14 Covalent Bonding Flashcards

1
Q

What is a sigma bond?

A

-Direct head-on/end to-end overlap of atomic orbitals
-results in electron density concentrated between nuclei of bonding atoms

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2
Q

What is a pi bond?

A
  • sideways overlap of atomic orbital
  • results in electron density above and below the plane of the nuclei of the bonding atoms
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3
Q

Formal Charge

A
  • decide which Lewis structure is preferred from several
  • Lewis structure with the atoms having FC values closest to 0 is preferred
  • Treats covalent bonds as if they were purely covalent with equal e- distribution
  • ignores electronegativity
  • counts how may e- belong to each atom in Lewis structure and compares this with the # of valence e- in non-bonded atom
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4
Q

Octet Rule exceptions

A
  • incomplete octets
  • expanded octets
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5
Q

Delocalization

A
  • electrons that are shared between all atoms in a molecule/ion opposed to being localized between a pair of atoms
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6
Q

Resonance

A
  • 2 or more Lewis structures to represent the same molecule
  • structures that cannot be described by a single structure
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7
Q

Why do expanded octets exist?

A
  • d orbital available in valence shell of these atoms have energy values relatively close to those of p orbitals
  • Example: from 3p to 3d orbitals –> allows additional e- pairs to form
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8
Q

Species with 5 e- domains

A
  • triangular bipyramidal shape (all 5 domains are bonding pairs)
  • angles of 90, 180 and 120
  • shape will change if there are non-bonding e- as they cause greater repulsion
  • 1 non-bonding pair – > seesaw
  • 2 non-bonding pairs –> T-shaped
  • 3 non-bonding pairs –> linear
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9
Q

Species with 6 e- domains

A
  • octahedral
  • angles of 90
  • 1 non-bonding pair –> square pyramidal
  • 2 non-bonding pairs –> square planar
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10
Q

How to interpret Formal Charge

A
  • low formal charges means less charge transfer has taken place in forming a structure from it’s atoms (stable structure)
  • sum of formal charges in molecule for neutral molecules to equal charge of ion
  • more stable Lewis structure has have negative values for more electro negative atoms+
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11
Q

Oxygen dissociation wavelength

A

<242nm

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12
Q

Ozone dissociation wavelength

A

<330nm

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13
Q

Does it take less energy to break ozone or oxygen and why?

A
  • it takes less energy to break ozone because it has a resonance structure which counts its bonds as 1.5 opposed to the double (2) bond of oxygen
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14
Q

Why is ozone important?

A
  • it absorbs radiation in the range of 200-315 which is UV-B and UV-C (veri scawy to living tissue)
  • henceforth, ozone protec human being
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15
Q

Catalytic destruction of Ozone

A
  • when ozone absorbs UV radiation, it become unstable and allows it to react with other compounds such as Nitrogen oxides (NOx) and chlorofluorocarbons (try saying that 5 times fast) (CFCs)
  • both compounds produce highly reactive free radials that catalyze the decomposition of ozone to oxygen
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16
Q

Catalytic destruction of Ozone (Nitrogen Oxides)

A
  • Nitrogen dioxide forms from the oxidation of Nitrogen Oxide (also a free radical)
17
Q

Catalytic destruction of Ozone (chloroflurocarbons)

A
  • higher energy UV radiation breaks CFCs down releasing free chlorine atoms (reactive free radicals)
  • weaker C-Cl bond breaks in preference to the C-F bond, thus, Cl radicals catalyze the decomposition of ozone
18
Q

Sigma Bond

A
  • overlap along bond axis
  • always forms in a single covalent bond
  • electron density is concentrated between the nuclei of bonded atoms
19
Q

Pi bond

A
  • overlap sideways
  • weaker than sigma bonds
  • only form during the overlap of p orbitals –> pi bonds can only form in double or triple bonds
  • electron is concentrated above and below bond axis
20
Q

What forms a hybrid orbital?

A
  • mixing of different types of atomic orbitals on the same atom
21
Q

Formation of Covalent Bonds

A
  • often starts with excitation of atoms
  • excitation is where and e- is promoted within the atom from the 2s orbital to the vacant 2p orbital
22
Q

Hybridization

A
  • mixing atomic orbitals to form new hybrid atomic orbitals
  • there is an unequal atomic orbitals as a result of excitation
  • these orbits are mixed together resulting gin hybrid atomic orbitals
  • this mix of atomic orbits will balance themselves out due to the imbalance (refer to paint analogy)
23
Q

sp3 hybridization

A

Example: Carbon (CH4)
- when carbon forms 4 single bonds, it undergoes sp3 hybridization, producing 4 equal orbitals
- forms a tetrahedron (109.5 degrees)
- each hybrid orbital overlaps with the atomic orbital of another atom forming 4 sigma bonds

24
Q

sp2 hybridization

A

Example: Carbon (C2H4)
- produces 3 equal orbits
- triangular planar (120 degrees)
- forms 3 sigma bonds
-p orbitals form pi bonds

25
Q

sp hybridization

A

Example: Carbon (C2H2)
- 2 equal orbits
- linear (180 degrees)
- 2 sigma bonds
2 pi bonds form representing 4 lobes of e- density around the atoms

26
Q

Lone pairs in Hybridization

A

Example: Amonia
- non-bonding pair allows for sp3 hybrid orbital even though it has only 3 bonding pairs

27
Q

Hybridization to predict molecular shape

A

Tetrahedral = sp3 hybridized
Triangular planar = sp2 hybridized
Linear = sp hybridized