1.4 Energetics Flashcards

1
Q

State what is meant by the term mean bond enthalpy

A
  • energy required to break a given covalent bond
  • averaged over a range of compounds
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2
Q
A

bi) 4 -xCH Bonds + C-C bond + C=O bond + 2.5 x O=O bond = +3980
ii) -4 x H-O + -4 x C-O = -4800
iii) = bond broken - bonds made
3980 - 4800 =-820

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3
Q

Define the term standard enthalpy of combustion

A

enthalpy change when 1 mole of a substance is completely burned in oxygen with all products and reactant in their standard state

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4
Q

State why the standard enthalpy of formation of oxygen is zero.

A

by definition enthalpy of formation is from an element

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5
Q

Write an equation for the decomposition of hydrazine (N2H4) into ammonia and nitrogen only.

A

3N2H4 -> 4NH3 + N2

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6
Q

Give one reason why the value calculated from mean bond enthalpies is different from the value given in a data book.

A

Mean bond enthalpies are average values from different compounds

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7
Q

Suggest one reason, other than the use of mean bond enthalpies, why a value for the enthalpy of combustion of a liquid alkane is different from the value obtained using the expression

A
  • alkanes is not gaseous as equation relates to gaseous alkanes
  • it takes energy to convert it to a gas
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8
Q

Suggest one environmental advantage of manufacturing methanol fuel by this reaction.
CO2(g) + 3H2(g) -> CH3OH(g) + H2O(g)

A

The carbon dioxide (produced on burning methanol) is used up in this reaction

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9
Q
A

Bonds broken - bonds formed
Leads to F-F = 158 kJmol^-1
Student is correct because F-F bond energy is much less

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10
Q
A
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11
Q
A

Product - reactant = -104
iii) Sb is not in its standard state, as is it a solid in standard state, not liquid
iii) Reduction / redox

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12
Q

How to remember how you should construct your Hess cycles

A

Green arrow for combustion
Red for formation

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13
Q

Write an equation, including state symbols, for the reaction with an enthalpy change equal to the enthalpy of formation for iron(III) oxide.

A

2Fe(s) + O2(g) ⟶ Fe2O3(s)

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14
Q
A
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15
Q
A

For enthalpy change it is broken bonds - bonds formed
Make carbon monoxide and steam the products
Final answer is B

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16
Q
A

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