2 - chapter 12 - further application of calculus Flashcards
convex curve
curves upwards
second derivative >0
concave curve
curves downwards
second derivative <0
if second deriv = 0
point of inflection - curve goes from concave to convex or vice versa
f’(x) is not necessarily = 0 - doesn’t have to be a horizontal point of inflection
if f’(x) = 0 and f’‘(x) = 0
a point can be any one of the 3 stationary points - to see which one look at the grad each side
see table in textbook p251
cartesian eq
just involves x and y
parametric eq
involve a 3rd variable (parameter)
eg x = f(t) and y = g(t)
differentiating parametric eq
dy/dt = dy/dx *dx/dt
dy/dx = (dy/dt) / (dx/dt)
or = dy/dt * dt/dx
tangent paralel to x and y
tangent parallel to x axis
dy/dt = 0
tangent parallel to y axis
dx/dt = 0
integrating parametric eq
∫y dt * dx/dt
= ∫y dx
if between limits eg x = a and x = b have to find the t values when x = a and b to integrate y with those limits and with respect to t
related rates of change
eg dV/ dr = dV /dt * dt/dr
area between 2 curves
y = f(x) and y = g(x)
A = ∫f(x) - g(x) from b to a
where f(x) is above g(x)
area between curve and y axis
y = f(x)
rearrange to be x = g(y)
and integrate g(y) within the limits