19 Equilibrium constant Kp Flashcards

1
Q

How is Kp different to Kc

eg write out kp expression for

2A + B <—> 3C +D

A

Although you can use Kc in solutions, many reversible reactions occur in the gas phase

So we have to express their concentrations in a different way, using partial pressure

(PpC)^3(PpD) / (PpA)^2(Pp(B)
So do NOT use square brackets for kp because we are not dealing with concentration.
Use rounded brackets, with P in them to show the pressure

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2
Q

What is partial pressure

What is total pressure

A

. It is the pressure that the gas would exert if it occupied the container on its own
. Each gas contributes to the partial pressure, so it is the sum of all the gases

Eg air has oxygen, nitrogen etc and has an overall pressure of 100Kpa
So partial pressure of oxygen in air is 20kpa bcs it makes up 20%
And nitrogen is 80kPa

Total pressure is the sum of all of these partial pressures combined

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3
Q

How do you find partial pressure

A

p of A = mol fraction of gas A multiplied by total pressure

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4
Q

How do you find mol fraction of a gas

A

Number of moles of A in the mixture divided by total number of moles of gas in mixture

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5
Q

How would you apply equilibrium law to gaseous equilibria

For example in 3H2 + N2 <–> 2NH3

A

. Find partial pressures of each reactant and product and multiply together in the kc equation
Where p is partial pressure

kp =
p^2(NH3) divided by (p^3(H2) x pN2)

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6
Q

In reaction

SO2Cl2 —> SO2 + Cl2
- Total pressure is 714kpa
- At equilibrium, vessel contains 263kpa of Cl2

Calculate the partial pressure of SO2Cl2

A

Total pressure is the sum of all the partial pressures so
714 = 263 + P(SO2) + P(SO2Cl2)

The chlorine and sulfur dioxide are in a 1:1 ratio so the partial pressure of SO2 is also 263

So pressure of SO2Cl2 is
714 - 526
Which is 188

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7
Q

In equation

2D(g) –> E(g) + F(g)
What would the mol fraction of D be

A

We can see that there are 4 mol of gas in total
So 2/4 is 1/2 so that is the mol fraction

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8
Q

How does temperature affect Kp

A

.Kp is only valid for one temperature
. Changing the temperature will change equilibrium pressures as more energy means the particles move around more and collide with walls etc so kp value will change

So if temperature increases, and if forward reaction is exothermic, the equilibrium will shift to the left, so there are more reactants.
So in Kp equation, the value of Kp will decrease

If temperature causes equilibrium to shift to the right, there will be more products made.
So value of Kp will increase

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9
Q

How does pressure affect Kp

A

Kp is not affected by change in pressure because the pressure will impact the conditions for all substances so it will even out

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10
Q

How would a catalyst impact Kp

A

Adding a catalyst would not affect Kp, it just increases rate of reaction by increasing speed of forward and backward reaction, decreasing activation energy for it to occur

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