructure will need to be made to store it safely and transport it
Also because it is a gas it takes up lots of space